Campbell Biology, Books a la Carte Plus Mastering Biology with eText -- Access Card Package (10th Edition)
10th Edition
ISBN: 9780133922851
Author: Jane B. Reece, Lisa A. Urry, Michael L. Cain, Steven A. Wasserman, Peter V. Minorsky, Robert B. Jackson
Publisher: PEARSON
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Chapter 21.5, Problem 2CC
Explain how multiple exons might have arisen in the ancestral EGF and fibronectin genes shown on the left side of Figure 21.16.
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a)
hours: 0 2 567
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Oxygen level (% normal)
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FIGURE 4.6. Comparison of Northern blots with DNA microarray
data. a) Results from four individual Northern blots examining four different
genes and measuring mRNA production over time, as indicated. b) Results
from a series of microarrays for the same four genes of interest. Note the color
scale on the bottom of b), where bright green indicates a 20-fold repression
and bright red indicates a 20-fold induction. Black indicates no change in
transcription (i.e., the merged microarray spot would have appeared yellow).
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gene Z
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fold repressed
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FIGURE 4.7 Transcriptional response of three genes
to the gradual loss of oxygen. a) Graph of oxygen con-
sumption over time by…
Based on Figure 9-19, can you predict the position of amutation that would affect the synthesis of one isoformbut not the other?
Explain how the following mutations would affect transcription of the yeast GAL1 gene in the presence of galactose. (a) A deletion within the GAL4 gene that removes the region encoding amino acids 1 to 100. (b) A deletion of the entire GAL3 gene. (c) A mutation within the GAL80 gene that blocks the ability of Gal80 protein to interact with Gal3p. (d) A deletion of one of the four UASG elements upstream from the GAL1 gene. (e) A point mutation in the GAL1 core promoter that alters the sequence of the TATA box.
Chapter 21 Solutions
Campbell Biology, Books a la Carte Plus Mastering Biology with eText -- Access Card Package (10th Edition)
Ch. 21.1 - Describe the whole-genome shotgun approach.Ch. 21.2 - Prob. 1CCCh. 21.2 - Explain the advantage of the systems biology...Ch. 21.2 - MAKE CONNECTIONS The ENCODE pilot project found...Ch. 21.2 - MAKE CONNECTIONS In Concept 20.2, you learned...Ch. 21.3 - The best estimate is that the human genome...Ch. 21.3 - Prob. 2CCCh. 21.3 - WHAT IF? What evolutionary processes might...Ch. 21.4 - Discuss the characteristics of mammalian genomes...Ch. 21.4 - VISUAL SKILLS Which of the three mechanisms...
Ch. 21.4 - Contrast the organizations of the rRNA gene family...Ch. 21.4 - MAKE CONNECTIONS Assign each DNA segment at the...Ch. 21.5 - Describe three examples of errors in cellular...Ch. 21.5 - Explain how multiple exons might have arisen in...Ch. 21.5 - What are three ways that transposable elements are...Ch. 21.5 - WHAT IF? In 2005, Icelandic scientists reported...Ch. 21.6 - Prob. 1CCCh. 21.6 - Prob. 2CCCh. 21.6 - Prob. 3CCCh. 21 - How did the Human Genome Project result in more...Ch. 21 - What has been the most significant finding of the...Ch. 21 - Compare genome size, gene number, and gene density...Ch. 21 - Explain how the function of transposable elements...Ch. 21 - How could chromosomal rearrangements lead to the...Ch. 21 - What type of Information can be obtained by...Ch. 21 - Bioinformatics intludes all of the following...Ch. 21 - Homeotic genes (A) encode transcription factors...Ch. 21 - Prob. 3TYUCh. 21 - DRAW IT Below are the amino acid sequences(using...Ch. 21 - EVOLUTION CONNECTION Genes important in the...Ch. 21 - scientific inquiry The scientists mapping the SNPs...Ch. 21 - Prob. 7TYUCh. 21 - SYNTHESIZE YOUR KNOWLEDGE Insects have three...
