BIOCHEMISTRY
BIOCHEMISTRY
9th Edition
ISBN: 2818440090622
Author: BERG
Publisher: MAC HIGHER
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Chapter 21, Problem 39P
Interpretation Introduction

Interpretation:

Crystals of phosphorylase a grown in the presence of glucose shatter when a substrate such as glucose 1-phosphate is added, this statement should be explained.

Concept introduction:

Glucose can act as a allosteric inhibitor for phosphorylase a enzyme.

Enzymes have different conformational equilibrium.

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The beta-lactamase hydrolyzes the lactam-ring in penicillin. Describe the mechanism  of hydrolysis, insuring to include the involvement of S, D, & K in the reaction sequence. Please help
To map the active site of beta-lactamase, the enzyme was hydrolyzed with trypsin to yield a hexapeptide (P1) with the following amino acids. Glu, Lys, Leu, Phe, Met, and Ser. Treatment of P1 with phenyl isothiocyanate yielded a PTH derivative of phenylalanine and a peptide (P2). Treatment of P1 with cyanogenbromide gave an acidic tetrapeptide (P3) and a dipeptide (P4).Treatment of P2 with 1-fluoro-2,4-dinitrobenzene, followed by complete hydrolysis, yields N-2,4-dinitrophenyl-Glu. P1, P2, and P3 contain the active site serine. Why doesn't D in this hexapeptide not participate in the hydrolysis of the beta-lactam ring even though S, K, and D are involved in the catalyst?
To map the active site of -lactamase, the enzyme was hydrolyzed with trypsin to yield a hexapeptide (P1) with the following amino acids. Glu, Lys, Leu, Phe, Met, and Ser. Treatment of P1 with phenyl isothiocyanate yielded a PTH derivative of phenylalanine and a peptide (P2). Treatment of P1 with cyanogenbromide gave an acidic tetrapeptide (P3) and a dipeptide (P4).Treatment of P2 with 1-fluoro-2,4-dinitrobenzene, followed by complete hydrolysis, yields N-2,4-dinitrophenyl-Glu. P1, P2, and P3 contain the active site serine.  Using the experimental results described above derive the primary sequence of the active site hexapeptide. Please help!
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