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The stereochemistry of the products of reduction depends on the reagent used, as you learned in Sections 20.5 and 20.6. With this in mind, how would you convert
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- A compound with formula C7H12O is treated with sodium borohydride in methanol to yield 2,2-dimethylcylopentanol. Write a reaction scheme showing the structures of the reactant, the reagents, and the product. Will the product be optically active? Explain.arrow_forwardDraw the two major organic products of the reaction in ether. Show the stereochemistry of the products. Are the products single enantiomers or racemic mixtures?arrow_forwardCr(VI) compounds are common reagents for the oxidation of alcohols. Primary alcohols are oxidized to carboxylic acids and secondary alcohols are oxidized to ketones. The mechanism involves a reaction similar to the E2 elimination, whereby a C=O double bond is formed with a reduced Cr(IV) compound as the leaving group.Draw curved arrows to show the movement of electrons in this step of the mechanism.arrow_forward
- #1077 of Paperchasel Compound A is treated with H₂SO4 to produce compound B which decolourises bromine in CCl4 Compound B is treated with cold, dilute KMnO4 to produce compound C. If compound A has the molecular formula C6H₁2O then: Select one: O a. B could be 1-hexene and C could be 1,2-hexanediol b. A could be cyclohexanol and B could be cyclohexane O c. A could be cyclohexanone and B could be cyclohexene O d. A could be cyclohexanol and C could be 1,2-cyclohexanediol e. B could be cyclohexene and C could be cyclohexanol #1444 of AromaticDirectors Which of the following are meta directing and deactivating substituents in aromatic electrophilic substitution reactions? 2) Br 3) OH 4) OR 5) NHCOR 1) CI Select one: 1), 2) and 3) O b. all of the above c. 1), 4) and 5) d. none of the above e. 3), 4), 5) and 6) a. 6) methylarrow_forwardName the following using IUPAC system of nomenclature: (a) CH2 (Cl) CH (NH2) CHO (b) CH3 C (Br) CH2 CH (F) COOH Brarrow_forward(a) Draw the two isomeric dienes formed when CH2 = CHCH2CH(Cl)CH(CH3)2 is treated with an alkoxide base, (b) Explain why the major product formed in this reaction does not contain the more highly substituted alkene.arrow_forward
- (ii) Name the following using IUPAC system of nomenclature: (a) CH2 (Cl) CH (NH2) CHO (b) CH3 C (Br) CH2 CH (F) COOH Brarrow_forwardWhen the conjugate acid of aniline, C6H5NH3+, reacts with the acetate ion, the following reaction takes place: C6H5NH3+(aq)+CH3COO(aq)C6H5NH2(aq)+CH3COOH(aq) If Kafor C6H5NH3+ is 1.35105 and Kafor CH3COOH is 1.86105 , what is K for the reaction?arrow_forwardDraw the formulas of the reactants and products of the reaction: 2-ethylbutanoyl bromide with excess ethylmagnesium bromide and heating the product with concentrated H2SO4.arrow_forward
- 3,4-Dimethylpent-1-ene has the formula CH2“CH¬CH(CH3)¬CH(CH3)2. When pure (R)-3,4-dimethylpent-1-ene is treated with hydrogen over a platinum catalyst, the product is (S)-2,3-dimethylpentane. The reactant is named (R), but the product is named (S). Does this name change imply a change in the spatial arrangement of the groups around the chiral center? So why does the name switch from (R) to (S)?arrow_forwardReaction of (CH3)3CH with Cl2 forms two products: (CH3)2CHCH2Cl (63%) and (CH3)3CCl (37%). Why is the major product formed by cleavage of the stronger 1° C–H bond?arrow_forwardThe substitution reaction below forms two ehters (which are consitutional isomers). Please draw the structures of the 2 ethers formed. Are the ethers single enantiomers or racemic mixtures?arrow_forward
- Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning