If you wished to warm 100 kg of water by
Amount of heat required in joule and calories.
Answer to Problem 54A
Heat required is
Explanation of Solution
Given:
Mass of water,
Change in temperature of water,
Formula used:
Where, Q is amount of heat required, m is mass, c is specific heat and
Calculation:
Specific heat of water is,
Now, substituting the value m , c and
Now, 1 cal = 1.184 J
Therefore,
Conclusion:
Therefore, heat required is
Chapter 21 Solutions
Conceptual Physics: The High School Physics Program
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