Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition
7th Edition
ISBN: 9780199339136
Author: Adel S. Sedra, Kenneth C. Smith
Publisher: Oxford University Press
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 2, Problem 2.77P
a
To determine
The voltage waveform at nodes B and C for the given condition using the circuit diagram. Also, sketch the output voltage.
b
To determine
The voltage gain of the op-amp.
c
To determine
The largest sinewave output also peaks to peak and rms values.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
The two input terminals of an op-amp are connected to voltage signals of strength
745µV and 740µV repectively. The gain of the op-amp in common mode is 50 and CMMR is
8&IB. Calculate the output voltage and % of error due to common mode.
Q3.
This question is on op-amps.
(a)
Comment on the differences between the values in the two columns of
properties in the table for both an ideal op-amp and a typical 741 op-amp.
Fill in the two missing values.
Op-amp
Gain
Input resistance
Unity Bandwidth
Short circuit current
Output resistance
Ideal
Infinite
Infinite
Infinite
0
741
200000
1MHz
25mA
75 ohms
please see the attached pic thank you
Chapter 2 Solutions
Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition
Ch. 2.1 - Prob. 2.1ECh. 2.1 - Prob. 2.2ECh. 2.1 - Prob. 2.3ECh. 2.2 - Prob. D2.4ECh. 2.2 - Prob. 2.5ECh. 2.2 - Prob. 2.6ECh. 2.2 - Prob. D2.7ECh. 2.2 - Prob. D2.8ECh. 2.3 - Prob. 2.9ECh. 2.3 - Prob. 2.10E
Ch. 2.3 - Prob. D2.11ECh. 2.3 - Prob. 2.12ECh. 2.3 - Prob. 2.13ECh. 2.3 - Prob. 2.14ECh. 2.4 - Prob. 2.15ECh. 2.4 - Prob. D2.16ECh. 2.4 - Prob. 2.17ECh. 2.5 - Prob. 2.18ECh. 2.5 - Prob. D2.19ECh. 2.5 - Prob. D2.20ECh. 2.6 - Prob. 2.21ECh. 2.6 - Prob. 2.22ECh. 2.6 - Prob. 2.23ECh. 2.6 - Prob. 2.24ECh. 2.6 - Prob. 2.25ECh. 2.7 - Prob. 2.26ECh. 2.7 - Prob. 2.27ECh. 2.7 - Prob. 2.28ECh. 2.8 - Prob. 2.29ECh. 2.8 - Prob. 2.30ECh. 2 - Prob. 2.1PCh. 2 - Prob. 2.2PCh. 2 - Prob. 2.3PCh. 2 - Prob. 2.4PCh. 2 - Prob. 2.5PCh. 2 - Prob. 2.6PCh. 2 - Prob. 2.7PCh. 2 - Prob. 2.8PCh. 2 - Prob. 2.9PCh. 2 - Prob. 2.10PCh. 2 - Prob. 2.11PCh. 2 - Prob. D2.12PCh. 2 - Prob. D2.13PCh. 2 - Prob. D2.14PCh. 2 - Prob. 2.15PCh. 2 - Prob. 2.16PCh. 2 - Prob. 2.17PCh. 2 - Prob. 2.18PCh. 2 - Prob. 2.19PCh. 2 - Prob. D2.20PCh. 2 - Prob. 2.21PCh. 2 - Prob. 2.22PCh. 2 - Prob. 2.23PCh. 2 - Prob. 2.24PCh. 2 - Prob. 2.25PCh. 2 - Prob. D2.26PCh. 2 - Prob. 2.27PCh. 2 - Prob. 2.28PCh. 2 - Prob. D2.29PCh. 2 - Prob. 2.30PCh. 2 - Prob. 2.31PCh. 2 - Prob. 2.32PCh. 2 - Prob. D2.33PCh. 2 - Prob. D2.34PCh. 2 - Prob. D2.35PCh. 2 - Prob. 2.36PCh. 2 - Prob. D2.37PCh. 2 - Prob. D2.38PCh. 2 - Prob. D2.39PCh. 2 - Prob. D2.40PCh. 2 - Prob. D2.41PCh. 2 - Prob. D2.42PCh. 2 - Prob. 2.43PCh. 2 - Prob. D2.44PCh. 2 - Prob. D2.45PCh. 2 - Prob. D2.46PCh. 2 - Prob. D2.47PCh. 2 - Prob. D2.48PCh. 2 - Prob. 2.49PCh. 2 - Prob. 2.50PCh. 2 - Prob. D2.51PCh. 2 - Prob. D2.52PCh. 2 - Prob. 2.53PCh. 2 - Prob. 2.54PCh. 2 - Prob. 2.55PCh. 2 - Prob. D2.56PCh. 2 - Prob. 2.57PCh. 2 - Prob. 2.58PCh. 2 - Prob. 2.59PCh. 2 - Prob. 2.60PCh. 2 - Prob. D2.61PCh. 2 - Prob. 2.62PCh. 2 - Prob. 2.63PCh. 2 - Prob. 2.64PCh. 2 - Prob. 2.65PCh. 2 - Prob. 2.66PCh. 2 - Prob. D2.67PCh. 2 - Prob. 2.68PCh. 2 - Prob. D2.69PCh. 2 - Prob. 2.70PCh. 2 - Prob. D2.71PCh. 2 - Prob. 2.72PCh. 2 - Prob. 2.73PCh. 2 - Prob. 2.74PCh. 2 - Prob. 2.75PCh. 2 - Prob. D2.76PCh. 2 - Prob. 2.77PCh. 2 - Prob. 2.78PCh. 2 - Prob. 2.79PCh. 2 - Prob. D2.80PCh. 2 - Prob. 2.81PCh. 2 - Prob. D2.82PCh. 2 - Prob. D2.83PCh. 2 - Prob. 2.84PCh. 2 - Prob. 2.85PCh. 2 - Prob. D2.86PCh. 2 - Prob. 2.87PCh. 2 - Prob. 2.88PCh. 2 - Prob. 2.89PCh. 2 - Prob. 2.90PCh. 2 - Prob. 2.91PCh. 2 - Prob. D2.92PCh. 2 - Prob. D2.93PCh. 2 - Prob. 2.94PCh. 2 - Prob. 2.95PCh. 2 - Prob. 2.96PCh. 2 - Prob. 2.97PCh. 2 - Prob. 2.98PCh. 2 - Prob. D2.99PCh. 2 - Prob. D2.100PCh. 2 - Prob. 