
Concept explainers
For a specific application, the circuit shown in Fig. 2.140 was designed so that IL = 83.33 mA and that Rin = 5 kΩ. What are the values of R1 and R2?
Figure 2.140

Calculate the values of
Answer to Problem 81CP
The values of
Explanation of Solution
Given Data:
Refer to Figure 2.140 in the textbook for the given circuit.
Formula used:
Consider the expression for
Here,
Consider the expression for
Calculation:
Modify Figure 2.140 as shown in Figure 1.
In Figure 1,
Therefore,
From Figure 1, write the expression for equivalent resistance
Substitute
To maintain
Modify the Figure as shown in Figure 2.
Therefore from current division rule, the current through
From current division rule, write the expression for current
Substitute
Rearrange the equation as follows.
Simplify the equation as follows.
Simplify the equation as follows.
Substitute
Simplify the equation as follows.
Simplify the equation to obtain the value of
Conclusion:
Thus, the values of
Want to see more full solutions like this?
Chapter 2 Solutions
EBK FUNDAMENTALS OF ELECTRIC CIRCUITS
- Q2 but when you get to part 3, can you please draw it outarrow_forwardplease solve manually. I need the drawing and the values too. Thank you!arrow_forwardTwo alternators, Y-connected 6.6 kV supply a load of 3000 kW at 0.8 p.f lagging. The synchronous mpedance of first alternator is (0.5+j10) Q/ph and second alternator is (0.4+j12) /ph. First alternator delivers 150 amp at 0.875 lag p.f. The two alterators are shared load equally. Determine the current, p.f., induced e.m.f, load angel, and maximum developed power of each alternator?arrow_forward
- A domestic load of 2300 kW at 0.88 p.f lagging and a motors load of 3400 kW at 0.85 p.f lagging are supplied by two alternators operating in parallel. If one alternator is delivering a load of 3300 kW at 0.9 p.f lagging, what will be the output power and p.f of the other alternator?arrow_forwardDetermine the value of Rr that necessary for the circuit in Fig.(2) to operate as an oscillator and then determine the frequency of oscillation. 0.001 F 0.001 F 0.001 F R₁ • 10 ΚΩ R₁ 10 k R • 10 ΚΩarrow_forward(a) For the circuit shown in Figure Q3(a) (RFC and Cc are forbias) (i) (ii) Draw the AC small signal equivalent circuit of the oscillator. From this equivalent circuit derive an equation for fo and the gain condition for the oscillations to start. VDD www RG eee RFC H Cc 北 5 C₁ L 000 C₂ Voarrow_forward
- Please solve this question step by step handwritten solution and do not use chat gpt or any ai toolsfor part ii) you may need to use nodal analysisarrow_forward12.1. Find the steady-state response vo (t) for the network. 00000- 1Ω ww 12 cos(t) V + www 202 1 H 202 1 F + 1Ω νο -arrow_forwardA Three-phase, 12 pole, Y-connected alternator has 108 slots and 14 conductors per slot. The windings are (5/6 th) pitched. The flux per pole is 57 mWb distributed sinusoidally over the pole. If the machine runs at 500 r.p.m., determine the following: (a) The frequency of the generated e.m.f., (b) The distribution factor, (c) The pitch factor, and (d) The phase and line values of the generated e.m.f.?arrow_forward
- Two 3-ph, 6.6 kV, Y-connected, alternators supply a load of 3000 kW at 0.8 p.f. lagging. The synchronou impedance per phase of machine A is (0.5+110) and that of machine B is (0.4 +J12) . The excitation of machine A adjusted so that it delivers 150 A. The load is shared equally between the machines. Determine the armature curre p.f., induced e.m.f., and load angle of each machine?arrow_forwardName the circuit below? The output voltage is initially zero and the pulse width is 200 μs. Find the Vout and draw the output waveform? +2.5 V V 247 -2.5 V C 0.01 F Ri W 10 ΚΩarrow_forwardPlease work outarrow_forward
- Introductory Circuit Analysis (13th Edition)Electrical EngineeringISBN:9780133923605Author:Robert L. BoylestadPublisher:PEARSONDelmar's Standard Textbook Of ElectricityElectrical EngineeringISBN:9781337900348Author:Stephen L. HermanPublisher:Cengage LearningProgrammable Logic ControllersElectrical EngineeringISBN:9780073373843Author:Frank D. PetruzellaPublisher:McGraw-Hill Education
- Fundamentals of Electric CircuitsElectrical EngineeringISBN:9780078028229Author:Charles K Alexander, Matthew SadikuPublisher:McGraw-Hill EducationElectric Circuits. (11th Edition)Electrical EngineeringISBN:9780134746968Author:James W. Nilsson, Susan RiedelPublisher:PEARSONEngineering ElectromagneticsElectrical EngineeringISBN:9780078028151Author:Hayt, William H. (william Hart), Jr, BUCK, John A.Publisher:Mcgraw-hill Education,





