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An unknown compound A (molecular formula
in
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- When compound A (C5H12O) is treated with HBr, it forms compound B (C5H11Br). The 1H NMR spectrum of compound A has a 1H singlet, a 3H doublet, a 6H doublet, and two 1H multiplets. The 1H NMR spectrum of compound B has a 6H singlet, a 3H triplet, and a 2H quartet. Identify compounds A and B.arrow_forwardCompound A has molecular formula C7H15B.. Treatment of compound A with sodium ethoxide yields only one elimination product (compound B) and no substitution products. When compound B is treated with dilute sulfuric acid, compound C is obtained, which has molecular formula C7H160. Draw the structures of compounds A, B, and C.arrow_forwardCompound X (molecular formula C10H12O) was treated with NH2NH2,−OH to yield compound Y (molecular formula C10H14). Based on the 1H NMR spectra of X and Y given below, what are the structures of X and Y?arrow_forward
- Compound X has the molecular formula C10H12O. The IR spectrum of X has a strong band near 1710 cm-1. Compound X forms a phenyhydrazone, but gives a negative Tollens’ test and a positive iodoform test. What is the structure of the compound?arrow_forwardIdentify the structure of compound C (molecular formula C11H15NO2), which has an IR absorption at 1699 cm−1 and the 1H NMR spectrum shown below.arrow_forwardCompound A has molecular formula C8H8O. Its 1H-NMR spectrum shows a singlet of integral 3 at 2.58 ppm and a multiplet of integral 5 at 7.84 ppm. Its 13C-NMR shows six signals. The IR spectrum of A shows a noteworthy stretch at 1698 cm-1. - Identify Compound A, explaining your reasoning Compound A is treated with a mixture of nitric and sulfuric acids to generate Compound B. The 1H-NMR spectrum of B shows three singlets, one at 2.52 pm of integral 3, one at 6.67 ppm of integral 1, and one at 7.94 ppm of integral 2. The 13C-NMR spectrum of B shows six signals. - Identify compound B, explaining your reasoning Compound B is treated with methylmagnesium bromide and then aqueous acid to generate compound C. The 1H-NMR spectrum of C shows four singlets, one at 1.42 ppm of integral 6, one at 2.3 ppm of integral 1, one at 8.52 ppm of integral 2, and one at 8.97 ppm of integral 1. The 13C-NMR spectrum of C shows six signals. The IR spectrum of C shows a noteworthy broad stretch at 3326 cm-1. -…arrow_forward
- Identify the structure of compound C (molecular formula C11H15NO2),which has an IR absorption at 1699 cm−1 and the 1H NMR spectrumshown below.arrow_forwardA solution of acetone [(CH3)2C=O] in ethanol (CH3CH2OH) in the presence of a trace of acid was allowed to stand for several days, and a new compound of molecular formula C7H16O2 was formed. The IR spectrum showed only one major peak in the functional group region around 3000 cm−1, and the 1H NMR spectrum is given here. What is the structure of the product?arrow_forwardCompound B of molecular formula C9H19N shows a noteworthy infrared absorption at 3300 cm-1. Its 1H-NMR spectrum shows three singlets – δ 1.0 (6H), 1.1 (12H), 1.4 (1H) ppm. Its 13C-NMR spectrum has four signals – δ 25, 28, 41, 64 ppm. Suggest a structure for this compound.arrow_forward
- Propose a structure of compound C (molecular formula C10H12O) consistent with the following data. C is partly responsible for the odor and flavor of raspberries. Compound C: IR absorption at 1717 cm–1arrow_forwardAn unknown compound C (molecular formula C4H8O3) exhibits IR absorptions at 3600–2500 and 1734 cm–1, as well as the following 1H NMR spectrum. What is the structure of C?arrow_forwardThree isomeric compounds, A, B, and C, all have molecular formula C8H11N. The 1H NMR and IR spectral data of A, B, and C are given below. What are their structures?arrow_forward