Concept explainers
Interpretation:
The reason for colorless nature of the complex ion
Concept Introduction:
Co-ordination compounds are primarily formed by
Many of the complex compounds are due to the presence of unpaired electrons in d-orbital of metal ion and exchange of energy between them.
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Chapter 22 Solutions
OWLv2 with Student Solutions Manual eBook for Ebbing/Gammon's General Chemistry, 11th Edition, [Instant Access], 4 terms (24 months)
- Platinum(II) forms many complexes, among them those with the following ligands. Give the formula and charge of each complex. (a) two ammonia molecules and one oxalate ion (C2O42-) (b) two ammonia molecules, one thiocyanate ion (SCN-), and one bromide ion (c) one ethylenediamine molecule and two nitrite ionsarrow_forwardGive the number of unpaired electrons in octahedral complexes with strong-field ligands for (a) Rh3+ (b) Mn3+ (c) Ag+ (d) Pt4+ (e) Au3+arrow_forwardAn aqueous solution of [Rh(C2O4)3]3− is yellow. Predict the approximate wavelength and predominant color of light absorbed by the complex.arrow_forward
- Identify, based on the position in the periodic table, the actinide elements among those in the following list: Co, Cm, Cd, Ce, Cf.arrow_forwardFour different octahedral chromium coordination compounds exist that all have the same oxidation state for chromium and have H2O and Cl as the ligands and counterions. When 1 mole of each of the four compounds is dissolved in water, how many moles of silver chloride will precipitate upon addition of excess AgNO3?arrow_forwardWhich is more acidic and why? [Fe(H2O)6]2+ or [Fe(NH3)(H2O)5]2+arrow_forward
- Explain why a solution of [Ni(H2O)6]²+ is green but a solution of [Ni(CN)6]²- is colorlessarrow_forwardWhat should happen when the concentration of chloride is increased in a solution containing hexaaquocobalt(II), [Co(H2O)6] 2+ (aq)?arrow_forwardCobalt (II) chloride can form two complexes when dissolved in water: [Co(H2O)6]2+(aq) which is pink in colour, and [CoCl4]2- which is blue. The equilibrium system isarrow_forward
- Consider the following tetrahedral complex ions: [Zr(H₂O)4]²+, [Zr(CN)4]²¯, and [Zr(OH)4]². Arrange these in terms of increasing wavelength of the color they appear. [Zr(OH)4]²- < [Zr(CN)4]² < [Zr(H₂O)4]²+ O [Zr(CN)4]²- < [Zr(OH)4]²¯ < [Zr(H₂O)4]²+ [Zr(CN)4]² < [Zr(H₂O)4]²+ < [Zr(OH)4]²- O [Zr(H₂O)4]²+ < [Zr(CN)4]²¯ < [Zr(OH)4]²- [Zr(OH)4]² < [Zr(H₂O)4]²+ < [Zr(CN)4]²-arrow_forwardCopper(II) ion exists in water as the [Cu(H2O)6]2+ ion. Ammonia forms stronger bonds to copper than does water and hence was able to replace the water molecules in this complex ion to form the tetrammine complex, [Cu(NH3)4]2+. What properties of a ligand make it a “strong” ligand? Use your textbook or an encyclopedia of chemistry to find an example of a ligand that would be “stronger” than ammonia and this would be able to replace ammonia from [Cu(NH3)4]2+ .arrow_forwardProvide the name and identify the oxidation state, coordination number, and the molecular geometry of [Fe(H20)6]3+.arrow_forward
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