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A barge is pulled by the two tugboats shown in the following figure. One tugboat pulls on the barge with a force of magnitude 4000 units of force at
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- In a tug-of-war game on one campus, 15 students pull on a rope at both ends in an effort to displace the central knot to one side or the other. Two students pull with force 196 N each to the light, four students pull with force 98 N each to the left, five students pull with force 62 N each to the left, three students pull with force 150 N each to the right, and one student pulls with force 250 N to the left. Assuming the positive direction to the tight, express the net pull on the knot in terms of the unit vector. How big is the net pull on the knot? In what direction?arrow_forwardConsider the three displacement vectors A=(3i3j)m, B=(i4j)m, and C=(2i+5j)m. Use the component method to determine (a) the magnitude and direction of the vector D=A+B+C and (b) the magnitude and direction of E=AB+C.arrow_forwardA vector points from the origin into the second quadrant of the xy plane. What can you conclude about its components? (a) Both components are positive. (b) The x component is positive, and the y component is negative. (c) The x component is negative, and the y component is positive. (d) Both components are negative. (e) More than one answer is possible.arrow_forward
- For the two vectors find A − B and |A – B| component of B along A angle between A and B A × B (A − B) × (A + B)arrow_forwardA Three vectors all have the same magnitude. The symbol for the magnitude of each of these vectors is M. The first vector A points in the positive x direction. The second vector B points in the negative y direction. The third vector C points in the positive z direction. These three vectors added together are equal to a fourth vector D. What is the magnitude of the fourth vector?arrow_forwardA force F, of magnitude 5.60 units acts at the origin in a direction 26.0° above the positive x axis. A second force F, of magnitude 5.00 units acts at the origin in the direction of the positive y axis. Find graphically the magnitude and direction of the resultant force F, + F,. magnitude units direction ° counterclockwise from the +x axis ITa F, Farrow_forward
- A force F, of magnitude 7.00 units acts at the origin in a direction 31.0° above the positive x axis. A second force F, of magnitude 5.00 units acts at the origin in the direction of the positive y axis. Find graphically the magnitude and direction of the resultant force F, + F,. magnitude units direction ° counterclockwise from the +x axisarrow_forwardAs you will see in a later chapter, forces are vector quantities, and the total force on an object is the vector sum of all forces acting on it. In the figure below, a force F, of magnitude 6.70 units acts on a crate at the origin in a direction 0 = 26.0° above the positive x-axis. A second force F, of magnitude 5.00 units acts on the crate in the direction of the positive y-axis. Find graphically the magnitude and direction (in degrees counterclockwise from the +x-axis) of the resultant force F, + F,. magnitude units direction Counterciockwise from the +x-axisarrow_forwardTwo forces of magnitude 70 newtons (N) and 50 N act on an object at angles of 30° and - 45° with the positive x-axis as shown in the figure. Find the direction and magnitude of the resultant force; that is, find F₁+F₂. C F₁+F₂ = (35√3+25√√2 )i + (35-25√2)j (Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.) 30° 45° |||F₁ || = = 70 N ||F₂||= = 50 N Xarrow_forward
- Three forces act on a point. The forces are represented by colored arrows. The orange force is 10 N @ 105o; the blue force is 8 N @ 210o; and the green force is 15 N @ 315o. Express the net force on that point in both unit vector notation and polar notation.arrow_forwardOften a vector is specified by a magnitude and a direction; for example, a rope with tension T exerts a force of magnitude T=20 N in a direction 0 = 35° north of east. This is a good way to think of vectors; however, to calculate results with vectors, it is best to select a coordinate system and manipulate the components of the vectors in that coordinate system. B length = aA length b Find the components of the vector A with length a = 1.00 and angle a=20.0 ° with respect to the x axis Enter numerically, separated by a comma, the x component followed by the y component. Find the components of the vector B with length b = 1.00 and angle B=20.0 ° with respect to the x axis Enter numerically, separated by a comma, the x component followed by the y component. Find the components of the vector C with length c = 1.00 and angle o = 35.0 ° Enter numerically, separated by a comma, the x component followed by the y component. length =carrow_forwardJuanito is pulling a cart with 15.00-N force due 20.00 degrees North of West. Find a vector of equal length perpendicular to the force exerted by Juanito . Let the force exerted by Juanito be , and the force perpendicular to that force be . The vector makes an angle of degrees with respect to the positive x-axis. Subtracting 90 degrees from that standard angle, should be due degrees north of east. Since we know that the magnitude of is equal to that of and we also know the angle of , we can calculate the components of which results to: = +arrow_forward
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