
Concept explainers
Referring to the previous problem, find the volume of the displaced air.

The displaced volume of air.
Answer to Problem 63A
The volume of displaced air is
Explanation of Solution
Given:
The buoyant force acting on the balloon is equal to the weight of the displaced air.
The weight of the displaced air in the balloon is
Formula used:
The buoyant force acting on the balloon is given as follows:
Here,
Rearrange the equation for
Calculation:
The buoyant force acting on the balloon will be equal to the displaced air weight.
The balloon is neither accelerating upward nor downward, so the net force acting on it will be zero. The upward buoyant force will be equal to the weight of the balloon including the hot air. Therefore, the weight of the displaced air in the balloon is
Substitute
Conclusion:
Therefore, the volume of displaced air is
Chapter 20 Solutions
Conceptual Physics: The High School Physics Program
Additional Science Textbook Solutions
Biology: Life on Earth with Physiology (11th Edition)
Biology: Life on Earth (11th Edition)
Campbell Biology: Concepts & Connections (9th Edition)
Campbell Biology (11th Edition)
Human Anatomy & Physiology (2nd Edition)
Microbiology: An Introduction
- Mick and Rick are twins born on Earth in the year 2175. Rick grows up to be an Earth-bound robotics technician while Mick becomes an intergalactic astronaut. Mick leaves the Earth on his first space mission in the year 2200 and travels, according to his clock, for 10 years at a speed of 0.75c. Unfortunately, at this point in his journey, the structure of his ship undergoes mechanical breakdown and the ship explodes. How old is Rick when his brother dies?arrow_forwardHi, I have canceled, why did you charge me again?arrow_forwardNo chatgpt pls will upvotearrow_forward
- For each of the actions depicted below, a magnet and/or metal loop moves with velocity v→ (v→ is constant and has the same magnitude in all parts). Determine whether a current is induced in the metal loop. If so, indicate the direction of the current in the loop, either clockwise or counterclockwise when seen from the right of the loop. The axis of the magnet is lined up with the center of the loop. For the action depicted in (Figure 5), indicate the direction of the induced current in the loop (clockwise, counterclockwise or zero, when seen from the right of the loop). I know that the current is clockwise, I just dont understand why. Please fully explain why it's clockwise, Thank youarrow_forwardA planar double pendulum consists of two point masses \[m_1 = 1.00~\mathrm{kg}, \qquad m_2 = 1.00~\mathrm{kg}\]connected by massless, rigid rods of lengths \[L_1 = 1.00~\mathrm{m}, \qquad L_2 = 1.20~\mathrm{m}.\]The upper rod is hinged to a fixed pivot; gravity acts vertically downward with\[g = 9.81~\mathrm{m\,s^{-2}}.\]Define the generalized coordinates \(\theta_1,\theta_2\) as the angles each rod makes with thedownward vertical (positive anticlockwise, measured in radians unless stated otherwise).At \(t=0\) the system is released from rest with \[\theta_1(0)=120^{\circ}, \qquad\theta_2(0)=-10^{\circ}, \qquad\dot{\theta}_1(0)=\dot{\theta}_2(0)=0 .\]Using the exact nonlinear equations of motion (no small-angle or planar-pendulumapproximations) and assuming the rods never stretch or slip, determine the angle\(\theta_2\) at the instant\[t = 10.0~\mathrm{s}.\]Give the result in degrees, in the interval \((-180^{\circ},180^{\circ}]\).arrow_forwardWhat are the expected readings of the ammeter and voltmeter for the circuit in the figure below? (R = 5.60 Ω, ΔV = 6.30 V) ammeter I =arrow_forward
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningLecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-WesleyCollege Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON





