
Concept explainers
(a)
Interpretation: The number of unpaired electrons in the given complex ions is to be calculated.
Concept introduction: Weak field ligand that has small crystal field splitting energy gives high spin due to the presence of maximum unpaired electrons in lower energy
Strong field ligand that has large crystal field splitting energy gives low spin due to the presence of maximum paired electrons in lower energy
To determine: The number of unpaired electrons in
(b)
Interpretation: The number of unpaired electrons in the given complex ions is to be calculated.
Concept introduction: Weak field ligand that has small crystal field splitting energy gives high spin due to the presence of maximum unpaired electrons in lower energy
Strong field ligand that has large crystal field splitting energy gives low spin due to the presence of maximum paired electrons in lower energy
To determine: The number of unpaired electrons in
(c)
Interpretation: The number of unpaired electrons in the given complex ions is to be calculated.
Concept introduction: Weak field ligand that has small crystal field splitting energy gives high spin due to the presence of maximum unpaired electrons in lower energy
Strong field ligand that has large crystal field splitting energy gives low spin due to the presence of maximum paired electrons in lower energy
To determine: The number of unpaired electrons in

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Chapter 21 Solutions
Student Solutions Manual for Zumdahl/Zumdahl/DeCoste?s Chemistry, 10th Edition
- Please predict the products for each of the following reactions: 1.03 2. H₂O NaNH, 1. n-BuLi 2. Mel A H₂ 10 9 0 H2SO4, H₂O HgSO4 Pd or Pt (catalyst) B 9 2 n-BuLi ♡ D2 (deuterium) Lindlar's Catalyst 1. NaNH2 2. EtBr Na, ND3 (deuterium) 2. H₂O2, NaOH 1. (Sia)2BH с Darrow_forwardin the scope of ontario SCH4U grade 12 course, please show ALL workarrow_forwardIs the chemical reaction CuCl42-(green) + 4H2O <==> Cu(H2O)42+(blue) + 4Cl- exothermic or endothermic?arrow_forward
- If we react tetraethoxypropane with hydrazine, what is the product obtained (explain its formula). State the reason why the corresponding dialdehyde is not used.arrow_forwarddrawing, no aiarrow_forwardIf CH3COCH2CH(OCH3)2 (4,4-dimethoxy-2-butanone) and hydrazine react, two isomeric products are formed. State their structure and which will be the majority.arrow_forward
- + Reset Provide the correct IUPAC name for the compound shown here. 4-methylhept-2-ene (Z)- (E)- 1-6-5-2-3-4- cyclo iso tert- sec- di tri hept hex oct meth eth pent ane yne ene ylarrow_forward+ Provide the correct IUPAC name for the compound shown here. Reset H3C H H C CH3 CH-CH3 1-3-methylpent ene trans- cis- 5-6-3-1-2-4- tert- tri sec- di cyclo iso but pent hex meth prop eth yl ane ene yne ☑arrow_forwarddrawing, no aiarrow_forward
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