COMPUTER SCIENCE ILLUMIN.-TEXT
7th Edition
ISBN: 9781284156010
Author: Dale
Publisher: Jones & Barlett
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Chapter 2, Problem 28E
Program Plan Intro
a.
Binary numbers:
- Binary number is a number which is expressed in base-2 numeral system or binary numeral system.
- It uses only two symbols zero and one.
- It is mainly used by all modern computers and computer based devices.
- Each digit in binary numeral system is referred to as bit.
Octal numbers:
- Octal number system is a base-8 number system and it has the digits from 0 to 7.
- It can be made from binary numerals by grouping consecutive binary digits into groups of three starting from the right.
- Octal number system provides a simple method to convert large binary numbers into smaller groups.
Explanation of Solution
b.
Conversion of binary number 1000001 into octal number:
- Here, the given binary number is 1000001.
- Separate every three digits from right to left...
Explanation of Solution
c.
Conversion of binary number 10000010 into octal number:
- Here, the given binary number is 10000010.
- Separate every three digits from right to left...
Explanation of Solution
d.
Conversion of binary number 1100010 into octal number:
- Here, the given binary number is 1100010.
- Separate every three digits from right to left...
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D. S. Malik, Data Structures Using C++, 2nd Edition, 2010
Methods (Ch6) - Review
1. (The MyRoot method) Below is a manual implementation of the Math.sqrt() method in Java.
There are two methods, method #1 which calculates the square root for positive integers, and
method #2, which calculates the square root of positive doubles (also works for integers).
public class SquareRoot {
public static void main(String[] args) {
}
// implement a loop of your choice here
// Method that calculates the square root of integer variables
public static double myRoot(int number) {
double root;
root=number/2;
double root old;
do {
root old root;
root (root_old+number/root_old)/2;
} while (Math.abs(root_old-root)>1.8E-6);
return root;
}
// Method that calculates the square root of double variables
public static double myRoot(double number) {
double root;
root number/2;
double root_old;
do {
root old root;
root (root_old+number/root_old)/2;
while (Math.abs (root_old-root)>1.0E-6);
return root;
}
}
Program-it-Yourself: In the main method, create a program that…
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Chapter 2 Solutions
COMPUTER SCIENCE ILLUMIN.-TEXT
Ch. 2 - Prob. 1ECh. 2 - Prob. 2ECh. 2 - Prob. 3ECh. 2 - Prob. 4ECh. 2 - Prob. 5ECh. 2 - Prob. 6ECh. 2 - Prob. 7ECh. 2 - Prob. 8ECh. 2 - Prob. 9ECh. 2 - Prob. 10E
Ch. 2 - Prob. 11ECh. 2 - Prob. 12ECh. 2 - Prob. 13ECh. 2 - Prob. 14ECh. 2 - Prob. 15ECh. 2 - Prob. 16ECh. 2 - Prob. 17ECh. 2 - Prob. 18ECh. 2 - Prob. 19ECh. 2 - Prob. 20ECh. 2 - Prob. 21ECh. 2 - Prob. 22ECh. 2 - Prob. 23ECh. 2 - Prob. 24ECh. 2 - Prob. 25ECh. 2 - Prob. 26ECh. 2 - Prob. 27ECh. 2 - Prob. 28ECh. 2 - Prob. 29ECh. 2 - Prob. 30ECh. 2 - Prob. 31ECh. 2 - Prob. 32ECh. 2 - Prob. 33ECh. 2 - Prob. 34ECh. 2 - Prob. 35ECh. 2 - Prob. 36ECh. 2 - Prob. 38ECh. 2 - Prob. 39ECh. 2 - Prob. 40ECh. 2 - Prob. 41ECh. 2 - Prob. 42ECh. 2 - Prob. 43ECh. 2 - Prob. 44ECh. 2 - Prob. 45ECh. 2 - Prob. 46ECh. 2 - Prob. 47ECh. 2 - Prob. 1TQCh. 2 - Prob. 2TQCh. 2 - Prob. 3TQCh. 2 - Prob. 4TQ
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