Coaxial cables are widely used with audio-visual technology, electronic instrumentation, and radio broadcasting, because they minimize interference with or from signals traveling on the cable. Coaxial cables consist of a wire inner conductor surrounded by a thin cylindrical conducting shield, usually of braided copper (Fig. 21.39). Flexible insulation separates the conductors. A straight length of coaxial cable can be approximated as an infinitely long wire surrounded by a cylindrical shell. Normally the two conductors carry charges of equal magnitude but opposite sign. (Charge actually varies with lime and position as signals travel down the cable, but for these problems consider the charge to be fixed and spread uniformly.) FIGURE 21.39 A coaxial cable (Passage Problems 76-79) For a coaxial cable in electrostatic equilibrium carrying equal bill opposite charges on its two conductors, there’s a nonzero electric field a. only in the space between the wire and shield. b. in the space between wire and shield, and outside the shield. c. inside the metal conducting wire and shield, as well as between the wires and outside the shield. d. only outside the shield.
Coaxial cables are widely used with audio-visual technology, electronic instrumentation, and radio broadcasting, because they minimize interference with or from signals traveling on the cable. Coaxial cables consist of a wire inner conductor surrounded by a thin cylindrical conducting shield, usually of braided copper (Fig. 21.39). Flexible insulation separates the conductors. A straight length of coaxial cable can be approximated as an infinitely long wire surrounded by a cylindrical shell. Normally the two conductors carry charges of equal magnitude but opposite sign. (Charge actually varies with lime and position as signals travel down the cable, but for these problems consider the charge to be fixed and spread uniformly.) FIGURE 21.39 A coaxial cable (Passage Problems 76-79) For a coaxial cable in electrostatic equilibrium carrying equal bill opposite charges on its two conductors, there’s a nonzero electric field a. only in the space between the wire and shield. b. in the space between wire and shield, and outside the shield. c. inside the metal conducting wire and shield, as well as between the wires and outside the shield. d. only outside the shield.
Coaxial cables are widely used with audio-visual technology, electronic instrumentation, and radio broadcasting, because they minimize interference with or from signals traveling on the cable. Coaxial cables consist of a wire inner conductor surrounded by a thin cylindrical conducting shield, usually of braided copper (Fig. 21.39). Flexible insulation separates the conductors. A straight length of coaxial cable can be approximated as an infinitely long wire surrounded by a cylindrical shell. Normally the two conductors carry charges of equal magnitude but opposite sign. (Charge actually varies with lime and position as signals travel down the cable, but for these problems consider the charge to be fixed and spread uniformly.)
FIGURE 21.39 A coaxial cable (Passage Problems 76-79)
For a coaxial cable in electrostatic equilibrium carrying equal bill opposite charges on its two conductors, there’s a nonzero electric field
a. only in the space between the wire and shield.
b. in the space between wire and shield, and outside the shield.
c. inside the metal conducting wire and shield, as well as between the wires and outside the shield.
You have a summer job as an assistant technician for a telephone company in California.During a recent earthquake, a 1.0-mile long underground telephone line is crushed atsome point. This telephone line is made up of two parallel copper wires of the samediameter and same length, which are normally not connected. At the place where theline is crushed, the two wires make contact. Your boss wants you to find this placeso that the wire can be dug up and fixed. You disconnect the line from the telephonesystem by disconnecting both wires of the line at both ends. You then go to one end ofthe line and connect one terminal of a 6.0-V battery to one wire, and the other terminalof the battery to one terminal of an ammeter. When the other terminal of the ammeteris connected to the other wire, the ammeter shows that the current through the wire is1.0 A. You then disconnect everything and travel to the other end of the telephone line,where you repeat the process and find a current of 1/3 A
Physics students, wanted to investigate the forces of attraction (F) between two parallel conductors carrying currents li and l2
(also known as Ampere's Law)
The students noticed that as the length of the parallel
conductors (/) was increased the force of attraction between
the conductors (F) also increased. The data collected is in the
|L= SA
conductor 1
average separation
(d = 0.50m)
table:
conductor 2
Length, / (m)
Force, F (x 10-5 N)
12= 5A
1.00
9.00
1.20
10.8
1.40
12,5
1.60
14.2
1.80
16.2
(iii) On the grid plot the force and length values from
the table.
(iv) Draw the line of best fit
(v) Find the slope of the line of best fit.
(c) Use the slope calculated and the Ampere's Law
equation to determine the experimental value of
the magnetic force constant, k.
10:25 E 54% N
K/s
(3
Imssb1.mutah.edu.jo/m 0
سؤال 4
غير مجاب عليه بعد
10.00
الدرجة من
علم هذا السؤال
Find the capacitance ( in units
of pF) of a conducting sphere
that has a radius of 35.6 cm.
. use ɛo = 8.8542×10-12 F:m¬1
اخترأحد الخیارات
A. 21.76
B. 100.04
C. 32.75
D. 18.20
+
University Physics with Modern Physics (14th Edition)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.