Explanation Given: Inverting op-amp adder circuit is presented. The value of the voltages applied at the inverting terminals is V 1 and V 2 respectively. The input and the output are related by V 0 = − ( V 1 + 3 V 2 ) − − − > ( 1 ) Calculation: The circuit diagram of an inverting op-amp summer is shown in Figure 1. Figure 1 The expression of the output voltage for the circuit given in Figure 1 can be expressed as V 0 = − ( R F R 1 × V 1 + R F R 2 × V 2 ) − − − > ( 2 ) From equation (1) and (2), the following can be concluded: R F R 1 = 1 = > R 1 = R F − − − > ( 3 ) R F R 2 = 3 = > R 2 = R F 3 − − − > ( 4 ) Using the superposition principle, initially let us consider the voltage V 2 = 0 . Under this condition, the following can be obtained: V 0 V 1 = − R F R 1 1 + j f f t ( 1 + R F R 1 ) − − − > ( 5 ) The 3 -dB frequency f b is defined as f b = f t ( 1 + R F R 1 ) − − − > ( 6 )

Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition

7th Edition

ISBN: 9780199339136

Author: Adel S. Sedra, Kenneth C. Smith

Publisher: Oxford University Press

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Operational Amplifier

An operational amplifier also called op amp is an integrated circuit or analog circuit that takes input as a differential voltage and produces output as a single-ended voltage. It is an IC that can amplify weak electric signals.An op amp has one output p…

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Chapter 2, Problem 2.120P

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The values of the 3-dB frequency fb in terms of ft for gain functions V0V1 and V0V2 .

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Chapter 2, Problem 2.119P

Chapter 2, Problem 2.121P

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Q2: (30 Marks) Design a DC/DC converter that produce output waveforms that shown in figures below from a fixed DC source of 20 volts. Vo (Volt) 14.1 IL (Amp) 13.9 2.25 1.75 † (msec) Output voltage 0.18 0.2 t (msec) L 0.214 0.22 Output current

6. Build the circuit shown in Figure 2 below in PSpice. Note that the power supply V1 is a VSIN power supply in the SOURCE library. Vcc is a VDC supply found in the SOURCE library. Model this circuit using the Time Domain (Transient) Analysis Type with a Run To Time of 2 ms. A. Paste your output graph showing the voltage at the base terminal, collector terminal and at the load. B. What is the voltage gain of the circuit? (Compare the voltage amplitude at the base terminal input (across Rb2) to that at the collector terminal. C. What happens to the output voltage at the collector terminal if the value of Rb1 is reduced by a factor of 10 (to 14.7 kn)? Simulate this situation and explain the result. D. What happens to the output voltage at the collector terminal if the value of Rb1 is increased by a factor of 3 (to 441 k)? Simulate this situation and explain the result. Rb1 RC 147k 1k C2 C1 Q1 Vcc 1u VOFF = 0 Q2N3904 10Vdc VAMPL = 0.1V1 1u FREQ = 2k R_load Rb2 Re AC = 0 250 40k 20 Figure…

Chapter 2 Solutions

Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition

Ch. 2.1 - Prob. 2.1E Ch. 2.1 - Prob. 2.2E Ch. 2.1 - Prob. 2.3E Ch. 2.2 - Prob. D2.4E Ch. 2.2 - Prob. 2.5E Ch. 2.2 - Prob. 2.6E Ch. 2.2 - Prob. D2.7E Ch. 2.2 - Prob. D2.8E Ch. 2.3 - Prob. 2.9E Ch. 2.3 - Prob. 2.10E

