EBK ORGANIC CHEMISTRY
8th Edition
ISBN: 8220102744127
Author: Bruice
Publisher: PEARSON
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Question
Chapter 20, Problem 51P
Interpretation Introduction
Interpretation:
Compounds A, B, C and D are to be identified.
Concept Introduction:
The structural representation of sugar molecule in cyclic form is known as Haworth projection. Sugar molecule that has six-membered-ring is known as pyranose and sugar molecule that has five-membered-ring is called furanose. A sugar molecule in which hydroxyl groups of second last carbon atom is on left side is known as
The Wohl degradation is used in order to reduce the chain of an aldose by one carbon and Kiliani-Fischer synthesis is used to increase the chain length of an aldose sugar.
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Arrange the solutions in order of increasing acidity. (Note that K (HF) = 6.8 x 10 and K (NH3) = 1.8 × 10-5)
Rank solutions from least acidity to greatest acidity. To rank items as equivalent, overlap them.
▸ View Available Hint(s)
Least acidity
NH&F NaBr NaOH
NH,Br NaCIO
Reset
Greatest acidity
1. Consider the following molecular-level diagrams of a titration.
O-HA molecule
-Aion
°°
о
°
(a)
о
(b)
(c)
(d)
a. Which diagram best illustrates the microscopic representation for the
EQUIVALENCE POINT in a titration of a weak acid (HA) with sodium.
hydroxide?
(e)
Answers to the remaining 6 questions will be hand-drawn on paper and submitted as a single
file upload below:
Review of this week's reaction:
H₂NCN (cyanamide) + CH3NHCH2COOH (sarcosine) + NaCl, NH4OH, H₂O --->
H₂NC(=NH)N(CH3)CH2COOH (creatine)
Q7. Draw by hand the reaction of creatine synthesis listed above using line structures without showing
the Cs and some of the Hs, but include the lone pairs of electrons wherever they apply. (4 pts)
Q8. Considering the Zwitterion form of an amino acid, draw the Zwitterion form of Creatine. (2 pts)
Q9. Explain with drawing why the C-N bond shown in creatine structure below can or cannot rotate. (3
pts)
NH2(C=NH)-N(CH)CH2COOH
This bond
Q10. Draw two tautomers of creatine using line structures. (Note: this question is valid because problem
Q9 is valid). (4 pts)
Q11. Mechanism. After seeing and understanding the mechanism of creatine synthesis, students should
be ready to understand the first half of one of the Grignard reactions presented in a past…
Chapter 20 Solutions
EBK ORGANIC CHEMISTRY
Ch. 20.1 - Prob. 1PCh. 20.2 - Prob. 2PCh. 20.2 - Prob. 3PCh. 20.3 - Prob. 4PCh. 20.3 - Prob. 5PCh. 20.3 - Prob. 6PCh. 20.4 - Prob. 7PCh. 20.4 - Prob. 8PCh. 20.5 - Prob. 9PCh. 20.5 - Prob. 10P
Ch. 20.5 - Prob. 11PCh. 20.6 - Prob. 12PCh. 20.6 - Prob. 13PCh. 20.6 - Prob. 14PCh. 20.7 - Prob. 15PCh. 20.8 - Prob. 16PCh. 20.9 - Prob. 18PCh. 20.10 - Prob. 20PCh. 20.10 - Prob. 21PCh. 20.10 - Prob. 22PCh. 20.11 - Prob. 23PCh. 20.11 - Prob. 24PCh. 20.12 - Prob. 25PCh. 20.12 - Prob. 26PCh. 20.14 - Prob. 28PCh. 20.15 - Prob. 29PCh. 20.15 - Prob. 30PCh. 20.16 - Prob. 31PCh. 20.17 - Prob. 32PCh. 20.18 - Refer to Figure 20.5 to answer the following...Ch. 20 - Prob. 34PCh. 20 - Prob. 35PCh. 20 - Prob. 36PCh. 20 - Prob. 37PCh. 20 - Prob. 38PCh. 20 - Prob. 39PCh. 20 - Prob. 40PCh. 20 - Prob. 41PCh. 20 - Prob. 42PCh. 20 - Prob. 43PCh. 20 - Prob. 44PCh. 20 - Prob. 45PCh. 20 - Prob. 46PCh. 20 - Prob. 47PCh. 20 - Prob. 48PCh. 20 - The 1H NMR spectrum of D-glucose in D2O exhibits...Ch. 20 - Prob. 50PCh. 20 - Prob. 51PCh. 20 - Prob. 52PCh. 20 - Prob. 53PCh. 20 - Prob. 54PCh. 20 - Prob. 55PCh. 20 - Prob. 56PCh. 20 - Prob. 57PCh. 20 - Prob. 58PCh. 20 - Prob. 59PCh. 20 - Prob. 60PCh. 20 - Prob. 61PCh. 20 - A hexose is obtained when the residue of a shrub...Ch. 20 - Prob. 63PCh. 20 - Prob. 64PCh. 20 - Prob. 65PCh. 20 - Prob. 66PCh. 20 - Prob. 67PCh. 20 - Prob. 68PCh. 20 - Prob. 69PCh. 20 - Prob. 70PCh. 20 - Prob. 71PCh. 20 - Prob. 72PCh. 20 - Prob. 73P
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