The given reaction equation has to be balanced. Concept introduction: Balanced equation: A balanced chemical equation is an equation which contains same elements in same number on both the sides (reactant and product side) of the chemical equation thereby obeying the law of conservation of mass. The equation for a reaction, which has same number of atoms and charge of the ions in both reactants and product sides, is known as balanced equation.
The given reaction equation has to be balanced. Concept introduction: Balanced equation: A balanced chemical equation is an equation which contains same elements in same number on both the sides (reactant and product side) of the chemical equation thereby obeying the law of conservation of mass. The equation for a reaction, which has same number of atoms and charge of the ions in both reactants and product sides, is known as balanced equation.
Science that deals with the amount of energy transferred from one equilibrium state to another equilibrium state.
Chapter 20, Problem 20.107P
(a)
Interpretation Introduction
Interpretation:
The given reaction equation has to be balanced.
Concept introduction:
Balanced equation: A balanced chemical equation is an equation which contains same elements in same number on both the sides (reactant and product side) of the chemical equation thereby obeying the law of conservation of mass.
The equation for a reaction, which has same number of atoms and charge of the ions in both reactants and product sides, is known as balanced equation.
(b)
Interpretation Introduction
Interpretation:
For respiration reaction 1.00g of glucose, the standard free energy ΔGrxno value should be calculated.
Concept introduction:
Free energy (Gibbs free energy) is the term that is used to explain the total energy content in a thermodynamic system that can be converted into work. The free energy is represented by the letter G. All spontaneous process is associated with the decrease of free energy in the system. The standard free energy change (ΔG°rxn) is the difference in free energy of the reactants and products in their standard state.
ΔG°rxn=∑nΔGf°(Products)-∑nΔGf°(Reactants)
(c)
Interpretation Introduction
Interpretation:
For fermentation reaction of 1.00g glucose, the standard free energy ΔGrxno value should be calculated.
Concept introduction:
Free energy (Gibbs free energy) is the term that is used to explain the total energy content in a thermodynamic system that can be converted into work. The free energy is represented by the letter G. All spontaneous process is associated with the decrease of free energy in the system. The standard free energy change (ΔG°rxn) is the difference in free energy of the reactants and products in their standard state.
ΔG°rxn=∑nΔGf°(Products)-∑nΔGf°(Reactants)
(d)
Interpretation Introduction
Interpretation:
For oxidation reaction of 1.00g glucose, the standard free energy ΔGrxno value should be calculated.
Concept introduction:
Free energy (Gibbs free energy) is the term that is used to explain the total energy content in a thermodynamic system that can be converted into work. The free energy is represented by the letter G. All spontaneous process is associated with the decrease of free energy in the system. The standard free energy change (ΔG°rxn) is the difference in free energy of the reactants and products in their standard state.
Q2: Label the following molecules as chiral or achiral, and label each stereocenter as R or S.
CI
CH3
CH3
NH2
C
CH3
CH3
Br
CH3
X
&p
Bra
'CH 3
"CH3
X
Br
CH3
Me - N
OMe
O
DuckDuck
1. For the four structures provided, Please answer the following questions in the table
below.
a. Please draw π molecular orbital diagram (use the polygon-and-circle method if
appropriate) and fill electrons in each molecular orbital
b. Please indicate the number of π electrons
c. Please indicate if each molecule provided is anti-aromatic, aromatic, or non-
aromatic
TT MO diagram
Number of π e-
Aromaticity Evaluation (X choose one)
Non-aromatic
Aromatic
Anti-aromatic
||
|||
+
IV
1.3 grams of pottasium iodide is placed in 100 mL of o.11 mol/L lead nitrate solution. At room temperature, lead iodide has a Ksp of 4.4x10^-9. How many moles of precipitate will form?
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Calorimetry Concept, Examples and Thermochemistry | How to Pass Chemistry; Author: Melissa Maribel;https://www.youtube.com/watch?v=nSh29lUGj00;License: Standard YouTube License, CC-BY