
COMPUTER SCIENCE ILLUMIN.-TEXT
7th Edition
ISBN: 9781284156010
Author: Dale
Publisher: Jones & Barlett
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Question
Chapter 2, Problem 31E
Program Plan Intro
a.
Octal numbers:
- Octal number system is also known as base 8 number system and uses the digits 0 to 7.
- These are made from binary numerals by grouping consecutive binary digits into three groups starting from the right.
- Octal numbers also makes it easy to write large binary numbers into smaller groups.
Hexadecimal numbers:
- Hexadecimal number system is a number system which consists of 16 digits and it is also known as base 16 number system.
- It consists of 10 digits from 0 to 9 and 6 letters from A to F.
- Hexadecimal makes it easy to write large binary numbers into smaller groups.
- It generally uses four bit binary coding.
Explanation of Solution
b.
Conversion of octal number 605 into hexadecimal value:
- Here the given octal value is 605.
- First convert the octal value 605 into its equivalent binary value. Hence the binary equivalent is 110000101.
- Separate four digits from right to left...
Explanation of Solution
c.
Conversion of octal number 443 into hexadecimal number:
- Here the given octal value is 443.
- First convert the octal value 443 into its equivalent binary value. Hence the binary equivalent is 100100011
- Separate four digits from right to left...
Explanation of Solution
d.
Conversion of octal number 521 into hexadecimal number:
- Here the given octal value is 521.
- First convert the octal value 521 into its equivalent binary value. Hence the binary equivalent is 101010001.
- Separate four digits from right to left...
Explanation of Solution
e.
Conversion of octal number 1 into hexadecimal number:
- Here the given octal value is 1.
- First convert the octal value 1 into its equivalent binary value. Hence the binary equivalent is 001.
- Separate four digits from right to left...
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Chapter 2 Solutions
COMPUTER SCIENCE ILLUMIN.-TEXT
Ch. 2 - Prob. 1ECh. 2 - Prob. 2ECh. 2 - Prob. 3ECh. 2 - Prob. 4ECh. 2 - Prob. 5ECh. 2 - Prob. 6ECh. 2 - Prob. 7ECh. 2 - Prob. 8ECh. 2 - Prob. 9ECh. 2 - Prob. 10E
Ch. 2 - Prob. 11ECh. 2 - Prob. 12ECh. 2 - Prob. 13ECh. 2 - Prob. 14ECh. 2 - Prob. 15ECh. 2 - Prob. 16ECh. 2 - Prob. 17ECh. 2 - Prob. 18ECh. 2 - Prob. 19ECh. 2 - Prob. 20ECh. 2 - Prob. 21ECh. 2 - Prob. 22ECh. 2 - Prob. 23ECh. 2 - Prob. 24ECh. 2 - Prob. 25ECh. 2 - Prob. 26ECh. 2 - Prob. 27ECh. 2 - Prob. 28ECh. 2 - Prob. 29ECh. 2 - Prob. 30ECh. 2 - Prob. 31ECh. 2 - Prob. 32ECh. 2 - Prob. 33ECh. 2 - Prob. 34ECh. 2 - Prob. 35ECh. 2 - Prob. 36ECh. 2 - Prob. 38ECh. 2 - Prob. 39ECh. 2 - Prob. 40ECh. 2 - Prob. 41ECh. 2 - Prob. 42ECh. 2 - Prob. 43ECh. 2 - Prob. 44ECh. 2 - Prob. 45ECh. 2 - Prob. 46ECh. 2 - Prob. 47ECh. 2 - Prob. 1TQCh. 2 - Prob. 2TQCh. 2 - Prob. 3TQCh. 2 - Prob. 4TQ
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