Bundle: Chemistry for Today: General, Organic, and Biochemistry, Loose-Leaf Version, 9th + LMS Integrated OWLv2, 4 terms (24 months) Printed Access Card
9th Edition
ISBN: 9781337598255
Author: Spencer L. Seager
Publisher: Cengage Learning
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Chapter 22, Problem 22.62E
Interpretation Introduction
Interpretation:
The types of proteins that are found in vegetables are to be stated.
Concept introduction:
Proteins consist of large number of amino acids linked together by peptide linkages. The human body requires
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Part 2 (0.5 point)
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Draw the major organic product with the correct geometry.
10
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Please draw all four bonds at chiral centers.
P
See Periodic Table See Hint
Heating an alcohol in the presence of sulfuric or phosphoric acid will cause a dehydration to occur: the removal of the elements of water from a
molecule, forming an alkene. The reaction usually follows an E1 mechanism. The SN1 pathway is suppressed by using a strong acid whose conjugate
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Draw the organic intermediate from the first step (no byproducts) and draw curved arrow(s) to show how it reacts.
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H
H
H
C
F
F
See Periodic Table
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This molecule undergoes an E1 mechanism when stirred in methanol.
3rd attempt
CH₂OH
CH₂OH
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Draw 3 chemical species including formal charges and lone pairs of electrons. Add the missing curved arrow notation.
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Chapter 22 Solutions
Bundle: Chemistry for Today: General, Organic, and Biochemistry, Loose-Leaf Version, 9th + LMS Integrated OWLv2, 4 terms (24 months) Printed Access Card
Ch. 22 - Prob. 22.1ECh. 22 - Prob. 22.2ECh. 22 - Prob. 22.3ECh. 22 - List two general functions in the body for each of...Ch. 22 - Prob. 22.5ECh. 22 - Prob. 22.6ECh. 22 - Prob. 22.7ECh. 22 - Prob. 22.8ECh. 22 - Prob. 22.9ECh. 22 - Identify each of the following vitamins as...
Ch. 22 - Prob. 22.11ECh. 22 - Prob. 22.12ECh. 22 - Prob. 22.13ECh. 22 - Prob. 22.14ECh. 22 - Prob. 22.15ECh. 22 - Prob. 22.16ECh. 22 - Prob. 22.17ECh. 22 - What are the general functions of trace minerals...Ch. 22 - Prob. 22.19ECh. 22 - Prob. 22.20ECh. 22 - Prob. 22.21ECh. 22 - Prob. 22.22ECh. 22 - Prob. 22.23ECh. 22 - Prob. 22.24ECh. 22 - What is a metabolic pathway?Ch. 22 - Prob. 22.26ECh. 22 - Prob. 22.27ECh. 22 - Prob. 22.28ECh. 22 - Prob. 22.29ECh. 22 - Prob. 22.30ECh. 22 - Prob. 22.31ECh. 22 - Prob. 22.32ECh. 22 - Prob. 22.33ECh. 22 - Prob. 22.34ECh. 22 - Prob. 22.35ECh. 22 - Prob. 22.36ECh. 22 - Using symbolic formulas such as ADP and PPi, write...Ch. 22 - Prob. 22.38ECh. 22 - Prob. 22.39ECh. 22 - Prob. 22.40ECh. 22 - Prob. 22.41ECh. 22 - Prob. 22.42ECh. 22 - Prob. 22.43ECh. 22 - Prob. 22.44ECh. 22 - Prob. 22.45ECh. 22 - Prob. 22.46ECh. 22 - Prob. 22.47ECh. 22 - Prob. 22.48ECh. 22 - Prob. 22.49ECh. 22 - Prob. 22.50ECh. 22 - Prob. 22.51ECh. 22 - Prob. 22.52ECh. 22 - Prob. 22.53ECh. 22 - Prob. 22.54ECh. 22 - Prob. 22.55ECh. 22 - Prob. 22.56ECh. 22 - Prob. 22.57ECh. 22 - Prob. 22.58ECh. 22 - Prob. 22.59ECh. 22 - Prob. 22.60ECh. 22 - Prob. 22.61ECh. 22 - Prob. 22.62ECh. 22 - Prob. 22.63ECh. 22 - Prob. 22.64ECh. 22 - Prob. 22.65ECh. 22 - Prob. 22.66ECh. 22 - Prob. 22.67ECh. 22 - Prob. 22.68ECh. 22 - Which of the following are not a requirement for...Ch. 22 - Prob. 22.70ECh. 22 - Prob. 22.71ECh. 22 - Outline the three stages in the extraction of...Ch. 22 - Prob. 22.73ECh. 22 - Prob. 22.74ECh. 22 - Prob. 22.75ECh. 22 - Prob. 22.76ECh. 22 - Prob. 22.77E
