Essential Organic Chemistry, Global Edition
3rd Edition
ISBN: 9781292089034
Author: Paula Yurkanis Bruice
Publisher: PEARSON
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Chapter 20.4, Problem 6P
Interpretation Introduction
Interpretation:
Difference in the amino acid composition of integral and peripheral membrane protein has to be given.
Concept Introduction:
Phosphoglycerides form membranes by arranging themselves in a lipid bilayer. The polar heads of the phosphoglycerides are on both surfaces of the bilayer and fatty acids form the interior of the bilayer.
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Students have asked these similar questions
For the decomposition reaction of N2O5(g): 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed:
N2O5 NO2 + NO3 (K1) | NO2 + NO3 → N2O5 (k-1) | NO2 + NO3 NO2 + O2 + NO (k2) | NO + N2O51 NO2 + NO2 + NO2 (K3)
→
Give the expression for the acceptable rate.
→
→
(A).
d[N205]
dt
==
2k,k₂[N₂O₂]
k₁+k₁₂
(B).
d[N2O5]
=-k₁[N₂O] + k₁[NO₂] [NO3] - k₂[NO₂]³
dt
(C).
d[N2O5]
=-k₁[N₂O] + k [NO] - k₂[NO] [NO]
d[N2O5]
(D).
=
dt
= -k₁[N2O5] - k¸[NO][N₂05]
dt
Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard
the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.
For the decomposition reaction of N2O5(g): 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed:
N2O5 NO2 + NO3 (K1) | NO2 + NO3 → N2O5 (k-1) | NO2 + NO3 NO2 + O2 + NO (k2) | NO + N2O51 NO2 + NO2 + NO2 (K3)
→
Give the expression for the acceptable rate.
→
→
(A).
d[N205]
dt
==
2k,k₂[N₂O₂]
k₁+k₁₂
(B).
d[N2O5]
=-k₁[N₂O] + k₁[NO₂] [NO3] - k₂[NO₂]³
dt
(C).
d[N2O5]
=-k₁[N₂O] + k [NO] - k₂[NO] [NO]
d[N2O5]
(D).
=
dt
= -k₁[N2O5] - k¸[NO][N₂05]
dt
Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard
the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.
R lactam or lactone considering as weak acid or weak base and why
Chapter 20 Solutions
Essential Organic Chemistry, Global Edition
Ch. 20.1 - Prob. 1PCh. 20.2 - Prob. 2PCh. 20.2 - Prob. 3PCh. 20.2 - Draw the structure of an optically active fat...Ch. 20.4 - Prob. 6PCh. 20.4 - Prob. 7PCh. 20.4 - The membrane phospholipids in deer have a higher...Ch. 20.4 - Prob. 9PCh. 20.6 - Prob. 10PCh. 20.6 - Prob. 11P
Ch. 20.6 - Prob. 12PCh. 20.7 - Propose a mechanism for the biosynthesis of...Ch. 20.7 - Prob. 14PCh. 20.8 - Draw the individual 1,2-hydride and 1,2-methyl...Ch. 20.9 - Prob. 16PCh. 20 - Prob. 17PCh. 20 - Prob. 18PCh. 20 - Cardiolipins are found in heart muscles. Draw the...Ch. 20 - Prob. 20PCh. 20 - 5-Androstene-3,17-dione is isomerized to...Ch. 20 - Prob. 22PCh. 20 - Prob. 23PCh. 20 - Prob. 24PCh. 20 - Eudesmol is a sesquiterpene found in eucalyptus....
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