DeGarmo's Materials and Processes in Manufacturing
12th Edition
ISBN: 9781118987674
Author: J. T. Black, Ronald A. Kohser
Publisher: WILEY
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Chapter 21, Problem 4P
Explain how you would estimate the cutting force for a turning operation if you do not have a dynamometer?
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Find the machining time, in seconds, and the rate of material removing in mmA3;sec for a turning operation having the following information: 1- Wp diameter is 80mm, 2- the length is 0.12m, 3- the cutting speed is 80m/min, 4- feed i50.5 mm/rev and 5- the depth of cut is 0.002m.
A high-speed steel tool is used to turn a steel work part that is 360 mm long
and 78 mm in diameter. The parameters in the Tylor equation are: n = 0.12
and C = 71 m/min for a feed of 0.40 mm/rev. The operator and machine tool
rate = $36.00/hr, and the tooling cost per cutting edge = $4.25. It takes 3.5
min to load and unload the work part and 5.0 min to change tools. The total
time required to produce one unit is closest to,
A high-sneed stel tool is ucod to tuurn
A HSS tool is used to turn a steel workpart that is 300 mm long and 80 mm in diameter. The
parameters in the Taylor equation are: n=0.13 and C= 75 (m/min) for a feed of 0.4 mm/rev.
The operator and machine tool rate = $30.00/hr, and the tooling cost per cutting edge =
$4.00. It takes 2.0 min to load and unload the workpart and 3.50 min to change tools.
Determine:
a. Tutting speed for maximum production rate,
b. Tool life in min of cutting, and
c. Cycle time and cost per unit of product.
Chapter 21 Solutions
DeGarmo's Materials and Processes in Manufacturing
Ch. 21 - Why has the metal-cutting process resisted...Ch. 21 - What variables must be considered in understanding...Ch. 21 - Which of the seven basic chip formation processes...Ch. 21 - How is feed related to speed in the machining...Ch. 21 - Before you select speed and feed for a machining...Ch. 21 - Milling has two feeds. What are they, and which...Ch. 21 - What is the fundamental mechanism of chip...Ch. 21 - What is the difference between oblique machining...Ch. 21 - What are the implications of Figure 21.13, given...Ch. 21 - Note that the units for the approximate equation...
Ch. 21 - For orthogonal machining, the cutting edge radius...Ch. 21 - How do the magnitude of the strain and strain rate...Ch. 21 - Why is titanium such a difficult metal to machine?...Ch. 21 - Explain why you get segmented or discontinuous...Ch. 21 - Why is metal cutting shear stress such an...Ch. 21 - Which of the three cutting forces in oblique...Ch. 21 - How is the energy in a machining process typically...Ch. 21 - Where does the energy consumed in metal cutting...Ch. 21 - What are two ways of estimating the primary...Ch. 21 - What are the three different ways to perform...Ch. 21 - Why does the cutting force Fc increase with...Ch. 21 - Why doesnt the cutting force Fc increase with...Ch. 21 - Prob. 23RQCh. 21 - How does the selection of the machining parameters...Ch. 21 - Suppose you had a machining operation (boring)...Ch. 21 - Make a sketch like that shown in Figure 21.1 with...Ch. 21 - Show how you would do near orthogonal machining in...Ch. 21 - Can you do orthogonal machining on a shaper or...Ch. 21 - What process and material combination would yield...Ch. 21 - What is meant by the statement that machining...Ch. 21 - Prob. 31RQCh. 21 - Figure 21.4 provides suggested cutting speeds and...Ch. 21 - For problem 1, suppose you selected a speed of 145...Ch. 21 - If the cutting forces is 1000 lb calculate the...Ch. 21 - Explain how you would estimate the cutting force...Ch. 21 - For a turning operation, you have selected a...Ch. 21 - For a slab milling operation using a...Ch. 21 - The power required to machine metal is related to...Ch. 21 - In order to drill a hole in the material described...Ch. 21 - Suppose you have the data in Table 21.A obtained...Ch. 21 - Calculate the horsepower that a process is going...Ch. 21 - Explain how you would estimate the cutting force...Ch. 21 - Derive equations for F and N using the circular...Ch. 21 - Prob. 14PCh. 21 - Prob. 15PCh. 21 - A manufacturing engineer needs an estimate of the...Ch. 21 - Using Figure 21.4 for input data, determine the...Ch. 21 - Estimate the horsepower needed to remove metal at...Ch. 21 - For a turning process, the horsepower required was...