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- Complete the mechanism for the E1 reaction below by following the directions written above each of the five boxes. Be sure to include lone pair electrons and nonzero formal charges. 1st attempt Y 0 + Provide the missing curved arrow notation. 01: See Periodic Table See Hint H C Br Iarrow_forwardPlease help answer number 2. Thanks in advance.arrow_forwardHow do I explain this? Thank you!arrow_forward
- When an unknown amine reacts with an unknown acid chloride, an amide with a molecular mass of 163 g/mol (M* = 163 m/z) is formed. In the infrared spectrum, important absorptions appear at 1661, 750 and 690 cm. The 13C NMR and DEPT spectra are provided. Draw the structure of the product as the resonance contributor lacking any formal charges. 13C NMR DEPT 90 200 160 120 80 40 0 200 160 120 80 40 0 DEPT 135 T 200 160 120 80 40 0 Draw the unknown amide. Select Dow Templates More Fragearrow_forwardIdentify the unknown compound from its IR and proton NMR spectra. C4H6O: 'H NMR: 82.43 (1H, t, J = 2 Hz); 8 3.41 (3H, s); 8 4.10 (2H, d, J = 2 Hz) IR: 2125, 3300 cm¹ The C4H6O compound liberates a gas when treated with C2H5 MgBr. Draw the unknown compound. Select Draw с H Templates Morearrow_forwardPlease help with number 6 I got a negative number could that be right?arrow_forward
- 1,4-Dimethyl-1,3-cyclohexadiene can undergo 1,2- or 1,4-addition with hydrogen halides. (a) 1,2-Addition i. Draw the carbocation intermediate(s) formed during the 1,2-addition of hydrobromic acid to 1,4-dimethyl-1,3-cyclohexadiene. ii. What is the major 1,2-addition product formed during the reaction in (i)? (b) 1,4-Addition i. Draw the carbocation intermediate(s) formed during the 1,4-addition of hydrobromic acid to 1,4-dimethyl-1,3-cyclohexadiene. ii. What is the major 1,4-addition product formed from the reaction in (i)? (c) What is the kinetic product from the reaction of one mole of hydrobromic acid with 1,4-dimethyl-1,3-cyclohexadiene? Explain your reasoning. (d) What is the thermodynamic product from the reaction of one mole of hydrobro-mic acid with 1,4-dimethyl-1,3-cyclohexadiene? Explain your reasoning. (e) What major product will result when 1,4-dimethyl-1,3-cyclohexadiene is treated with one mole of hydrobromic acid at - 78 deg * C ? Explain your reasoning.arrow_forwardGive the product of the bimolecular elimination from each of the isomeric halogenated compounds. Reaction A Reaction B. КОВ CH₂ HotBu +B+ ко HOIBU +Br+ Templates More QQQ Select Cv Templates More Cras QQQ One of these compounds undergoes elimination 50x faster than the other. Which one and why? Reaction A because the conformation needed for elimination places the phenyl groups and to each other Reaction A because the conformation needed for elimination places the phenyl groups gauche to each other. ◇ Reaction B because the conformation needed for elimination places the phenyl groups gach to each other. Reaction B because the conformation needed for elimination places the phenyl groups anti to each other.arrow_forwardFive isomeric alkenes. A through each undergo catalytic hydrogenation to give 2-methylpentane The IR spectra of these five alkenes have the key absorptions (in cm Compound Compound A –912. (§), 994 (5), 1643 (%), 3077 (1) Compound B 833 (3), 1667 (W), 3050 (weak shoulder on C-Habsorption) Compound C Compound D) –714 (5), 1665 (w), 3010 (m) 885 (3), 1650 (m), 3086 (m) 967 (5), no aharption 1600 to 1700, 3040 (m) Compound K Match each compound to the data presented. Compound A Compound B Compound C Compound D Compoundarrow_forward
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