EBK MANUFACTURING ENGINEERING & TECHNOL
7th Edition
ISBN: 9780100793439
Author: KALPAKJIAN
Publisher: YUZU
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Textbook Question
Chapter 21, Problem 25QLP
The cutting force increases with the depth of cut and decreasing rake angle. Explain why.
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2 1.25 The cutting force increases with the depth of cut and decreasing rake angle. Explain why.
2 1.57 Show that, for the same shear angle, there are two rake angles that give the same cutting ratio.
A bar of 70 mm diameter is being cut orthogonally and is reduced to 68 mm by cutting tool in case mean length of the chip is 68.9 mm. find the cutting ratio determine shear angle also if the rake angle is 10 degree.
Chapter 21 Solutions
EBK MANUFACTURING ENGINEERING & TECHNOL
Ch. 21 - Explain why continuous chips are not necessarily...Ch. 21 - Name the factors that contribute to the formation...Ch. 21 - What is the cutting ratio? Is it always less than...Ch. 21 - Explain the difference between positive and...Ch. 21 - Explain how a dull tool can lead to negative rake...Ch. 21 - Comment on the role and importance relief angle.Ch. 21 - Explain the difference between discontinuous chips...Ch. 21 - Why should we be interested in the magnitude of...Ch. 21 - What are the differences between orthogonal and...Ch. 21 - What is a BUE? Why does it form?
Ch. 21 - Is there any advantage to having a built-up edge...Ch. 21 - What is the function of chip breakers? How do they...Ch. 21 - Identify the forces involved in a cutting...Ch. 21 - Explain the characteristics of different types of...Ch. 21 - List the factors that contribute to poor surface...Ch. 21 - Explain what is meant by the term machinability...Ch. 21 - What is shaving in machining? When would it be...Ch. 21 - List reasons that machining operations may be...Ch. 21 - Are the locations of maximum temperature and...Ch. 21 - Is material ductility important for machinability?...Ch. 21 - Explain why studying the types of chips produced...Ch. 21 - Prob. 22QLPCh. 21 - Tool life can be almost infinite at low cutting...Ch. 21 - Explain the consequences of allowing temperatures...Ch. 21 - The cutting force increases with the depth of cut...Ch. 21 - Why is it not always advisable to increase the...Ch. 21 - What are the consequences if a cutting tool chips?Ch. 21 - What are the effects of performing a cutting...Ch. 21 - Prob. 29QLPCh. 21 - Prob. 30QLPCh. 21 - Prob. 31QLPCh. 21 - Prob. 32QLPCh. 21 - Comment on your observations regarding Figs. 21.1...Ch. 21 - Prob. 34QLPCh. 21 - Comment on your observations regarding the...Ch. 21 - Why does the temperature in cutting depend on the...Ch. 21 - You will note that the values of a and b in Eq....Ch. 21 - Prob. 38QLPCh. 21 - Prob. 39QLPCh. 21 - Explain whether it is desirable to have a high or...Ch. 21 - The Taylor tool-life equation is directly...Ch. 21 - Prob. 42QLPCh. 21 - Why are tool temperatures low at low cutting...Ch. 21 - Can high-speed machining be performed without the...Ch. 21 - Prob. 45QLPCh. 21 - Prob. 46QLPCh. 21 - State whether or not the following statements are...Ch. 21 - Let n = 0.5 and C = 400 in the Taylor equation for...Ch. 21 - Assume that, in orthogonal cutting, the rake angle...Ch. 21 - Prob. 50QTPCh. 21 - Prob. 51QTPCh. 21 - Using trigonometric relationships, derive an...Ch. 21 - An orthogonal cutting operation is being carried...Ch. 21 - Prob. 54QTPCh. 21 - Prob. 55QTPCh. 21 - Prob. 56QTPCh. 