PHYSICS F/SCI.+ENGRS.,STAND.-W/ACCESS
PHYSICS F/SCI.+ENGRS.,STAND.-W/ACCESS
6th Edition
ISBN: 9781429206099
Author: Tipler
Publisher: MAC HIGHER
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Chapter 22, Problem 1P
To determine

The direction of the electric field along the dashed 45° lineaway from the intersection point of both the lengths for the L-shaped object.

Expert Solution & Answer
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Explanation of Solution

Given:

The charge is uniformly distributed along the length of the L-shaped object having equal lengths on both sides.

Introduction:

Write the expression for the electric field due to continuous line charge distribution is

  E=14πε0λdl R ^ R 2

Here, ε0 is the free space permittivity, λ is the uniform linear charge density, R is the distance of the point from the charge distribution and dl is any elemental length on the L-shaped object carrying the charge.

.

  PHYSICS F/SCI.+ENGRS.,STAND.-W/ACCESS, Chapter 22, Problem 1P

Draw the diagram to show the different components of the electric field due to the L-shaped object.

Take an arbitrary point, situated a distance R on the dashed line due to any elemental length along the horizontal length.

Write the expression of the electric field on that point.

  EH=14πε0λdl R ^ R 2

Here, EH is the value of the electric field and the direction will be vertically upwards.

Similarly, take an arbitrary point situated a distance ‘ R ’ on the dashed line due to any elemental length along the vertical length.

Write the expression for the electric field on that point.ss

  EV=14πε0λdl R ^ R 2

Here EV is the value of the electric field and the direction will be horizontally towards the right of the vertical length.Take the resultant of both the fields.

The direction of the net electric field ( Enet ) will be along the dashed line away from the intersection point of the both lengths.

Conclusion:

Thus, the direction of the electric field along the dashed 45° line away from the intersection point of both the lengths for the L-shaped object.

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Chapter 22 Solutions

PHYSICS F/SCI.+ENGRS.,STAND.-W/ACCESS

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