Elements of Chemical Reaction Engineering (5th Edition) (Prentice Hall International Series in the Physical and Chemical Engineering Sciences)
5th Edition
ISBN: 9780133887518
Author: H. Scott Fogler
Publisher: Prentice Hall
expand_more
expand_more
format_list_bulleted
Textbook Question
thumb_up100%
Chapter 2, Problem 2.10P
The curve shown in Figure 2-1 is typical of a reaction carried out isothermally, and the curve shown in Figure P2-10B (sec Example 11-3) is typical of a gas-solid catalytic exothermic reaction carried out adiabatically).
Figure P2-10B Levenspiel plot for an adiabatic exothermic heterogeneous reaction.
- (a) Assuming that you have a fluidized CSTR and a PBR containing equal weights of catalyst, how should they be arranged for this adiabatic reaction? Use the smallest amount of catalyst weight to achieve 80% conversion of A.
- (b) What is the catalyst weight necessary to achieve 80% conversion in a fluidized CSTR?
- (c) What fluidized CSTR weight is necessary to achieve 40% conversion?
- (d) What PBR weight is necessary to achieve 80% conversion?
- (e) What PBR weight is necessary to achieve 40% conversion?
- (f) Plot the rate of reaction and conversion as a function of PBR catalyst weight, W.
Additional information: FA0 = 2 mol/s.
Expert Solution & Answer
Learn your wayIncludes step-by-step video
schedule05:37
Students have asked these similar questions
مشر
on
۲/۱
Two rods (fins) having same dimensions, one made of brass(k=85 m
K) and the other of copper (k = 375 W/m K), having one of their ends inserted
into a furnace. At a section 10.5 cm a way from the furnace, the temperature
brass rod 120°C. Find the distance at which the same temperature would be
reached in the copper rod ? both ends are exposed to the same environment.
22.05
ofthe
4.59
Using the unilateral z-transform, solve the following difference equations with the given initial
conditions.
(a) y[n]-3y[n-1] = x[n], with x[n] = 4u[n], y[− 1] = 1
(b) y[n]-5y[n-1]+6y[n-2]= x[n], with x[n] = u[n], y[-1] = 3, y[-2]= 2
Ans. (a) y[n] = -2+9(3)", n ≥ -1
(b) y[n]=+8(2)" - (3)", n ≥ -2
(30)
6. In a process design, the following process streams must be cooled or heated:
Stream
No
mCp
Temperature In Temperature Out
°C
°C
kW/°C
1
5
350
270
2
9
270
120
3
3
100
320
4
5
120
288
Use the MUMNE algorithm for heat exchanger networks with a minimum approach
temperature of 20°C.
(5)
a. Determine the temperature interval diagram.
(3)
(2)
(10)
(10)
b. Determine the cascade diagram, the pinch temperatures, and the minimum hot and
cold utilities.
c. Determine the minimum number of heat exchangers above and below the pinch.
d. Determine a valid heat exchange network above the pinch.
e. Determine a valid heat exchange network below the pinch.
Chapter 2 Solutions
Elements of Chemical Reaction Engineering (5th Edition) (Prentice Hall International Series in the Physical and Chemical Engineering Sciences)
Additional Engineering Textbook Solutions
Find more solutions based on key concepts
If the interface of a weld is viewed in cross section, what is the distinctive geometric feature of an explosiv...
Degarmo's Materials And Processes In Manufacturing
Pure Abstract Base Class Project Define a pure abstract base class called BasicShape. The BasicShape class shou...
Starting Out with C++ from Control Structures to Objects (9th Edition)
Write a program that reads a 4-bit binary number from the keyboard as a string and then converts it into decima...
Java: An Introduction to Problem Solving and Programming (8th Edition)
Describe the purpose of the access key attribute and how it supports accessibility.
Web Development and Design Foundations with HTML5 (8th Edition)
1.2 Explain the difference between geodetic and plane
surveys,
Elementary Surveying: An Introduction To Geomatics (15th Edition)
Distinguish among data definition commands, data manipulation commands, and data control commands.
