For the hydrolysis of ATP process, the K value should be founded at 37 o C . Concept introduction: Free energy (Gibbs free energy ) is the term that is used to explain the total energy content in a thermodynamic system that can be converted into work. The free energy is represented by the letter G . All spontaneous process is associated with the decrease of free energy in the system. The standard free energy change (ΔG ° rxn ) is the difference in free energy of the reactants and products in their standard state. ΔG ° rxn = ∑ nΔG f ° (Products)- ∑ nΔG f ° (Reactants) Free energy change ΔG : change in the free energy takes place while reactants convert to product where both are in standard state. It depends on the equilibrium constant K ΔG = ΔG o + RT ln ( K ) ΔG o =- RT ln ( K ) Where, T is the temperature ΔG is the free energy ΔG o , ΔH o and ΔS o is standard free energy, enthalpy and entropy values.
For the hydrolysis of ATP process, the K value should be founded at 37 o C . Concept introduction: Free energy (Gibbs free energy ) is the term that is used to explain the total energy content in a thermodynamic system that can be converted into work. The free energy is represented by the letter G . All spontaneous process is associated with the decrease of free energy in the system. The standard free energy change (ΔG ° rxn ) is the difference in free energy of the reactants and products in their standard state. ΔG ° rxn = ∑ nΔG f ° (Products)- ∑ nΔG f ° (Reactants) Free energy change ΔG : change in the free energy takes place while reactants convert to product where both are in standard state. It depends on the equilibrium constant K ΔG = ΔG o + RT ln ( K ) ΔG o =- RT ln ( K ) Where, T is the temperature ΔG is the free energy ΔG o , ΔH o and ΔS o is standard free energy, enthalpy and entropy values.
Science that deals with the amount of energy transferred from one equilibrium state to another equilibrium state.
Chapter 20, Problem 20.100P
(a)
Interpretation Introduction
Interpretation:
For the hydrolysis of ATP process, the K value should be founded at 37oC.
Concept introduction:
Free energy (Gibbs free energy) is the term that is used to explain the total energy content in a thermodynamic system that can be converted into work. The free energy is represented by the letter G. All spontaneous process is associated with the decrease of free energy in the system. The standard free energy change (ΔG°rxn) is the difference in free energy of the reactants and products in their standard state.
ΔG°rxn=∑nΔGf°(Products)-∑nΔGf°(Reactants)
Free energy changeΔG: change in the free energy takes place while reactants convert to product where both are in standard state. It depends on the equilibrium constant K
ΔG =ΔGo+RTln(K)ΔGo=- RTln(K)
Where,
T is the temperature
ΔG is the free energy
ΔGo, ΔHo and ΔSo is standard free energy, enthalpy and entropy values.
(b)
Interpretation Introduction
Interpretation:
For the metabolism of 1mol glucose, the ΔGrxno value should be founded.
Concept introduction:
Free energy (Gibbs free energy) is the term that is used to explain the total energy content in a thermodynamic system that can be converted into work. The free energy is represented by the letter G. All spontaneous process is associated with the decrease of free energy in the system. The standard free energy change (ΔG°rxn) is the difference in free energy of the reactants and products in their standard state.
ΔG°rxn=∑mΔGf°(Products)-∑nΔGf°(Reactants)
Where,
nΔGf°(Reactants) is the standard entropy of the reactants
mΔGf°(products) is the standard free energy of the products
(c)
Interpretation Introduction
Interpretation:
How many moles of ATP are produced by phosphorylation in glycolysis of 1 mole of glucose should be determined.
Concept introduction:
Moles: One mole is equivalent to the mass of the substance consists same number of units equal to the atoms present in 12g of 12C.
From given mass of substance moles could be calculated by using the following formula,
Molar mass: It is obtained by dividing the mass of substance with the amount of substance and the S.I. unit of molar mass is kg/mol. It is numerically equal to the molecular weight since molecular weight is sum of all individual atom weight present in molecule which is represented in amu.
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.