Ch. 2.3 - Prob. D2.11E Ch. 2.3 - Prob. 2.12E Ch. 2.3 - Prob. 2.13E Ch. 2.3 - Prob. 2.14E Ch. 2.4 - Prob. 2.15E Ch. 2.4 - Prob. D2.16E Ch. 2.4 - Prob. 2.17E Ch. 2.5 - Prob. 2.18E Ch. 2.5 - Prob. D2.19E Ch. 2.5 - Prob. D2.20E Ch. 2.6 - Prob. 2.21E Ch. 2.6 - Prob. 2.22E Ch. 2.6 - Prob. 2.23E Ch. 2.6 - Prob. 2.24E Ch. 2.6 - Prob. 2.25E Ch. 2.7 - Prob. 2.26E Ch. 2.7 - Prob. 2.27E Ch. 2.7 - Prob. 2.28E Ch. 2.8 - Prob. 2.29E Ch. 2.8 - Prob. 2.30E Ch. 2 - Prob. 2.1P Ch. 2 - Prob. 2.2P Ch. 2 - Prob. 2.3P Ch. 2 - Prob. 2.4P Ch. 2 - Prob. 2.5P Ch. 2 - Prob. 2.6P Ch. 2 - Prob. 2.7P Ch. 2 - Prob. 2.8P Ch. 2 - Prob. 2.9P Ch. 2 - Prob. 2.10P Ch. 2 - Prob. 2.11P Ch. 2 - Prob. D2.12P Ch. 2 - Prob. D2.13P Ch. 2 - Prob. D2.14P Ch. 2 - Prob. 2.15P Ch. 2 - Prob. 2.16P Ch. 2 - Prob. 2.17P Ch. 2 - Prob. 2.18P Ch. 2 - Prob. 2.19P Ch. 2 - Prob. D2.20P Ch. 2 - Prob. 2.21P Ch. 2 - Prob. 2.22P Ch. 2 - Prob. 2.23P Ch. 2 - Prob. 2.24P Ch. 2 - Prob. 2.25P Ch. 2 - Prob. D2.26P Ch. 2 - Prob. 2.27P Ch. 2 - Prob. 2.28P Ch. 2 - Prob. D2.29P Ch. 2 - Prob. 2.30P Ch. 2 - Prob. 2.31P Ch. 2 - Prob. 2.32P Ch. 2 - Prob. D2.33P Ch. 2 - Prob. D2.34P Ch. 2 - Prob. D2.35P Ch. 2 - Prob. 2.36P Ch. 2 - Prob. D2.37P Ch. 2 - Prob. D2.38P Ch. 2 - Prob. D2.39P Ch. 2 - Prob. D2.40P Ch. 2 - Prob. D2.41P Ch. 2 - Prob. D2.42P Ch. 2 - Prob. 2.43P Ch. 2 - Prob. D2.44P Ch. 2 - Prob. D2.45P Ch. 2 - Prob. D2.46P Ch. 2 - Prob. D2.47P Ch. 2 - Prob. D2.48P Ch. 2 - Prob. 2.49P Ch. 2 - Prob. 2.50P Ch. 2 - Prob. D2.51P Ch. 2 - Prob. D2.52P Ch. 2 - Prob. 2.53P Ch. 2 - Prob. 2.54P Ch. 2 - Prob. 2.55P Ch. 2 - Prob. D2.56P Ch. 2 - Prob. 2.57P Ch. 2 - Prob. 2.58P Ch. 2 - Prob. 2.59P Ch. 2 - Prob. 2.60P Ch. 2 - Prob. D2.61P Ch. 2 - Prob. 2.62P Ch. 2 - Prob. 2.63P Ch. 2 - Prob. 2.64P Ch. 2 - Prob. 2.65P Ch. 2 - Prob. 2.66P Ch. 2 - Prob. D2.67P Ch. 2 - Prob. 2.68P Ch. 2 - Prob. D2.69P Ch. 2 - Prob. 2.70P Ch. 2 - Prob. D2.71P Ch. 2 - Prob. 2.72P Ch. 2 - Prob. 2.73P Ch. 2 - Prob. 2.74P Ch. 2 - Prob. 2.75P Ch. 2 - Prob. D2.76P Ch. 2 - Prob. 2.77P Ch. 2 - Prob. 2.78P Ch. 2 - Prob. 2.79P Ch. 2 - Prob. D2.80P Ch. 2 - Prob. 2.81P Ch. 2 - Prob. D2.82P Ch. 2 - Prob. D2.83P Ch. 2 - Prob. 2.84P Ch. 2 - Prob. 2.85P Ch. 2 - Prob. D2.86P Ch. 2 - Prob. 2.87P Ch. 2 - Prob. 2.88P Ch. 2 - Prob. 2.89P Ch. 2 - Prob. 2.90P Ch. 2 - Prob. 2.91P Ch. 2 - Prob. D2.92P Ch. 2 - Prob. D2.93P Ch. 2 - Prob. 2.94P Ch. 2 - Prob. 2.95P Ch. 2 - Prob. 2.96P Ch. 2 - Prob. 2.97P Ch. 2 - Prob. 2.98P Ch. 2 - Prob. D2.99P Ch. 2 - Prob. D2.100P Ch. 2 - Prob. 2.101P Ch. 2 - Prob. 2.102P Ch. 2 - Prob. 2.103P Ch. 2 - Prob. 2.104P Ch. 2 - Prob. 2.105P Ch. 2 - Prob. 2.106P Ch. 2 - Prob. 2.107P Ch. 2 - Prob. 2.108P Ch. 2 - Prob. 2.109P Ch. 2 - Prob. 2.110P Ch. 2 - Prob. 2.111P Ch. 2 - Prob. 2.112P Ch. 2 - Prob. 2.113P Ch. 2 - Prob. 2.114P Ch. 2 - Prob. 2.115P Ch. 2 - Prob. D2.116P Ch. 2 - Prob. D2.117P Ch. 2 - Prob. D2.118P Ch. 2 - Prob. 2.119P Ch. 2 - Prob. 2.120P Ch. 2 - Prob. 2.121P Ch. 2 - Prob. 2.122P Ch. 2 - Prob. 2.123P Ch. 2 - Prob. 2.124P Ch. 2 - Prob. 2.125P Ch. 2 - Prob. 2.126P Ch. 2 - Prob. D2.127P

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The values of the 3 -dB frequency f b in terms of f t for gain functions V 0 V 1 and V 0 V 2 .

Solution Summary: The author illustrates the circuit diagram of an inverting op-amp adder circuit.

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The values of the 3-dB frequency fb in terms of ft for gain functions V0V1 and V0V2 .

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Chapter 2 Solutions