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- The streptolysin S toxin made by S. pyogenes is encoded by a 9-gene operon, sagABCDEFGHI. Thinking about what a 3-line diagram would look like for this operon, answer the following questions. Write numeric answers only. For example, if your answer is 6 promoters, write only 6. 1) How many promoters control the expression of these genes? 2) How many locations does RNA Polymerase bind to get full expression of these genes? 3) How many ribosome binding sites are needed for full protein expression? 4) How many start codons will be needed for full protein expression? 5) How many mRNA strands will be produced with full operon expression? 6) How many proteins will be produced with full protein expression? 1arrow_forwardThe attached table below shows the reference and a diseased patient's DMD genes in the hip flexor which, if mutated, can cause muscular dystophy. Analyze the table, make the coding strand, and explain how and which mutation in the patien's genes caused muscular dystrophyarrow_forwardDescribe how transcription would be affected in the Galactose metabolizing pathway in Yeast in the presence of the following mutations. 1. A mutation that resulted in an inability of Gal80 to enter the nucleus. 2. A mutation that resulted in a lack of ability of Gal3 to bind galactose.arrow_forward
- The transcription factor Pax6 is required continually during the life of a mouse (or a human) for the development of the retina. Homozygous Pax6 knockout mice die soon after birth because Pax6 protein is also required in essential organs, such as the pancreas. a) In order to study the role of Pax6 in eye development a researcher wants to generate a mouse that expresses Pax6 everywhere except in its eyes. Describe how you could construct such a mouse by floxing the gene. Is it possible to achieve the same end with a transgene? (Hint: think about using cDNA and RNAI) b) Suppose you want to create a mouse similar to that in part (a), but one where the eye cells from Pax6 function has been removed and now express a gene that specifies a green fluorescent protein (GFP). Marking the cells in this way will allow the investigators to see the shapes of the Pax6- eye cells more easily than if they did not express GFP. Diagram a Pax6 gene construct that would enable the researcher to do this…arrow_forwardUse the blanks on the left hand side to put the following statements in order (use numbers or letters to designate the order). All of the statements refer to the diauxic (sequential) growth of a bacterium on the carbon substrates glucose and lactose (see textbook Fig 4.11 on diauxic growth). Remember, the lac operon contains the genes necessary for the lactose catabolism. The glucose substrate is completely consumed, at which time the repressor protein on the lac operon unbinds from the DNA molecule. The lactose substrate is catabolized by the active B-galactosidase enzyme. Glucose, as the preferred carbon substrate, is first consumed by catabolic enzymes that are constitutive (always present). After completion of translation, the B-galactosidase enzyme undergoes folding to form into an active enzyme that can breakdown lactose into its constituent monosaccharides. The messenger RNA code from the lac operon is translated by ribosomal RNAS to form lac-related enzymes, such as…arrow_forwardConsidering Figure 2-13, if you had a homozygous double mutant m3/m3 m5/m5, would you expect it to be mutant in phenotype? (Note: This line would have two mutant sites in the same coding sequence.)arrow_forward
- The diagram below shows a closeup of regulatory proteins binding to one of the UASG elements near the GAL7, GALI0, and GALI genes, which code for the protein products needed for yeast to use the sugar galactose. The red triangle symbolizes an "effector" molecule that binds to Gal80p. In this hypothesis (which has since been shown to be incorrect), what could be happening to Gal80p when it is bound to the effector molecule that causes it to change its position and uncover the Gal4p transcriptional activation domain. Hint: think about what effector molecules do upon binding to proteins such as the the Lac repressor protein or the CAP protein. Galactose absent, glucose absent Gal80p. _Activation domain Gal4p dimer -Binding domain UASG Galactose present, glucose absent Activation domain Gal80p- Binding domain UASG For the toolbar, press ALT+F10 (PC) or ALT+FN+F10 (Mac).arrow_forwardSearching the yeast Saccharomyces cerevisiae genome, researchers found approximately 4,000 DNA sites with a sequence which could potentially bind the yeast transcription factor GAL4. GAL4 activates the transcription of galactose genes. Yet there are only 10 GAL4-binding sites which control the genes necessary for galactose metabolism. The GAL4 binding sequence is CGGAT#AGAAGC*GCCG, where # is T, C or G, and * is C or T. In one chromatin immunoprecipitation experiment (ChIP), yeast growing on galactose were lysed, and subjected to cross-linking reagents which cross-linked transcription factors and activators to DNA. Next the DNA was sheared into small fragments, and antibodies to GAL4 were added. These antibodies coprecipitated the GAL4 and the DNA it was cross-linked to. The cross-linking was then chemically reversed, and the DNA was isolated, cloned into a library of plasmids and sequenced. Results showed that only 10 different DNA sequences had GAL4 bound. Since the…arrow_forwardYou are working with a fly hair cell developmental system. This Notch/Delta-regulated system results in clusters of cells where the central one differentiates into a specialized hair cell. To better understand this system you have tagged the C-terminal cytoplasmic domain of Notch with GFP. You have done a forward genetic screen to look for mutants that have unusual phenotypes in this Notch system. The first one is a mutation in Notch itself. This mutant is in the ADAM10 cleavage site and blocks proteolysis. Draw the expected outcome for such a mutant: GFP localization and developmental outcome 24hr after differentiation. WT before differentiation WT 24 hours after differentiationarrow_forward
- Brenner’s m mutant phages (m1–m6) described inFig. 8.8 were suppressed when grown in suppressor(su−) mutant bacteria; they produced full-length Mproteins that functioned like wild-type M protein.a. What gene do you think was mutant in the su−bacteria?b. When the m− phages were propagated in the su−bacterial strain, not all of the proteins made by themutant m alleles were identical to wild-type Mprotein. How did some of them differ?arrow_forwardWhat is a second messenger? What are two second messengers that are involved in signaling pathways downstream of GPCRs and explain how they are produced? long answer: If you wanted to compare a cardiac muscle cell with a skeletal muscle, how could you use RNA sequencing to identify genes that are differentially expressed? In your answer, explain this technique and describe what type of information you can learn from it. If RNA sequencing led to the identification of two genes, gene X and gene Y, what are two experiments you could do to study the functions of these two genes?arrow_forwardNow read this abstract from a 2013 journal article What is the authors' explanation of how Gal80p works? Note UASG from the question above is the same as UASGAL The DNA-binding transcriptional activator Gal4 and its regulators Gal80 and Gal3 constitute a galactose-responsive switch for the GAL genes of Saccharomyces cerevisiae. Gal4 binds to GAL gene UASGAL. (upstream activation sequence in GAL gene pro- moter) sites as a dimer via its N-terminal domain and activates transcription via a C-terminal transcription activation domain (AD). In the absence of galactose, a Gal80 dimer binds to a dimer of Gal4, masking the Gal4AD. Galactose triggers Gal3-Gal80 interaction to rapidly initiate Gal4-mediated transcription activation. Just how Gal3 alters Gal80 to relieve Gals0 inhibition of Gal4 has been unknown, but previous analyses of Gal80 mutants suggested a possible competition between Gal3-Gal80 and Gal80 self-association interactions. Here we assayed Gal80-Gal80 interactions and tested for…arrow_forward
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