21 - Show that, for the same shear angle, there are two...Ch. 21 - With appropriate diagrams, show how the use of a...Ch. 21 - In a cutting operation using a 5 rake angle, the...Ch. 21 - For a turning operation using a ceramic cutting...Ch. 21 - In Example 21.3, if the cutting speed V is...Ch. 21 - Using Eq. (21.30), select an appropriate feed for...Ch. 21 - With a carbide tool, the temperature in a cutting...Ch. 21 - The following flank wear data were collected in a...Ch. 21 - The following data are available from orthogonal...Ch. 21 - Prob. 66QTPCh. 21 - Design an experimental setup whereby orthogonal...Ch. 21 - Describe your thoughts on whether chips produced...Ch. 21 - Recall that cutting tools can be designed so that...Ch. 21 - Recall that the chip-formation mechanism also can...Ch. 21 - Prob. 73SDPCh. 21 - Describe your thoughts regarding the recycling of...Ch. 21 - List products that can be directly produced from...Ch. 21 - Obtain a wood planer and some wood specimens. Show...Ch. 21 - It has been noted that the chips from certain...Ch. 21 - As we have seen, chips carry away the majority of...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- In orthogonal turning of a low carbon steel bar of diameter 150 mm with uncoated carbide tool. the cutting velocity is 90 m/min The feed is 0.24 mm/rev and the depth of cut is 2 mm. The chip thickness obtained is 0.48 mm If the orthogonal rake angle is zero and the principal cutting edge angle is 90° Calculate the shear angle in degree.arrow_forwardDifferentiate between orthogonal and oblique cutting.explain the importance of eacharrow_forwardA tool with zero rake angle used in orthogonal cutting when its clearance angle a is changed from 10 to 7 deg, Calculate the approximate % change in the life of the tool.arrow_forward
- The orthogonal cutting of steel is done with 10° rake tool with a depth of cut of 4mm feed rate of 0.4mm/rev. The cutting speed is 200m/min. The chip thickness ratio is 0.35. The vertical cutting force is 1200N and the horizontal cutting force is 700N. Calculate from the Merchant's theory, the various work done in metal cutting and shear stress.arrow_forwardI need the answer as soon as possiblearrow_forwardDetermine ratio of friction energy to total energyarrow_forward
- * ordiogonal cutting of material the feed force is 80 kg and cuutting force is 150 kg. Calculate the following: 1. Compression and shear forces on shear plane. 2. Coefficient of friction of the chip on the tool face. Take chip thickness ratio as 0.3 and rake angle as 8.arrow_forwardFind the ratio of friction energy to total energy,i need correct solution without any mistakes otherwise skip to othersarrow_forwardAn orthogonal cutting operation is being carried out under the following conditions: depth of cut, to = 0.1 mm, rake angle, a = 10°, Cutting force, Fc =1500 N, and Thrust force, Ft = 800 N. Calculate the shear force.arrow_forward
- (b) An orthogonal cutting operation is being carried out under the following conditions: depth of cut, to = 0.1 mm, chip thickness, to = 0.2 mm, width of cut = 4 mm, cutting speed, v = 3 m/s, rake angle, a = 10°, Cutting force, Fc = 500 N, and Thrust force, F1= 200 N. Calculate the percentage of the total energy that is dissipated in the shear plane of cutting process.arrow_forwardA student is using a lathe with 80-hp and 80% efficiency to fabricate a copper alloy with Sy = 1200ksi If the width of cut is 0.30 inand the student set a rake angle of 0and a cutting speed of 200fl / min while she assumed a coefficient of friction to be 0.5. What is the maximum depth of cut the student can achieve?arrow_forwardAn orthogonal cutting operations is being carried out in which uncut thickness is 0.010 mm, cutting speed is 130 m/min, rake angle is 15° and width of cut is 6 mm. It is observed that the chip thickness is 0.015 mm, the cutting force is 60 N and the thrust force is 25 N. The ratio of friction energy to total energy is (correct to twoarrow_forward
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