EBK ORGANIC CHEMISTRY
8th Edition
ISBN: 8220102744127
Author: Bruice
Publisher: PEARSON
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Chapter 20, Problem 69P
Interpretation Introduction
Interpretation:
Whether
Concept Introduction:
Carbohydrates are made from carbon, oxygen and hydrogen atoms and the wide numbers of isomers exist for the carbohydrates because of the presence of chiral Carbon atoms.
Pyranose are the compounds that comprise six-membered ring made of one Oxygen and five Carbon atoms, whereas furanose is the carbohydrates that comprise five-membered ring made of one Oxygen and four carbon atoms.
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Q2: Write the structure of the product formed in each case
(A)
C6H₂CH₂CH₂C6H₁
H₂C=CHCCH₂
NaOCH,
CH₂OH
β-d-gulopyranose + hydrogen gas and a platinum catalyst.
Draw the organic products formed when attached compound is treated with H2, Pd-C. Indicate the three-dimensional structure of all stereoisomersformed.
Chapter 20 Solutions
EBK ORGANIC CHEMISTRY
Ch. 20.1 - Prob. 1PCh. 20.2 - Prob. 2PCh. 20.2 - Prob. 3PCh. 20.3 - Prob. 4PCh. 20.3 - Prob. 5PCh. 20.3 - Prob. 6PCh. 20.4 - Prob. 7PCh. 20.4 - Prob. 8PCh. 20.5 - Prob. 9PCh. 20.5 - Prob. 10P
Ch. 20.5 - Prob. 11PCh. 20.6 - Prob. 12PCh. 20.6 - Prob. 13PCh. 20.6 - Prob. 14PCh. 20.7 - Prob. 15PCh. 20.8 - Prob. 16PCh. 20.9 - Prob. 18PCh. 20.10 - Prob. 20PCh. 20.10 - Prob. 21PCh. 20.10 - Prob. 22PCh. 20.11 - Prob. 23PCh. 20.11 - Prob. 24PCh. 20.12 - Prob. 25PCh. 20.12 - Prob. 26PCh. 20.14 - Prob. 28PCh. 20.15 - Prob. 29PCh. 20.15 - Prob. 30PCh. 20.16 - Prob. 31PCh. 20.17 - Prob. 32PCh. 20.18 - Refer to Figure 20.5 to answer the following...Ch. 20 - Prob. 34PCh. 20 - Prob. 35PCh. 20 - Prob. 36PCh. 20 - Prob. 37PCh. 20 - Prob. 38PCh. 20 - Prob. 39PCh. 20 - Prob. 40PCh. 20 - Prob. 41PCh. 20 - Prob. 42PCh. 20 - Prob. 43PCh. 20 - Prob. 44PCh. 20 - Prob. 45PCh. 20 - Prob. 46PCh. 20 - Prob. 47PCh. 20 - Prob. 48PCh. 20 - The 1H NMR spectrum of D-glucose in D2O exhibits...Ch. 20 - Prob. 50PCh. 20 - Prob. 51PCh. 20 - Prob. 52PCh. 20 - Prob. 53PCh. 20 - Prob. 54PCh. 20 - Prob. 55PCh. 20 - Prob. 56PCh. 20 - Prob. 57PCh. 20 - Prob. 58PCh. 20 - Prob. 59PCh. 20 - Prob. 60PCh. 20 - Prob. 61PCh. 20 - A hexose is obtained when the residue of a shrub...Ch. 20 - Prob. 63PCh. 20 - Prob. 64PCh. 20 - Prob. 65PCh. 20 - Prob. 66PCh. 20 - Prob. 67PCh. 20 - Prob. 68PCh. 20 - Prob. 69PCh. 20 - Prob. 70PCh. 20 - Prob. 71PCh. 20 - Prob. 72PCh. 20 - Prob. 73P
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- The structural formula for the open-chain form of D-mannose is CH НО—С—Н Но-с—н Н—С—ОН Н—ҫ—ОН CH-OН (a) Is this molecule a sugar? (b) How many chiral carbons are present in the molecule? (c) Draw the structure of the six-member-ring form of this molecule.arrow_forwardDraw the following sugar derivatives. ) 2,3,4,6-tetra-O-methyl-d-mannopyranose(arrow_forwardQ2:Write the structure of the product formed in each case (A) C6H₂CH₂CCH₂C6H₁ H₂C=CHCCH3 NaOCH, CH₂OHarrow_forward
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- The most stable conformation of most aldopyranoses is one in which the largest group, the CH2OH group, is equatorial. However, alpha-D-idopyranose exists primarily in a conformation with an axial CH2OH group. Write formulas for the two chair conformations of a-D-idopyranose (one with the CH2OH group axial and one with the CH2OH group equatorial) and provide an explanationarrow_forwardIs C-O ester of 3-chloro-4’-methoxychalcone conjugated (talking about the H3CO attatched to the benzene ring)? Can you explain your answer?arrow_forwardb) Disaccharide E is a reducing sugar. It is hydrolyzed by an α-glycosidase enzyme, which means it contains an α- glycoside link. Treatment of E with Ag2O and excess Mel gives an octamethyl derivative F. Hydrolysis of F in dilute aqueous acid gives the pair of molecules shown below. Write the structures of E and F. (If the stereochemistry at a particular carbon is not determined by the above data, indicate this with a wavy line as shown below.) HO OMe OMe Is is MeO MeO MOH OMe mOH OMe OMearrow_forward
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