(a)
Interpretation:
The synthesis of diene has to be shown from cyclopentanone and acetylene.
Concept introduction:
Dehydration reaction:
Removal of water molecule from the reaction when the alcohol is treated with strong acid like sulfuric acid.
Alcohol is reaction with concentrated sulfuric acid, first alcohol gets protonated forms carbocation (more stable carbocation) followed by elimination of proton (
Tertiary carbocation is more stable than the secondary, secondary carbocation is more stable than primary.
In dehydration reaction, sulfuric acid is act as a proton donor, and which is used to protonate the alcohol and makes carbocation therefore sulfuric acid is the driving force of the reaction. Dehydration reaction will not go without acid (sulfuric acid).
Hydrogenation:
Palladium on carbon (Pd/C) or Pd/ CaCO3 is used as a catalyst for hydrogenation of
(b)
Interpretation:
Stereochemistry of the dicarboxylic acid has to be rationalized.
Concept introduction:
Chiral:
A molecule is non superimposable on its mirror image is called chiral molecule.
Four different atoms attached to a carbon atom is called chiral molecule.
Isomer: A molecule having the same molecular formula but with different chemical structure is called isomer.
Stereoisomers: Stereoisomers are molecules that have the same molecular formula and they differ only in arrangement of atom in three-dimensional space.
Enantiomers: A compound which is non-superimposable mirror image is called enantiomers.
Diastereomers: A compound which is non-superimposable and non-mirror image is called diastereomers.
Racemic mixture: A racemic mixture is simply a mixture containing an equal amount of each enantiomer.
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Organic Chemistry
- (a) How will you carry out the following conversions?(i) Acetylene to Acetic acid (ii) Toluene to m-nitrobenzoic acid(iii) Ethanol to Acetone(b) Give reasons :(i) Chloroacetic acid is stronger than acetic acid.(ii) pH of reaction should be carefully controlled while preparing ammonia derivatives of carbonyl compounds.arrow_forwardExplain the following behaviours :(i) Alcohols are more soluble in water than the hydrocarbons of comparable molecular masses.(ii) Ortho-nitrophenol is more acidic than ortho-methoxyphenol.arrow_forwardFuran undergoes electrophilic aromatic substitution more readily than benzene; mild reagents and conditions are sufficient.For example, furan reacts with bromine to give 2-bromofuran.(a) Propose mechanisms for the bromination of furan at the 2-position and at the 3-position. Draw the resonance forms ofeach sigma complex, and compare their stabilities.(b) Explain why furan undergoes bromination (and other electrophilic aromatic substitutions) primarily at the 2-position.O Br O123furan 2-bromofuranarrow_forward
- (a) Give a mechanism for this reaction, showing how the two products arise as aconsequence of the resonance-stabilized intermediate.(b) The bromination of cyclohexene using NBS gives only one major product, as shown onthe previous page. Explain why there is no second product from an allylic shift.arrow_forwardWrite the structure of the major organic product formed in the reaction of 1-pentene with each of the following: (a) Hydrogen chloride (b) Dilute sulfuric acid (c) Diborane in diglyme, followed by basic hydrogen peroxide (d) Bromine in carbon tetrachloride (e) Bromine in water (f) Peroxyacetic acid (g) Ozone (h) Product of part (g) treated with zinc and water (i) Product of part (g) treated with dimethyl sulfide (CH3)2Sarrow_forwardAlkenes can be converted to alcohols by hydroboration-oxidation. (a) Draw the structure of the alcohol or alcohols formed in the reaction sequence. Clearly indicate stereochemistry by drawing a wedged bond, a dashed bond and two in-plane bonds per each chiral carbon. Draw hydrogen atoms that are connected to wedge-and-dash bonds.(b) Characterize the product or products of the reactions. Be sure to draw hydrogens on oxygen, where applicable. Select Draw Rings More Erase C 1. B2H6, diglyme (a) 2. H2O2, HO¯, H2Oarrow_forward
- Alkenes can be converted to alcohols by hydroboration-oxidation. (a) Draw the structure of the alcohol or alcohols formed in the reaction sequence. Clearly indicate stereochemistry by drawing a wedged bond, a dashed bond and two in-plane bonds per each chiral carbon. Draw hydrogen atoms that are connected to wedge-and-dash bonds.(b) Characterize the product or products of the reactions. Be sure to draw hydrogens on oxygen, where applicable. Select Draw Rings More Erase H 1. B,H§, diglyme (a) 2. H2O2, HO", H2Oarrow_forwardAlkenes can be converted to alcohols by hydroboration-oxidation. (a) Draw the structure of the alcohol or alcohols formed in the reaction sequence. Clearly indicate stereochemistry by drawing a wedged bond, a dashed bond and two in-plane bonds per each chiral carbon. Draw hydrogen atoms that are connected to wedge-and-dash bonds.(b) Characterize the product or products of the reactions. Be sure to draw hydrogens on oxygen, where applicable. 1. B2H6, diglyme (a) 2. H202, HO¯, H20 OH OH H. Incorrect MacBook Proarrow_forwardAlkenes can be converted to alcohols by hydroboration-oxidation. (a) Draw the structure of the alcohol or alcohols formed in the reaction sequence. Clearly indicate stereochemistry by drawing a wedged bond, a dashed bond and two in-plane bonds per each chiral carbon. Draw hydrogen atoms that are connected to wedge-and-dash bonds.(b) Characterize the product or products of the reactions. Be sure to draw hydrogens on oxygen, where applicable. H 1. B2H6. diglyme (a) H 2. H2O2, HO-, H20 он OH Incorrectarrow_forward
- Alkenes can be converted to alcohols by hydroboration-oxidation. (a) Draw the structure of the alcohol or alcohols formed in the reaction sequence. Clearly indicate stereochemistry by drawing a wedged bond, a dashed bond and two in-plane bonds per each chiral carbon. Draw hydrogen atoms that are connected to wedge-and-dash bonds.(b) Characterize the product or products of the reactions. Be sure to draw hydrogens on oxygen, where applicable. Select Draw Rings More Erase H 1. B₂H6, (a) diglyme 2. H2O2, HOT, H₂O ✓ C O Q2 Qarrow_forward(a) Explain how pyrrole is isoelectronic with the cyclopentadienyl anion.(b) Specifically, what is the difference between the cyclopentadienyl anion and pyrrole?(c) Draw resonance forms to show the charge distribution on the pyrrole structure.arrow_forwardThe following compound, 2-hydroxycycloheptatrienone, does not give all the usual carbonyl group reactions. (i) Explain this apparent anomaly. Furthermore, explain the significant difference between the relative stability of this compound and its 3- and 4-hydroxy isomers. (ii) What would you expect to be the influence of adding (a) a nitro group as a substituent on the 7-membered ring or (b) an alkyl group, on the degree of aromaticity of the above compound. (iii) Based on your understanding of the hydrogen bonding concept, which isomer would you expect to have a higher m.p, (assuming they are both solids) between 2- and 4- hydroxycycloheptatrienone? Explain your choice.arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning