(a) Interpretation: The oxidation state of oxygen in each oxide and the oxidation state of the other element should be determined. Concept introduction: Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding. When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides. All the oxygen in oxides are in − 2 oxidation state.

Question

Want to see the full answer?

Answer 1

Question

Chapter 22, Problem 22.25CP

Interpretation Introduction

(a)

Interpretation:

The oxidation state of oxygen in each oxide and the oxidation state of the other element should be determined.

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

All the oxygen in oxides are in −2 oxidation state.

Interpretation Introduction

(b)

Interpretation:

Each oxide should be identified as molecular or a solid with an infinity extended three-dimensional structure

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

Interpretation Introduction

(c)

Interpretation:

The oxides which are likely to be a gas or a liquid and which are likely to be a high-melting solid should be determined.

Concept introduction:

Most of ionic oxides form crystal lattice structures. Lattice energies are very high, so, the bonds between atoms are difficult to break. So, ionic oxides have higher melting points. Most first row and second row nonmetal oxides have lower melting points, so, most of them exists as gas or liquid at room temperature.

Interpretation Introduction

(d)

Interpretation:

The identity of the other element in (2) and (3) should be determined.

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Draw the missing intermediates 1 and 2, plus the final product 3, of this synthesis: 0 1. Eto 1. Eto- 1 2 2. MeBr 2. EtBr H3O+ A 3 You can draw the three structures in any arrangement you like. Explanation Check Click and drag to start drawing a structure.

Draw the missing intermediate 1 and final product 2 of this synthesis: 1. MeO- H3O+ 1 2 2. PrBr Δ You can draw the two structures in any arrangement you like. Click and drag to start drawing a structure.

What is the differences between: Glyceride and phosphoglyceride Wax and Fat Soap and Fatty acid HDL and LDL cholesterol Phospho lipids and sphingosine What are the types of lipids? What are the main lipid components of membrane structures? How could lipids play important rules as signaling molecules and building units? The structure variety of lipids makes them to play significant rules in our body, conclude breifly on this statement.

Answer 2

Question

Chapter 22, Problem 22.25CP

Interpretation Introduction

(a)

Interpretation:

The oxidation state of oxygen in each oxide and the oxidation state of the other element should be determined.

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

All the oxygen in oxides are in −2 oxidation state.

Interpretation Introduction

(b)

Interpretation:

Each oxide should be identified as molecular or a solid with an infinity extended three-dimensional structure

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

Interpretation Introduction

(c)

Interpretation:

The oxides which are likely to be a gas or a liquid and which are likely to be a high-melting solid should be determined.

Concept introduction:

Most of ionic oxides form crystal lattice structures. Lattice energies are very high, so, the bonds between atoms are difficult to break. So, ionic oxides have higher melting points. Most first row and second row nonmetal oxides have lower melting points, so, most of them exists as gas or liquid at room temperature.

Interpretation Introduction

(d)

Interpretation:

The identity of the other element in (2) and (3) should be determined.

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 22, Problem 22.25CP

Interpretation Introduction

(a)

Interpretation:

The oxidation state of oxygen in each oxide and the oxidation state of the other element should be determined.

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

All the oxygen in oxides are in −2 oxidation state.

Interpretation Introduction

(b)

Interpretation:

Each oxide should be identified as molecular or a solid with an infinity extended three-dimensional structure

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

Interpretation Introduction

(c)

Interpretation:

The oxides which are likely to be a gas or a liquid and which are likely to be a high-melting solid should be determined.

Concept introduction:

Most of ionic oxides form crystal lattice structures. Lattice energies are very high, so, the bonds between atoms are difficult to break. So, ionic oxides have higher melting points. Most first row and second row nonmetal oxides have lower melting points, so, most of them exists as gas or liquid at room temperature.

Interpretation Introduction

(d)

Interpretation:

The identity of the other element in (2) and (3) should be determined.

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 22, Problem 22.25CP

Interpretation Introduction

(a)

Interpretation:

The oxidation state of oxygen in each oxide and the oxidation state of the other element should be determined.

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

All the oxygen in oxides are in −2 oxidation state.

