(a) Interpretation: The empirical formula of the compound that is formed by the reaction of niobium and fluorine at room temperature that contains 49.44 % of Nb by mass should be determined. Concept introduction: The formula of the compound that gives information about the proportions of the elements present within a compound is said to be the empirical formula. It does not represent the actual numbers of the atoms present in the compound.
(a) Interpretation: The empirical formula of the compound that is formed by the reaction of niobium and fluorine at room temperature that contains 49.44 % of Nb by mass should be determined. Concept introduction: The formula of the compound that gives information about the proportions of the elements present within a compound is said to be the empirical formula. It does not represent the actual numbers of the atoms present in the compound.
Solution Summary: The author explains that the equilibrium equation for the reaction of niobium and fluorine at room temperature should be determined.
The empirical formula of the compound that is formed by the reaction of niobium and fluorine at room temperature that contains 49.44 % of Nb by mass should be determined.
Concept introduction:
The formula of the compound that gives information about the proportions of the elements present within a compound is said to be the empirical formula. It does not represent the actual numbers of the atoms present in the compound.
Interpretation Introduction
(b)
Interpretation:
The balance equation for the reaction of niobium and fluorine at room temperature should be determined.
Concept introduction:
The reaction is said to be balanced if the number of atoms of each element on the reactant and product side is equal.
Interpretation Introduction
(c)
Interpretation:
The balance equation for the reaction of NbF5 with hydrogen to regenerate metallic Nb should be determined.
Concept introduction:
The reaction is said to be balanced if the number of atoms of each element on the reactant and product side are equal.
43) 10.00 ml of vinegar (active ingredient is acetic acid) is titrated to the endpoint
using 19.32 ml of 0.250 M sodium hydroxide. What is the molarity of acetic acid
in the vinegar? YOU MUST SHOW YOUR WORK.
NOTE: MA x VA = MB x VB
424 Repon Sheet Rates of Chemical Reactions : Rate and Order of 1,0, Deception
B. Effect of Temperature
BATH TEMPERATURE
35'c
Yol of Oh
نام
Time
485
Buret rend
ing(n)
12
194
16.
6
18
20
10
22
24
14
115 95
14738
2158235
8:26 CMS
40148
Total volume of 0, collected
Barometric pressure 770-572
ml
mm Hg
Vapor pressure of water at bath temperature (see Appendix L) 42.2
Slope
Compared with the rate found for solution 1, there is
Using the ideal gas law, calculate the moles of O; collected
(show calculations)
times faster
10
Based on the moles of O, evolved, calculate the molar concentration of the original 3% 1,0, solution (sho
calculations)
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Step by Step Stoichiometry Practice Problems | How to Pass ChemistryMole Conversions Made Easy: How to Convert Between Grams and Moles; Author: Ketzbook;https://www.youtube.com/watch?v=b2raanVWU6c;License: Standard YouTube License, CC-BY