2.101PCh. 2 - Prob. 2.102PCh. 2 - Prob. 2.103PCh. 2 - Prob. 2.104PCh. 2 - Prob. 2.105PCh. 2 - Prob. 2.106PCh. 2 - Prob. 2.107PCh. 2 - Prob. 2.108PCh. 2 - Prob. 2.109PCh. 2 - Prob. 2.110PCh. 2 - Prob. 2.111PCh. 2 - Prob. 2.112PCh. 2 - Prob. 2.113PCh. 2 - Prob. 2.114PCh. 2 - Prob. 2.115PCh. 2 - Prob. D2.116PCh. 2 - Prob. D2.117PCh. 2 - Prob. D2.118PCh. 2 - Prob. 2.119PCh. 2 - Prob. 2.120PCh. 2 - Prob. 2.121PCh. 2 - Prob. 2.122PCh. 2 - Prob. 2.123PCh. 2 - Prob. 2.124PCh. 2 - Prob. 2.125PCh. 2 - Prob. 2.126PCh. 2 - Prob. D2.127P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.Similar questions
- Select true or false for 1 and 21 Op amp component is temperature limited due to maximum output current2 The input offset voltage affects the value of the opamp output and is caused by internal non-idealities in the transistors and resistors. 3 What is the use of an op amp in voltage follower? Select one:a. It is the ideal bridge to couple any stages without affecting the voltage.b. It is ideal for maximum power transferc. Allows a small signal to be amplified with high gaind. voltage attenuation 4. It allows to eliminate the problem of variability in the gain parameter of the circuit:Select one:a. The load RLb. High input impedancec. feedback loopd. decoupling capacitors 5 Complete: The output current is limited due to the _____ that the opamp can handle, while the ______ is limiting due to the maximum bias level supported by the transistor.arrow_forwardProblem 3: Derive the gain of the operational amplifier circuit below using the op-amp voltage rule and op-amp current rule. If the resistor R2 =1 k2, the input voltage vin = voltage vout = 5 V DC, what should the resistance of R1 be? 0.1 V DC and the output %3D wwwwarrow_forwardBy using only two op-amps, design a circuit that can perform the following operation: Vo == Also, evaluate the given circuit equation. Show all the assumptions, calculation and the circuit illustration. Marking Scheme: Circuit Design Assumptions Calculationarrow_forward
- Here is a single op-amp, shown under two different conditions (different input voltages). Determine the voltage gain of this op-amp, given the conditions shown. Also, write a mathematical formula solving for differential voltage gain (AV) in terms of an op-amp's input and output voltages. +12 V +12 V Va=1.00 V %3D Vout = 1.5 V +12 V V=1.00003 V %3D -12 V +12 V +12 V Va =1.00 V %3D Vet = 6.8 V +12 V V 1.00004 V -12 Varrow_forwardThe ideal op-amps depicted can swing rail-to-rail at output, and Vcc= 13 V. Initially, the output voltage Vo = +13 V and the input voltage is vS = -13 V. The feedback resistors are R1 = 6.4 k0, R2 = 8.5 kQ, and R3 = 1.6 KQ. If the input voltage is gradually increased, at what value of vS (to 1% accuracy) does the output voltage (Vo) change to Vo=-Vcc? VVV vS = + R10 Vcc -Vcc R20 04 O Voarrow_forward3J Calculate the the Input Voltage of a non-inverting op-amp with the following parameters Rf = 360KOhms, Ri= 12kOhms, and Vi = 2.4V. a.0.934 mV b.9.34 V c.77.42mV d.93.4 microVarrow_forward
- For a subtractor circuit using one op-amp, when all the resistors are equal which of the following statements is true? The non-inverting input voltage is less than the inverting input voltage. The node voltage VA is equal to twice the non-inverting input voltage. The inverting input voltage is greater than the non-inverting input voltage. The node voltage VA is equal to one-half of the non-inverting input voltage.arrow_forward1) Op-amp limiting factors - Current Saturation U2 Vin R1 OUT OPAMP R2 RLoad The saturation output current for the above op-amp is +/- 15mA. For the following input signals, determine if the output appears as would be expected in an ideal circuit. Include sketches of the output voltage. a) R1 = 100, R2 = 900, an open circuit load, and Vin is 2Vpp triangle wave with zero offset voltage (Vmax 1V, Vmin = -1V) and a period of 2ms. b) R1 = 100, R2 = 900, a 1k load, and Vin is 2Vpp triangle wave with a 1V offset voltage (Vmax=2V, Vmin = 0V) and a period of 2ms. c) R1 = 100, R2 = 900, an open circuit load, and Vin is 4Vpp triangle wave with zero offset voltage (Vmax=2V, Vmin = -2V) and a period of 2ms.arrow_forwardQ2) Why is there a difference between the theoretical and practical values of voltage gain in an inverting and non-inverting Op amplifier?arrow_forward