Modern Database Management
Knowledge Booster
Similar questions
- Use this equation to solve it.arrow_forwardQ1: Consider the following transfer function G(s) 5e-s 15s +1 1. What is the study state gain 2. What is the time constant 3. What is the value of the output at the end if the input is a unit step 4. What is the output value if the input is an impulse function with amplitude equals to 3, at t=7 5. When the output will be 3.5 if the input is a unit steparrow_forwardgive me solution math not explinarrow_forward
- Example (6): An evaporator is concentrating F kg/h at 311K of a 20wt% solution of NaOH to 50wt %. The saturated steam used for heating is at 399.3K. The pressure in the vapor space of the evaporator is 13.3 KPa abs. The 5:48 O Transcribed Image Text: Example (7): Determine thearrow_forward14.9. A forward feed double-effect vertical evaporator, with equal heating areas in each effect, is fed with 5 kg/s of a liquor of specific heat capacity of 4.18 kJ/kg K. and with no boiling point rise, so that 50 per cent of the feed liquor is evaporated. The overall heat transfer coefficient in the second effect is 75 per cent of that in the first effect. Steam is fed at 395 K and the boiling point in the second effect is 373 K. The feed is heated by an external heater to the boiling point in the first effect. It is decided to bleed off 0.25 kg/s of vapour from the vapour line to the second effect for use in another process. If the feed is still heated to the boiling point of the first effect by external means, what will be the change in steam consumption of the evaporator unit? For the purpose of calculation, the latent heat of the vapours and of the steam may both be taken as 2230 kJ/kgarrow_forwardExample(3): It is desired to design a double effect evaporator for concentrating a certain caustic soda solution from 12.5wt% to 40wt%. The feed at 50°C enters the first evaporator at a rate of 2500kg/h. Steam at atmospheric pressure is being used for the said purpose. The second effect is operated under 600mmHg vacuum. If the overall heat transfer coefficients of the two stages are 1952 and 1220kcal/ m2.h.°C. respectively, determine the heat transfer area of each effect. The BPR will be considered and present for the both effect 5:49arrow_forward
- العنوان ose only Q Example (7): Determine the heating surface area 개 required for the production of 2.5kg/s of 50wt% NaOH solution from 15 wt% NaOH feed solution which entering at 100 oC to a single effect evaporator. The steam is available as saturated at 451.5K and the boiling point rise (boiling point evaluation) of 50wt% solution is 35K. the overall heat transfer coefficient is 2000 w/m²K. The pressure in the vapor space of the evaporator at atmospheric pressure. The solution has a specific heat of 4.18kJ/ kg.K. The enthalpy of vaporization under these condition is 2257kJ/kg Example (6): 5:48 An evaporator is concentrating F kg/h at 311K of a 20wt% solution of NaOH to 50wt %. The saturated steam used for heating is at 399.3K. The pressure in the vapor space of the evaporator is 13.3 KPa abs. The 5:48 1 J ۲/۱ ostrarrow_forwardExample 8: 900 Kg dry solid per hour is dried in a counter current continues dryer from 0.4 to 0.04 Kg H20/Kg wet solid moisture content. The wet solid enters the dryer at 25 °C and leaves at 55 °C. Fresh air at 25 °C and 0.01Kg vapor/Kg dry air is mixed with a part of the moist air leaving the dryer and heated to a temperature of 130 °C in a finned air heater and enters the dryer with 0.025 Kg/Kg alry air. Air leaving the dryer at 85 °C and have a humidity 0.055 Kg vaper/Kg dry air. At equilibrium the wet solid weight is 908 Kg solid per hour. *=0.0088 Calculate:- Heat loss from the dryer and the rate of fresh air. Take the specific heat of the solid and moisture are 980 and 4.18J/Kg.K respectively, A. =2500 KJ/Kg. Humid heat at 0.01 Kg vap/Kg dry=1.0238 KJ/Kg. "C. Humid heat at 0.055 Kg/Kg 1.1084 KJ/Kg. "C 5:42 Oarrow_forwardQ1: From the Figure below for (=0.2 find the following 1. Rise Time 2. Time of oscillation 3. Overshoot value 4. Maximum value 5. When 1.2 which case will be? 1.6 1.4 1.2 12 1.0 |=0.8- 0.6 0.4 0.8 0.2- 0.6 0.4 0.2 1.2 = 1.0 0 2 4 6 8 10 10 t/Tarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Introduction to Chemical Engineering Thermodynami...Chemical EngineeringISBN:9781259696527Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark SwihartPublisher:McGraw-Hill Education
Elementary Principles of Chemical Processes, Bind...Chemical EngineeringISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY
Elements of Chemical Reaction Engineering (5th Ed...Chemical EngineeringISBN:9780133887518Author:H. Scott FoglerPublisher:Prentice Hall
Industrial Plastics: Theory and ApplicationsChemical EngineeringISBN:9781285061238Author:Lokensgard, ErikPublisher:Delmar Cengage Learning
Unit Operations of Chemical EngineeringChemical EngineeringISBN:9780072848236Author:Warren McCabe, Julian C. Smith, Peter HarriottPublisher:McGraw-Hill Companies, The
Introduction to Chemical Engineering Thermodynami...
Chemical Engineering
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:McGraw-Hill Education
Elementary Principles of Chemical Processes, Bind...
Chemical Engineering
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY
Elements of Chemical Reaction Engineering (5th Ed...
Chemical Engineering
ISBN:9780133887518
Author:H. Scott Fogler
Publisher:Prentice Hall
Industrial Plastics: Theory and Applications
Chemical Engineering
ISBN:9781285061238
Author:Lokensgard, Erik
Publisher:Delmar Cengage Learning
Unit Operations of Chemical Engineering
Chemical Engineering
ISBN:9780072848236
Author:Warren McCabe, Julian C. Smith, Peter Harriott
Publisher:McGraw-Hill Companies, The