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- A HSS tool is used to turn a steel workpart that is 300 mm long and 80 mm in diameter. The parameters in the Taylor equation are: n = 0.13 and C = 75 (m/min) for a feed of 0.4 mm/rev. The operator and machine tool rate = $30.00/hr, and the tooling cost per cutting edge = $4.00. It takes 2.0 min to load and unload the workpart and 3.50 min to change tools. Determine: Tutting speed for maximum production rate, Tool life in min of cutting, and Cycle time and cost per unit of product. determine cutting speed for minimum cost.arrow_forwardA motorised metal guillotine machine is required to cut 45 mm diameter hole in a plate of 20 mm thickness at rate of 35 holes per minute. It requires a torque of 7 Nm for an area of hole in mm². If the cutting takes 1/10 of a second and the speed of it's flywheel varies from 165 rpm to 145 rpm, calculate 4.1)Energy required to cut a hole 4.2)Energy required for cutting work per second. 4.3)Maximum fluctuation of energy of the flywheel 4.4)Mass of the flywheel having radius of gyrations of 1,5 marrow_forwardA motorised metal guillotine machine is required to cut 45 mm diameter hole ina plate of 20 mm thickness at rate of 35 holes per minute. It requires a torqueof 7 Nm for an area of hole in mm?. If the cutting takes 1/10 of a second andthe speed of its flywheel varies from 165 rpm to 145 rpm, calculate:1.Energy required to cut a hole.2.Energy required for cutting work per second.3.Maximum fluctuation of energy of the flywheel.4.Mass of the flywheel having radius of gyration of 1.5 m.arrow_forward
- A cemented carbide tool is used to turn a part with length = 18.0 in and diameter = 3.0 in. The parameters in the Taylor equation are: n = 0.27 and C = 1200. The rate for the operator and machine tool = $33.00/hr, and the tooling cost per cutting edge = $2.00. It takes 3.0 min to load and unload the workpart and 1.50 min to change tools. The feed = 0.013 in/rev. Determine: Cutting speed for maximum production rate, Tool life in min of cutting, and Cycle time and cost per unit of product.arrow_forwardPlease answer all partsarrow_forwardIn a machine test, a cutting speed of 100 m/min indicated the tool life as 16 min and a cutting speed of 200 m/min indicated the tool life as 4 min. Calculate the values of n and C.arrow_forward
- In a production turning operation, the workpart is 60 mm in diameter and 500 mm long. A feed of 0.75 mm/rev is used in the operation. If cutting speed=9 m/s, the tool must be changed every 4 workparts; But if cutting speed=5 m/s, the tool can be used to produce 50 pieces between tool changes. Determine the Taylor tool life equation for this job. (use the equations given below for solution)arrow_forwardUsing slot milling with a cutting tool surface width of 36mm was performed from the top surface to cut a workpiece of 85 x 42 x 8 cm into two equal parts. The milling cutter is 180 mm in diameter and has eight teeth. Cutting speed = 60 m/min, chip load = 0.35 mm/ tooth, and depth of cut = 2 mm, given that the setup and machine settings provide an approach distance of 7mm before actual cutting begins and an overtravel distance of 20 mm after actual cutting has finished, and the return time is a 4-second for idle pass stroke. Determine:- 1. What is the total machining time required for the entire workpiece? 2. The maximum metal removal rate during cutting.arrow_forwardA turning machining experiment was performed at the UCSI University's Mechanical Engineering workshop using a lathe machine with palm oil as lubricant. It was observed that during the entire machining, the technician set cutting tool perpendicular to the direction of tool motion. A further investigation revealed that the tool rake angle was 25° while the dynamometer results' analysis showed that the frictional force and the normal force to the friction was 5 kN and 25 kN respectively. Analyze how the chip thickness will be affected if the machining is performed without any lubricant and the frictional force is increased by 100 %. Assume that, all other parameters were kept constant during the entire operation for both machining with lubricant and the dry machining process.arrow_forward
- Calculate the spindle speed (rpm) for turning operation when the cutting speed is 107.00 m/min and external diameter is D44.00 mm? (Two decimal places; Don't input units.) Your Answer: Answerarrow_forwardIn an orthogonal cutting test with a bar of 75 mm diameter is reduced to 73 mm by using a HSS tool with arake angle = 10o, following observations were made: length of the chip, lc = 69.44 mm, cutting ratio r =0.3, the horizontal component of the cutting force, FH = 1450 N, and the vertical component of the cuttingforce, FV = 850 N. The various parameters recorded in this cutting operation are: depth of cut, d = 2 mm;feed rate, f = 0.3 mm/rev, cutting speed, V = 60 m/min. Using Merchant’s theory calculate the following:1) Friction force along rake face2) Normal force acting on rake face3) Shear force along the shear plane4) Normal force acting on shear plane5) The percentage error in shear angle predicted by Merchant’s theory6) Shear velocity7) Chip velocity8) Total work done9) The shear work proportion out of the total work done10) The friction work proportion out of the total work donearrow_forwardA motorised metal guillotine machine is required to cut 45 mm diameter hole in a plate of 20 mm thickness at rate of 35 holes per minute. It requires a torque of 7 Nm for an area of hole in mm2. If the cutting takes 1/10 of a second and the speed of its flywheel varies from 165 rpm to 145 rpm, calculate: 1. Energy required to cut a hole. 2. Energy required for cutting work per second. 3. Maximum fluctuation of energy of the flywheel. 4. Mass of the flywheel having radius of gyration of 1.5 m.arrow_forward
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