COMPUTER SCIENCE ILLUMIN.-TEXT
7th Edition
ISBN: 9781284156010
Author: Dale
Publisher: Jones & Barlett
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Chapter 2, Problem 34E
Program Plan Intro
a.
Decimal number:
- A decimal number is a number in which the whole number part and the fractional part is separated by a decimal point.
- The dot is known as a decimal point of a decimal number.
- Hence decimal numbering system is a method for representing both integer and non-integer numbers.
Hexadecimal number:
- Hexadecimal number system is a positional number system with a radix or base of 16.
- These are widely used by computer
system designers and programmers. - Each hexadecimal digit represents four binary digits which is also known as nibble.
- Hexadecimal numbers are 0-9 and letters A-F.
Explanation of Solution
b.
Conversion of decimal number 1939 into hexadecimal value:
- Divide 1939 by 16 and it returns 121 as quotient and 3 as remainder.
- Divide 121 by 16 and it returns 7 as quotient and 9 as remainder.
- Divide 7 by 16 and it is not possible as 7 is less than 16...
Explanation of Solution
c.
Conversion of decimal number 1 into hexadecimal value:
- Divide number 1 by 16. It is not possible as 1 is less than 16...
Explanation of Solution
d.
Conversion of decimal number 998 into hexadecimal value:
- Divide 998 by 16 and it returns 62 as quotient and 6 as remainder.
- Divide 62 by 16 and it returns 3 as quotient and 14 as remainder. The corresponding hexadecimal value for 14 is E...
Explanation of Solution
e.
Conversion of decimal number 43 into hexadecimal value:
- Divide 43 by 16 and it returns 2 as quotient and 11 as remainder. The corresponding hexadecimal value for 11 is B.
- Divide 2 by 16 and it is not possible as 2 is less than 16...
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I need help fixing the minor issue where the text isn't in the proper place, and to ensure that the frequency cutoff is at the right place.
My code:
% Define frequency range for the plot
f = logspace(1, 5, 500); % Frequency range from 10 Hz to 100 kHz
w = 2 * pi * f; % Angular frequency
% Parameters for the filters - let's adjust these to get more reasonable cutoffs
R = 1e3; % Resistance in ohms (1 kΩ)
C = 1e-6; % Capacitance in farads (1 μF)
% For bandpass, we need appropriate L value for desired cutoffs
L = 0.1; % Inductance in henries - adjusted for better bandpass response
% Calculate cutoff frequencies first to verify they're in desired range
f_cutoff_RC = 1 / (2 * pi * R * C);
f_resonance = 1 / (2 * pi * sqrt(L * C));
Q_factor = (1/R) * sqrt(L/C);
f_lower_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) + 1/(2*Q_factor));
f_upper_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) - 1/(2*Q_factor));
% Transfer functions
% Low-pass filter (RC)
H_low = 1 ./ (1 + 1i * w *…
Chapter 2 Solutions
COMPUTER SCIENCE ILLUMIN.-TEXT
Ch. 2 - Prob. 1ECh. 2 - Prob. 2ECh. 2 - Prob. 3ECh. 2 - Prob. 4ECh. 2 - Prob. 5ECh. 2 - Prob. 6ECh. 2 - Prob. 7ECh. 2 - Prob. 8ECh. 2 - Prob. 9ECh. 2 - Prob. 10E
Ch. 2 - Prob. 11ECh. 2 - Prob. 12ECh. 2 - Prob. 13ECh. 2 - Prob. 14ECh. 2 - Prob. 15ECh. 2 - Prob. 16ECh. 2 - Prob. 17ECh. 2 - Prob. 18ECh. 2 - Prob. 19ECh. 2 - Prob. 20ECh. 2 - Prob. 21ECh. 2 - Prob. 22ECh. 2 - Prob. 23ECh. 2 - Prob. 24ECh. 2 - Prob. 25ECh. 2 - Prob. 26ECh. 2 - Prob. 27ECh. 2 - Prob. 28ECh. 2 - Prob. 29ECh. 2 - Prob. 30ECh. 2 - Prob. 31ECh. 2 - Prob. 32ECh. 2 - Prob. 33ECh. 2 - Prob. 34ECh. 2 - Prob. 35ECh. 2 - Prob. 36ECh. 2 - Prob. 38ECh. 2 - Prob. 39ECh. 2 - Prob. 40ECh. 2 - Prob. 41ECh. 2 - Prob. 42ECh. 2 - Prob. 43ECh. 2 - Prob. 44ECh. 2 - Prob. 45ECh. 2 - Prob. 46ECh. 2 - Prob. 47ECh. 2 - Prob. 1TQCh. 2 - Prob. 2TQCh. 2 - Prob. 3TQCh. 2 - Prob. 4TQ
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