The product obtained from the reaction of D-ribose with one equivalent of methanol and HCl is to be predicted. Concept Introduction: The hydroxyl group of anomeric carbon is protonated by an acid. The lone pair on the ring helps in eliminating a molecule of water which results in the formation of oxocarbenium ion. It is planar molecule. When the alcohol approaches from the top of the plane, the β -glycoside is formed. When the alcohol approaches from the bottom of plane, the α -glycoside is formed.

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Answer 1

Question

Chapter 20, Problem 40P

Interpretation Introduction

Interpretation:

The product obtained from the reaction of D-ribose with one equivalent of methanol and HCl is to be predicted.

Concept Introduction:

The hydroxyl group of anomeric carbon is protonated by an acid. The lone pair on the ring helps in eliminating a molecule of water which results in the formation of oxocarbenium ion. It is planar molecule. When the alcohol approaches from the top of the plane, the β-glycoside is formed. When the alcohol approaches from the bottom of plane, the α-glycoside is formed.

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Answer 2

Question

Chapter 20, Problem 40P

Interpretation Introduction

Interpretation:

The product obtained from the reaction of D-ribose with one equivalent of methanol and HCl is to be predicted.

Concept Introduction:

The hydroxyl group of anomeric carbon is protonated by an acid. The lone pair on the ring helps in eliminating a molecule of water which results in the formation of oxocarbenium ion. It is planar molecule. When the alcohol approaches from the top of the plane, the β-glycoside is formed. When the alcohol approaches from the bottom of plane, the α-glycoside is formed.

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Answer 3

Question

Chapter 20, Problem 40P

Interpretation Introduction

Interpretation:

The product obtained from the reaction of D-ribose with one equivalent of methanol and HCl is to be predicted.

Concept Introduction:

The hydroxyl group of anomeric carbon is protonated by an acid. The lone pair on the ring helps in eliminating a molecule of water which results in the formation of oxocarbenium ion. It is planar molecule. When the alcohol approaches from the top of the plane, the β-glycoside is formed. When the alcohol approaches from the bottom of plane, the α-glycoside is formed.

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Answer 4

Question

Chapter 20, Problem 40P

Interpretation Introduction

Interpretation:

The product obtained from the reaction of D-ribose with one equivalent of methanol and HCl is to be predicted.

Concept Introduction:

The hydroxyl group of anomeric carbon is protonated by an acid. The lone pair on the ring helps in eliminating a molecule of water which results in the formation of oxocarbenium ion. It is planar molecule. When the alcohol approaches from the top of the plane, the β-glycoside is formed. When the alcohol approaches from the bottom of plane, the α-glycoside is formed.

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Answer 5

Chapter 20, Problem 40P

Interpretation Introduction

Interpretation:

The product obtained from the reaction of D-ribose with one equivalent of methanol and HCl is to be predicted.

Concept Introduction:

The hydroxyl group of anomeric carbon is protonated by an acid. The lone pair on the ring helps in eliminating a molecule of water which results in the formation of oxocarbenium ion. It is planar molecule. When the alcohol approaches from the top of the plane, the β-glycoside is formed. When the alcohol approaches from the bottom of plane, the α-glycoside is formed.

Answer 6

Chapter 20, Problem 40P

Interpretation Introduction

Interpretation:

The product obtained from the reaction of D-ribose with one equivalent of methanol and HCl is to be predicted.

Concept Introduction:

The hydroxyl group of anomeric carbon is protonated by an acid. The lone pair on the ring helps in eliminating a molecule of water which results in the formation of oxocarbenium ion. It is planar molecule. When the alcohol approaches from the top of the plane, the β-glycoside is formed. When the alcohol approaches from the bottom of plane, the α-glycoside is formed.

Answer 7

Chapter 20, Problem 40P

Interpretation Introduction

Interpretation:

The product obtained from the reaction of D-ribose with one equivalent of methanol and HCl is to be predicted.

Concept Introduction:

The hydroxyl group of anomeric carbon is protonated by an acid. The lone pair on the ring helps in eliminating a molecule of water which results in the formation of oxocarbenium ion. It is planar molecule. When the alcohol approaches from the top of the plane, the β-glycoside is formed. When the alcohol approaches from the bottom of plane, the α-glycoside is formed.

Answer 8

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Answer 10

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Answer 11

Ch. 20.1 - Prob. 1P Ch. 20.2 - Prob. 2P Ch. 20.2 - Prob. 3P Ch. 20.3 - Prob. 4P Ch. 20.3 - Prob. 5P Ch. 20.3 - Prob. 6P Ch. 20.4 - Prob. 7P Ch. 20.4 - Prob. 8P Ch. 20.5 - Prob. 9P Ch. 20.5 - Prob. 10P

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