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Concept explainers
(a)
Interpretation:
For the low spin complex
Geometry of complex ion
Concept Introduction:
Co-ordination compounds exhibit structural isomerism and stereoisomerism. Stereoisomerism deals with three dimensional spatial arrangements of atoms or groups of a molecule. There are two types of stereoisomerism – Geometric isomerism and optical isomerism.
In optical isomerism the isomer that rotates the plane of the polarized light in clockwise direction is termed as d-isomer and the isomer rotates the plane of the polarized light in anti-clockwise direction is l-isomer. These isomers are called optical isomers and they are non-superimposable mirror images.
(b)
Interpretation:
For the low spin complex
Oxidation state of
Concept Introduction:
Co-ordination compounds exhibit structural isomerism and stereoisomerism. Stereoisomerism deals with three dimensional spatial arrangements of atoms or groups of a molecule. There are two types of stereoisomerism – Geometric isomerism and optical isomerism.
In optical isomerism the isomer that rotates the plane of the polarized light in clockwise direction is termed as d-isomer and the isomer rotates the plane of the polarized light in anti-clockwise direction is l-isomer. These isomers are called optical isomers and they are non-superimposable mirror images.
(c)
Interpretation:
For the low spin complex
Geometric isomers and optical activity
Concept Introduction:
Co-ordination compounds exhibit structural isomerism and stereoisomerism. Stereoisomerism deals with three dimensional spatial arrangements of atoms or groups of a molecule. There are two types of stereoisomerism – Geometric isomerism and optical isomerism.
In optical isomerism the isomer that rotates the plane of the polarized light in clockwise direction is termed as d-isomer and the isomer rotates the plane of the polarized light in anti-clockwise direction is l-isomer. These isomers are called optical isomers and they are non-superimposable mirror images.
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Chapter 22 Solutions
OWLv2 with Student Solutions Manual eBook for Ebbing/Gammon's General Chemistry, 11th Edition, [Instant Access], 4 terms (24 months)
- A student proposes the following two-step synthesis of an ether from an alcohol A: 1. strong base A 2. R Is the student's proposed synthesis likely to work? If you said the proposed synthesis would work, enter the chemical formula or common abbreviation for an appropriate strong base to use in Step 1: If you said the synthesis would work, draw the structure of an alcohol A, and the structure of the additional reagent R needed in Step 2, in the drawing area below. If there's more than one reasonable choice for a good reaction yield, you can draw any of them. ☐ Click and drag to start drawing a structure. Yes No ロ→ロ 0|0 G Х D : ☐ பarrow_forwardटे Predict the major products of this organic reaction. Be sure to use wedge and dash bonds when necessary, for example to distinguish between different major products. ☐ ☐ : ☐ + NaOH HO 2 Click and drag to start drawing a structure.arrow_forwardShown below are five NMR spectra for five different C6H10O2 compounds. For each spectrum, draw the structure of the compound, and assign the spectrum by labeling H's in your structure (or in a second drawing of the structure) with the chemical shifts of the corresponding signals (which can be estimated to nearest 0.1 ppm). IR information is also provided. As a reminder, a peak near 1700 cm-1 is consistent with the presence of a carbonyl (C=O), and a peak near 3300 cm-1 is consistent with the presence of an O–H. Extra information: For C6H10O2 , there must be either 2 double bonds, or 1 triple bond, or two rings to account for the unsaturation. There is no two rings for this problem. A strong band was observed in the IR at 1717 cm-1arrow_forward
- Predict the major products of the organic reaction below. : ☐ + Х ك OH 1. NaH 2. CH₂Br Click and drag to start drawing a structure.arrow_forwardNG NC 15Show all the steps you would use to synthesize the following products shown below using benzene and any organic reagent 4 carbons or less as your starting material in addition to any inorganic reagents that you have learned. NO 2 NC SO3H NO2 OHarrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward
- Please show full mechanism for this equation, all arrows and resonance. I would like to see the mechanisms for para, ortho, and meta positions! Thank youarrow_forward1 Please provide an efficient synthesis of the product below from the starting material. Use the starting material as the ONLY source of carbon atoms. Show the synthesis of each compound that would be used in the overall synthesis of the product. [This synthesis uses alkyne and alcohol chemistry.]arrow_forward10- 4000 20 20 30- %Reflectance 60 50- 09 60- 40- Date: Thu Feb 06 17:30:02 2025 (GMT-05:0(UnknownP Scans: 8 Resolution: 2.000 70 70 88 80 3500 3000 2500 90 100 00 Wavenumbers (cm-1) 2000 1500 2983.10 2359.13 1602.52 1584.22 1451.19 1391.87 1367.07 1314.37 1174.34 1070.13 1027.33 1714.16 1269.47 1000 1106.08 1001.14 937.02 873.60 850.20 780.22 686.91 674.38 643.09 617.98 02/06/25 16:38:20arrow_forward
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