Explanation The given financially important reaction that is used to form valuable product B is, A → B + C The above mentioned reaction occurs in the liquid phase. The given budget to construct the reaction equipment is $ 10 , 000 . A Levenspiel plot between conversion and volume for the given reaction is shown as, Figure 1 The cost of various reactors is shown in the table below. Reactor Type Number Volume ( dm 3 ) Cost CSTR 2 2 $ 1000 CSTR 1 4 $ 2000 PFR 2 4 $ 2000 CSTR 2 6 $ 4000 CSTR 3 12 $ 8000 PFR 2 12 $ 6000 The reactor can be chosen and arranged to get the highest conversion in the given budget of $ 10 , 000 . After choosing the CSTR, the value of conversion is taken as X = 0.2 from the graph show in Figure 1 to calculate the needed volume of the CSTR. The equation that is used to calculate the volume of CSTR is, V = F A0 X ( − r A ) exit (1) Where, V is the CSTR’s volume. F A0 is the molar flow rate of the species A. X is the conversion. ( − r A ) exit is the evaluated rate of reaction at the time of exit. According to the given graph, the value of ( F A0 ( − r A ) exit ) X = 0.2 corresponding to X = 0.2 is, 20 = ( F A0 ( − r A ) exit ) X = 0.2 Substitute the value of ( F A0 ( − r A ) exit ) X = 0.2 as 20 and value of X as 0.2 in equation (1). V = 20 ( dm 3 ) × 0.2 = 4 ( dm 3 ) Thus, a CSTR with volume 4 ( dm 3 ) is selected to get the conversion, X = 0.2 . According to the given graph, there is no change in the value of ( F A0 ( − r A ) exit ) for conversion from X = 0.2 to 0.6 . Therefore, the conversion for this is not dependent upon any type of reactor. Thus, the needed volume of CSTR that is used to increase the conversion from X = 0.2 to 0.6 is calculated by the equation, V = F A0 ( − r A ) exit ( X 2 − X 1 ) (2) The value of X 2 is 0.6 . The value of X 1 is 0.2 . The value of ( F A0 ( − r A ) exit ) X = 0.6 corresponding to X = 0.2 to 0.6 is, 20 = ( F A0 ( − r A ) exit ) X = 0.6 Substitute the value of ( F A0 ( − r A ) exit ) X = 0.2 as 20 and value of X as 0.2 in equation (2). V = 20 ( dm 3 ) × ( 0.6 − 0.2 ) = 8 ( dm 3 ) Thus, a CSTR with volume 8 ( dm 3 ) is selected to get the conversion from X = 0

Elements of Chemical Reaction Engineering (5th Edition) (Prentice Hall International Series in the Physical and Chemical Engineering Sciences)

5th Edition

ISBN: 9780133887518

Author: H. Scott Fogler

Publisher: Prentice Hall

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Question

Chapter 2, Problem 2.5P

Interpretation Introduction

Interpretation:

The reactor that can be selected to perform the given reaction is to be stated. The procedure to arrange the selected reactor is to be stated. The highest conversion that is obtained for $10,000 is to be predicted. The approximate corresponding conversion with the selected arrangement of reactor is to be stated. The scheme and sketch for the volume of the selected reactor are to be stated.

Concept introduction:

The full form of CSTR is Continuous-Stirred Tank Reactor. This reactor has its application in the industrial processes. This reactor actually used for liquid-phase reactions.

The conversion, X can be defined as the moles of any species A that are reacted per mole of A fed in the reactor.

The equation in which number of moles of reactant and product are same or balanced is known as mole balanced equation.

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Chapter 2 Solutions

Elements of Chemical Reaction Engineering (5th Edition) (Prentice Hall International Series in the Physical and Chemical Engineering Sciences)

Ch. 2 - Prob. 2.1P Ch. 2 - You have two CSTRs and two PFRs, each with a...Ch. 2 - Prob. 2.4P Ch. 2 - Prob. 2.5P Ch. 2 - Prob. 2.6P Ch. 2 - The adiabatic exothermic irreversible gas-phase...Ch. 2 - Prob. 2.8P Ch. 2 - The curve shown in Figure 2-1 is typical of a...

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