EBK ORGANIC CHEMISTRY
8th Edition
ISBN: 8220102744127
Author: Bruice
Publisher: PEARSON
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Question
Chapter 20, Problem 48P
Interpretation Introduction
Interpretation:
The two possible structures for the
Concept Introduction:
The Wohl-degradation is opposite of the Killiani-Fisher synthesis. It shortens an aldoses chain by one carbon. Hexoses are converted to pentoses and pentoses are converted to tetroses.
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An unknown β-d-aldohexose has only one axial substituent. A Wohl degradation forms a compound which, when treated with sodium borohydride, forms an optically active alditol. This information allows you to arrive at two possible structures for the β-d-aldohexose. What experiment can you carry out to distinguish between the two possibilities?
d-Xylose and d-lyxose are formed when d-threose undergoes a Kiliani–Fischer synthesis. d-Xylose is oxidized to an optically inactive aldaric acid,whereas d-lyxose forms an optically active aldaric acid. What are the structures of d-xylose and d-lyxose?
When an optically active D-aldopentose was subjected to Kiliani-Fischer synthesis,
followed by NaBH4/H2O, it produced a mixture of an optically active and an
optically inactive alditol. When the same D-aldopentose was subjected to Wohl
degradation followed by HNO3 it produced an optically inactive aldaric acid. Provide
the structure of this D-aldopentose.
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Н-
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CH₂OH
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A) 1
B) II
C) III
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D) IV
НО
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-OH H-
H HỌ
CH₂OH
П
-OH H
-OH H
Н
-H
CH₂OH
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-OH HO
-OH H-
-OH H-
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-H
-OH
CH₂OH
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-OH
CH₂OH
V
Chapter 20 Solutions
EBK ORGANIC CHEMISTRY
Ch. 20.1 - Prob. 1PCh. 20.2 - Prob. 2PCh. 20.2 - Prob. 3PCh. 20.3 - Prob. 4PCh. 20.3 - Prob. 5PCh. 20.3 - Prob. 6PCh. 20.4 - Prob. 7PCh. 20.4 - Prob. 8PCh. 20.5 - Prob. 9PCh. 20.5 - Prob. 10P
Ch. 20.5 - Prob. 11PCh. 20.6 - Prob. 12PCh. 20.6 - Prob. 13PCh. 20.6 - Prob. 14PCh. 20.7 - Prob. 15PCh. 20.8 - Prob. 16PCh. 20.9 - Prob. 18PCh. 20.10 - Prob. 20PCh. 20.10 - Prob. 21PCh. 20.10 - Prob. 22PCh. 20.11 - Prob. 23PCh. 20.11 - Prob. 24PCh. 20.12 - Prob. 25PCh. 20.12 - Prob. 26PCh. 20.14 - Prob. 28PCh. 20.15 - Prob. 29PCh. 20.15 - Prob. 30PCh. 20.16 - Prob. 31PCh. 20.17 - Prob. 32PCh. 20.18 - Refer to Figure 20.5 to answer the following...Ch. 20 - Prob. 34PCh. 20 - Prob. 35PCh. 20 - Prob. 36PCh. 20 - Prob. 37PCh. 20 - Prob. 38PCh. 20 - Prob. 39PCh. 20 - Prob. 40PCh. 20 - Prob. 41PCh. 20 - Prob. 42PCh. 20 - Prob. 43PCh. 20 - Prob. 44PCh. 20 - Prob. 45PCh. 20 - Prob. 46PCh. 20 - Prob. 47PCh. 20 - Prob. 48PCh. 20 - The 1H NMR spectrum of D-glucose in D2O exhibits...Ch. 20 - Prob. 50PCh. 20 - Prob. 51PCh. 20 - Prob. 52PCh. 20 - Prob. 53PCh. 20 - Prob. 54PCh. 20 - Prob. 55PCh. 20 - Prob. 56PCh. 20 - Prob. 57PCh. 20 - Prob. 58PCh. 20 - Prob. 59PCh. 20 - Prob. 60PCh. 20 - Prob. 61PCh. 20 - A hexose is obtained when the residue of a shrub...Ch. 20 - Prob. 63PCh. 20 - Prob. 64PCh. 20 - Prob. 65PCh. 20 - Prob. 66PCh. 20 - Prob. 67PCh. 20 - Prob. 68PCh. 20 - Prob. 69PCh. 20 - Prob. 70PCh. 20 - Prob. 71PCh. 20 - Prob. 72PCh. 20 - Prob. 73P
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- Carbohydrates a. Compound Z is an aldopentose. If Z is oxidized with nitric acid the product is optically active. If Z undergoes one Ruff degradation and the product of that degradation is reduced to the alditol using H₂/Ni the resulting product is optically inactive. If compound Z undergoes two Ruff degradations, D-glyceraldehyde (shown below) is obtained. Draw the usual Fischer projection of Z (aldehyde at the top). (Hint: work backwards from D- glyceraldehyde.) H HIC OH CH₂OH D-Glyceraldehydearrow_forwardcan you please add an explanation.arrow_forwardThe 1H NMR spectrum of d-glucose in D2O exhibits two high-frequency doublets. What is responsible for these doublets?arrow_forward
- Choose the product that is expected when the β-pyranose form of compound A is treated with excess ethyl iodide in the presence of silver oxide. The following information can be used to determine the identity of compound A: 1. The molecular formula of compound A is C6H12O6.2. Compound A is a reducing sugar.3. When compound A is subjected to a Wohl degradation two times sequentially, D-erythrose is obtained.4. Compound A is epimeric with D-glucose at C3.5. The configuration at C2 is R.arrow_forwardList all possible D-2-ketohexoses. One of these D-2-ketohexoses is called sorbose. When sorbose is treated with sodium borohydride it produces a mixture of glucitol and iditol. What is the structure of sorbose? Another D-2-ketohexose, psychosa produces a mixture of alitol and altritol when reduced with sodium borohydride, which is the structure of psychosearrow_forwardA hexose was obtained after (+)-glyceraldehyde underwent three successive Kiliani–Fischer syntheses. Identify the hexose from the following experimental information: oxidation with nitric acid forms an optically active aldaric acid; a Wohl degradation followed by oxidation with nitric acid forms an optically inactive aldaric acid; and a second Wohl degradation forms erythrose.arrow_forward
- The most stable conformation of the pyranose ring of most D-aldohexoses places the largest group, CH2OH, in the equatorial position. An exception to this is the aldohexose D-idose. Draw the two possible chair conformations of either the a or B anomer of D-idose. Explain why the more stable conformation has the CH2OH group in the axial position.arrow_forwardNAIME H 1) Compound X consists of an aldopentose. If X is oxidized with nitric acid, the product is then optically active. If X undergoes one Ruff degradation and the product of that degradation is reduced to the alditol using H₂/Ni the resulting product is optically inactive. If compound X undergoes two Ruff degradations, D-glyceraldehyde (below) is obtained. Draw the usual Fischer projection of X (aldehyde at the top). (Hint: work backward from D- glyceraldehyde.) C10 Organic Chemistry 2: Homework assignment H-C-OH Carbohydrates CH₂OH D-Glyceraldehydearrow_forwardGive the full biochemical name for an L-ketohexose with the following pattern of chiral centers: carbon #3 = L, carbon #4 = D.arrow_forward
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