Interpretation:
Among
Concept Introduction:
Molecular orbital diagram is a linear combination of atomic orbitals of similar energy and similar symmetry. It is formed by the proper overlap of the atomic orbitals.
There are 3 types of molecular orbitals as follows:
1. Bonding molecular orbital: They are formed by the constructive interference of atomic orbitals and electrons in it stabilize the molecule and are of lesser in energy.
2. Antibonding molecular orbital: This type of orbitals increases the energy of molecule and destabilizes it and weakens the bond between the atoms.
3. Non-bonding molecular orbital: These types of orbitals have energy similar to atomic orbitals that is addition or removal of electron does not change the energy of molecule.
The order of energy in molecular orbital follows two rules as follows:
1. For
2. For atomic number more than 14 order of energy is,
Electron affinity is the energy released when electron is added to gaseous atom or molecule to give negative ion.
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ACHIEVE/CHEMICAL PRINCIPLES ACCESS 1TERM
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- Please help me figure out what the slope is and how to calculate the half life Using the data provided.arrow_forwardCurved arrows are used to illustrate the flow of electrons. Follow the curved arrows and draw the structure of the missing reactants, intermediates, or products in the following mechanism. Include all lone pairs. Ignore stereochemistry. Ignore inorganic byproducts. H Br2 (1 equiv) H- Select to Draw Starting Alkene Draw Major Product I I H2O 四: ⑦.. Q Draw Major Charged Intermediate Iarrow_forwardNH (aq)+CNO (aq) → CO(NH2)2(s) Experiment [NH4] (M) [CNO] (M) Initial rate (M/s) 1 0.014 0.02 0.002 23 0.028 0.02 0.008 0.014 0.01 0.001 Calculate the rate contant for this reaction using the data provided in the table.arrow_forward
- 2CIO2 + 20H-1 CIO31 + CIO2 + H2O Experiment [CIO2], M [OH-1], M 1 0.0500 0.100 23 2 0.100 0.100 3 0.100 0.0500 Initial Rate, M/s 0.0575 0.230 0.115 ... Given this date, calculate the overall order of this reaction.arrow_forward2 3 .(be)_[Ɔ+(be)_OI ← (b²)_IƆO+ (be)_I Experiment [1-] M 0.005 [OCI-] 0.005 Initial Rate M/min 0.000275 0.0025 0.005 0.000138 0.0025 0.0025 0.000069 4 0.0025 0.0025 0.000140 Calculate the rate constant of this reaction using the table data.arrow_forward1 2 3 4 I(aq) +OCl(aq) → IO¯¯(aq) + Cl¯(aq) Experiment [I-] M 0.005 [OCI-] 0.005 Initial Rate M/min 0.000275 0.0025 0.005 0.000138 0.0025 0.0025 Calculate the overall order of this reaction using the table data. 0.0025 0.000069 0.0025 0.000140arrow_forward
- General Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage Learning