- +15 V V. Ideally, when the two input terminals of an op-amp are shorted together (creating a condition of zerc differential voltage), and those two inputs are connected directly to ground (creating a condition of zero common-mode voltage), what should this op-amp's output voltage be? In reality, the output voltage of an op-amp under these conditions is not the same as what would be ideally predicted. Identify the fundamental problem in real op-amps, and also identify the best solution.arrow_forwardDiscussion: 1- What kind of restrictions Non- inverting op-amp face compared to inverting op-amp? 2- State 5 different types of op amp. Demonstrate them briefly then draw the circuit diagram for each kind. 3- For an inverting op amp, if the voltage input peak equal to 10.2 V, R=10KQ and RF 2002, find Vo and the voltage gain. Assume the input signal has a sinusoidal behavior. 4- Consider an OP amp connected to the inverting configuration to realize a closed-loop gain of -50 V/V utilizing resistors o f 1 k2 and 50 kQ. A load resistance RL is connected from the output to ground, and a low-frequency sine wave signal of peak amplitude Vp is applied to the input. Let the OP amp be ideal except that its output voltage saturates at +/- 10V and its output current is limited to the range +/-15 mA. For RL = 1 k2, what is the maximum possible value of Vp while an undistorted output sinusoid is obtained?arrow_forwardChoose the correct answer. *Please answer it ASAP if you can*arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Introductory Circuit Analysis (13th Edition)Electrical EngineeringISBN:9780133923605Author:Robert L. BoylestadPublisher:PEARSON
Delmar's Standard Textbook Of ElectricityElectrical EngineeringISBN:9781337900348Author:Stephen L. HermanPublisher:Cengage Learning
Programmable Logic ControllersElectrical EngineeringISBN:9780073373843Author:Frank D. PetruzellaPublisher:McGraw-Hill Education
Fundamentals of Electric CircuitsElectrical EngineeringISBN:9780078028229Author:Charles K Alexander, Matthew SadikuPublisher:McGraw-Hill Education
Electric Circuits. (11th Edition)Electrical EngineeringISBN:9780134746968Author:James W. Nilsson, Susan RiedelPublisher:PEARSON
Engineering ElectromagneticsElectrical EngineeringISBN:9780078028151Author:Hayt, William H. (william Hart), Jr, BUCK, John A.Publisher:Mcgraw-hill Education,
Introductory Circuit Analysis (13th Edition)
Electrical Engineering
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:PEARSON
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Cengage Learning
Programmable Logic Controllers
Electrical Engineering
ISBN:9780073373843
Author:Frank D. Petruzella
Publisher:McGraw-Hill Education
Fundamentals of Electric Circuits
Electrical Engineering
ISBN:9780078028229
Author:Charles K Alexander, Matthew Sadiku
Publisher:McGraw-Hill Education
Electric Circuits. (11th Edition)
Electrical Engineering
ISBN:9780134746968
Author:James W. Nilsson, Susan Riedel
Publisher:PEARSON
Engineering Electromagnetics
Electrical Engineering
ISBN:9780078028151
Author:Hayt, William H. (william Hart), Jr, BUCK, John A.
Publisher:Mcgraw-hill Education,
Electrical Engineering: Ch 5: Operational Amp (2 of 28) Inverting Amplifier-Basic Operation; Author: Michel van Biezen;https://www.youtube.com/watch?v=x2xxOKOTwM4;License: Standard YouTube License, CC-BY