Chapter 21, Problem 56A

(a)

To determine

The amount of ice water the person drinks.

Answer to Problem 56A

The amount of ice water the person drinks to burn 3500 Calories is $94.6\text{ kg}$ .

Explanation of Solution

Given:

Total calories a girl has to burn is 3500.

Formula used:

The expression for heat transfer is,

  $Q=mc\Delta T$

Here, $m$ is the mass, $c$ is the specific heat, and $\Delta T$ is the change in temperature.

Calculation:

Consider the specific heat as $c=1000\text{cal}/\text{kg}\cdot °\text{C}$ .

The change in temperature is,

  $\begin{array}{l}\Delta T=37°\text{C}-0°\text{C}\\ \Delta T=37°\text{C}\end{array}$

The amount of ice water the person drinks is,

  $\begin{array}{l}Q=mc\Delta T\\ 3500\text{ Calories}\times \frac{1000\text{ calories}}{1\text{ Calorie}}=m\times \left(1000\text{cal}/\text{kg}\cdot °\text{C}\right)\times \left(37°\text{C}\right)\\ m=94.6\text{ kg}\end{array}$

Conclusion:

Thus, the amount of ice water the person drinks to burn 3500 Calories is $94.6\text{ kg}$ .

(b)

To determine

To identify: Whether the person recommends this method for losing weight or not.

Answer to Problem 56A

The drinking of ice water is recommended for losing weight.

Explanation of Solution

Introduction:

The water absorbs more amount of heat, due to the increase in temperature of the water. The specific heat capacity resists the temperature changes in the climate.

Calculation:

Water has a large amount of capacity for the storage of energy with respect to the other materials in daily life. It is a transparent material and has large amount of specific heat.

So, drinking of ice water is recommended for losing weight because drinking of excess water heat up the body and releases the energy.

Conclusion:

Thus, the drinking of ice water is recommended for losing weight.