(a)
Interpretation:
Thegeometrical structure of
Concept introduction:
VSEPR theory stands as Valence Shell Electron Pair Repulsion Theory. It helps to predict the molecular shape or geometry of the molecule with the help of the number of bond pair or lone pair present in it. According to VSEPR theory, the presence of lone pair on the central atom of molecule causes deviation from standard molecular geometry. This is because of the repulsion between lone pairs and bond pairs of the central atom of the molecule. The order of repulsion is:
Lone pair-lone pair > lone pair-bond pair > bond pair-bond pair
Based on the number of lone pair and bond pair, the molecular geometry can be determined with the help of below table.
| Total number of electron pairs | Bond pair | Lone pair | Geometry |
| 2 | 2 | 0 | Linear |
| 2 | 1 | 1 | Linear |
| 3 | 3 | 0 | Trigonal planar |
| 3 | 2 | 1 | Bent |
| 4 | 4 | 0 | Tetrahedral |
| 4 | 3 | 1 | Trigonal pyramidal |
| 4 | 2 | 2 | Bent |
| 5 | 5 | 0 | Trigonal bipyramidal |
| 5 | 4 | 1 | See saw |
| 5 | 3 | 2 | T shaped |
| 5 | 2 | 3 | Linear |
| 6 | 6 | 0 | Octahedral |
(b)
Interpretation:
The geometrical structure of
Concept introduction:
VSEPR theory stands as Valence Shell Electron Pair Repulsion Theory. It helps to predict the molecular shape or geometry of the molecule with the help of the number of bond pair or lone pair present in it. According to VSEPR theory, the presence of lone pair on the central atom of molecule causes deviation from standard molecular geometry. This is because of the repulsion between lone pairs and bond pairs of the central atom of the molecule. The order of repulsion is:
Lone pair-lone pair > lone pair-bond pair > bond pair-bond pair
Based on the number of lone pair and bond pair, the molecular geometry can be determined with the help of below table.
| Total number of electron pairs | Bond pair | Lone pair | Geometry |
| 2 | 2 | 0 | Linear |
| 2 | 1 | 1 | Linear |
| 3 | 3 | 0 | Trigonal planar |
| 3 | 2 | 1 | Bent |
| 4 | 4 | 0 | Tetrahedral |
| 4 | 3 | 1 | Trigonal pyramidal |
| 4 | 2 | 2 | Bent |
| 5 | 5 | 0 | Trigonal bipyramidal |
| 5 | 4 | 1 | See saw |
| 5 | 3 | 2 | T shaped |
| 5 | 2 | 3 | Linear |
| 6 | 6 | 0 | Octahedral |
(c)
Interpretation:
The geometrical structure of
Concept introduction:
VSEPR theory stands as Valence Shell Electron Pair Repulsion Theory. It helps to predict the molecular shape or geometry of the molecule with the help of the number of bond pair or lone pair present in it. According to VSEPR theory, the presence of lone pair on the central atom of molecule causes deviation from standard molecular geometry. This is because of the repulsion between lone pairs and bond pairs of the central atom of the molecule. The order of repulsion is:
Lone pair-lone pair > lone pair-bond pair > bond pair-bond pair
Based on the number of lone pair and bond pair, the molecular geometry can be determined with the help of below table.
| Total number of electron pairs. | Bond pair | Lone pair | Geometry |
| 2 | 2 | 0 | Linear |
| 2 | 1 | 1 | Linear |
| 3 | 3 | 0 | Trigonal planar |
| 3 | 2 | 1 | Bent |
| 4 | 4 | 0 | Tetrahedral |
| 4 | 3 | 1 | Trigonal pyramidal |
| 4 | 2 | 2 | Bent |
| 5 | 5 | 0 | Trigonal bipyramidal |
| 5 | 4 | 1 | See saw |
| 5 | 3 | 2 | T shaped |
| 5 | 2 | 3 | Linear |
| 6 | 6 | 0 | Octahedral |
(d)
Interpretation:
The geometrical structure of
Concept introduction:
VSEPR theory stands as Valence Shell Electron Pair Repulsion Theory. It helps to predict the molecular shape or geometry of the molecule with the help of the number of bond pair or lone pair present in it. According to VSEPR theory, the presence of lone pair on the central atom of molecule causes deviation from standard molecular geometry. This is because of the repulsion between lone pairs and bond pairs of the central atom of the molecule. The order of repulsion is:
Lone pair-lone pair > lone pair-bond pair > bond pair-bond pair
Based on the number of lone pair and bond pair, the molecular geometry can be determined with the help of below table.
| Total number of electron pairs | Bond pair | Lone pair | Geometry |
| 2 | 2 | 0 | Linear |
| 2 | 1 | 1 | Linear |
| 3 | 3 | 0 | Trigonal planar |
| 3 | 2 | 1 | Bent |
| 4 | 4 | 0 | Tetrahedral |
| 4 | 3 | 1 | Trigonal pyramidal |
| 4 | 2 | 2 | Bent |
| 5 | 5 | 0 | Trigonal bipyramidal |
| 5 | 4 | 1 | See saw |
| 5 | 3 | 2 | T shaped |
| 5 | 2 | 3 | Linear |
| 6 | 6 | 0 | Octahedral |
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Chapter 22 Solutions
CHEMISTRY-TEXT
- What alkene or alkyne yields the following products after oxidative cleavage with ozone? Click the "draw structure" button to launch the drawing utility. and two equivalents of CH2=O draw structure ...arrow_forwardH-Br Energy 1) Draw the step-by-step mechanism by which 3-methylbut-1-ene is converted into 2-bromo-2-methylbutane. 2) Sketch a reaction coordinate diagram that shows how the internal energy (Y- axis) of the reacting species change from reactants to intermediate(s) to product. Brarrow_forward2. Draw the missing structure(s) in each of the following reactions. The missing structure(s) can be a starting material or the major reaction product(s). C5H10 H-CI CH2Cl2 CIarrow_forward
- Draw the products of the stronger acid protonating the other reactant. དའི་སྐད”“ H3C OH H3C CH CH3 KEq Product acid Product basearrow_forwardDraw the products of the stronger acid protonating the other reactant. H3C NH2 NH2 KEq H3C-CH₂ 1. Product acid Product basearrow_forwardWhat alkene or alkyne yields the following products after oxidative cleavage with ozone? Click the "draw structure" button to launch the drawing utility. draw structure ... andarrow_forward
- Draw the products of the stronger acid protonating the other reactant. H3C-C=C-4 NH2 KEq CH H3C `CH3 Product acid Product basearrow_forward2. Draw the missing structure(s) in each of the following reactions. The missing structure(s) can be a starting material or the major reaction product(s). C5H10 Br H-Br CH2Cl2 + enant.arrow_forwardDraw the products of the stronger acid protonating the other reactant. KEq H₂C-O-H H3C OH Product acid Product basearrow_forward
- Draw the products of the stronger acid protonating the other reactant. OH KEq CH H3C H3C `CH3 Product acid Product basearrow_forward2. Draw the missing structure(s) in each of the following reactions. The missing structure(s) can be a starting material or the major reaction product(s). Ph H-I CH2Cl2arrow_forward3 attempts left Check my work Draw the products formed in the following oxidative cleavage. [1] 03 [2] H₂O draw structure ... lower mass product draw structure ... higher mass productarrow_forward
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