Interpretation Introduction

(b)

Interpretation:

Each oxide should be identified as molecular or a solid with an infinity extended three-dimensional structure

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

Interpretation Introduction

(c)

Interpretation:

The oxides which are likely to be a gas or a liquid and which are likely to be a high-melting solid should be determined.

Concept introduction:

Most of ionic oxides form crystal lattice structures. Lattice energies are very high, so, the bonds between atoms are difficult to break. So, ionic oxides have higher melting points. Most first row and second row nonmetal oxides have lower melting points, so, most of them exists as gas or liquid at room temperature.

Interpretation Introduction

(d)

Interpretation:

The identity of the other element in (2) and (3) should be determined.

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 22, Problem 22.25CP

Interpretation Introduction

(a)

Interpretation:

The oxidation state of oxygen in each oxide and the oxidation state of the other element should be determined.

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

All the oxygen in oxides are in −2 oxidation state.

Interpretation Introduction

(b)

Interpretation:

Each oxide should be identified as molecular or a solid with an infinity extended three-dimensional structure

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

Interpretation Introduction

(c)

Interpretation:

The oxides which are likely to be a gas or a liquid and which are likely to be a high-melting solid should be determined.

Concept introduction:

Most of ionic oxides form crystal lattice structures. Lattice energies are very high, so, the bonds between atoms are difficult to break. So, ionic oxides have higher melting points. Most first row and second row nonmetal oxides have lower melting points, so, most of them exists as gas or liquid at room temperature.

Interpretation Introduction

(d)

Interpretation:

The identity of the other element in (2) and (3) should be determined.

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

Answer 6

Chapter 22, Problem 22.25CP

Interpretation Introduction

(a)

Interpretation:

The oxidation state of oxygen in each oxide and the oxidation state of the other element should be determined.

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

All the oxygen in oxides are in −2 oxidation state.

Answer 7

Chapter 22, Problem 22.25CP

Interpretation Introduction

(a)

Interpretation:

The oxidation state of oxygen in each oxide and the oxidation state of the other element should be determined.

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

All the oxygen in oxides are in −2 oxidation state.

Answer 8

Interpretation Introduction

(b)

Interpretation:

Each oxide should be identified as molecular or a solid with an infinity extended three-dimensional structure

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

Answer 9

Interpretation Introduction

(b)

Interpretation:

Each oxide should be identified as molecular or a solid with an infinity extended three-dimensional structure

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

Answer 10

Interpretation Introduction

(c)

Interpretation:

The oxides which are likely to be a gas or a liquid and which are likely to be a high-melting solid should be determined.

Concept introduction:

Most of ionic oxides form crystal lattice structures. Lattice energies are very high, so, the bonds between atoms are difficult to break. So, ionic oxides have higher melting points. Most first row and second row nonmetal oxides have lower melting points, so, most of them exists as gas or liquid at room temperature.

Answer 11

Interpretation Introduction

(c)

Interpretation:

The oxides which are likely to be a gas or a liquid and which are likely to be a high-melting solid should be determined.

Concept introduction:

Most of ionic oxides form crystal lattice structures. Lattice energies are very high, so, the bonds between atoms are difficult to break. So, ionic oxides have higher melting points. Most first row and second row nonmetal oxides have lower melting points, so, most of them exists as gas or liquid at room temperature.

Answer 12

Interpretation Introduction

(d)

Interpretation:

The identity of the other element in (2) and (3) should be determined.

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

Answer 13

Interpretation Introduction

(d)

Interpretation:

The identity of the other element in (2) and (3) should be determined.

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

Answer 14

Expert Solution & Answer

Answer 15

Expert Solution & Answer

Answer 16

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 17

Ch. 22 - Which element has more nonmetallic character:Cl or...Ch. 22 - Prob. 22.2A Ch. 22 - Prob. 22.3P Ch. 22 - Prob. 22.4A Ch. 22 - Prob. 22.5P Ch. 22 - Look at the location of elements A, B, C, and Din...Ch. 22 - What are the formula and charge of the silicate...Ch. 22 - Suggest a plausible structure for the silicate...Ch. 22 - Prob. 22.9P Ch. 22 - Write balanced net ionic equations for the...

Solution Summary: The author explains how oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electron through covalent bonding.

Concept explainers

Want to see the full answer?

Chapter 22 Solutions