The chemical formulas for the given compounds are to be written. Concept Information: Transition metals have the ability to form more than one positive ion and then form two ionic compounds with given non-metals. Stock system is the method for naming the metal ions that have more than one oxidation state in compounds indicated by Roman numeral in parenthesis just after the name of the metal ion. For naming of ionic compounds containing polyatomic ions, the name of the metal (cation) or a polyatomic cation written first, followed by the name of anion, this can be non-metal, and it this is non-metal (anion), change the suffix of non-metal to - i d e , adding at the end of the anion, that is in case of monatomic ions. The hydroxide ion and cynide ion are the exceptions. Rules of naming molecular compounds: Replace the ending of the second element with “ide”. While naming molecular compounds prefixes are used to indicate the number of a given element present in the compound like ” mono-” indicates one, “di-” indicates two, “tri-” is three, “tetra-” is four, “penta-” is five, and “hexa-” is six, “hepta-” is seven, “octo-” is eight, “nona-” is nine, and “deca” is ten.
The chemical formulas for the given compounds are to be written. Concept Information: Transition metals have the ability to form more than one positive ion and then form two ionic compounds with given non-metals. Stock system is the method for naming the metal ions that have more than one oxidation state in compounds indicated by Roman numeral in parenthesis just after the name of the metal ion. For naming of ionic compounds containing polyatomic ions, the name of the metal (cation) or a polyatomic cation written first, followed by the name of anion, this can be non-metal, and it this is non-metal (anion), change the suffix of non-metal to - i d e , adding at the end of the anion, that is in case of monatomic ions. The hydroxide ion and cynide ion are the exceptions. Rules of naming molecular compounds: Replace the ending of the second element with “ide”. While naming molecular compounds prefixes are used to indicate the number of a given element present in the compound like ” mono-” indicates one, “di-” indicates two, “tri-” is three, “tetra-” is four, “penta-” is five, and “hexa-” is six, “hepta-” is seven, “octo-” is eight, “nona-” is nine, and “deca” is ten.
Solution Summary: The author explains that transition metals have the ability to form more than one positive ion and then form two ions with given non-metals.
Definition Definition Elements containing partially filled d-subshell in their ground state configuration. Elements in the d-block of the periodic table receive the last or valence electron in the d-orbital. The groups from IIIB to VIIIB and IB to IIB comprise the d-block elements.
Chapter 2, Problem 112RQ
Interpretation Introduction
Interpretation:
The chemical formulas for the given compounds are to be written.
Concept Information:
Transition metals have the ability to form more than one positive ion and then form two ionic compounds with given non-metals.
Stock system is the method for naming the metal ions that have more than one oxidation state in compounds indicated by Roman numeral in parenthesis just after the name of the metal ion.
For naming of ionic compounds containing polyatomic ions, the name of the metal (cation) or a polyatomic cation written first, followed by the name of anion, this can be non-metal, and it this is non-metal (anion), change the suffix of non-metal to -ide, adding at the end of the anion, that is in case of monatomic ions. The hydroxide ion and cynide ion are the exceptions.
Rules of naming molecular compounds:
Replace the ending of the second element with “ide”.
While naming molecular compounds prefixes are used to indicate the number of a given element present in the compound like ” mono-” indicates one, “di-” indicates two, “tri-” is three, “tetra-” is four, “penta-” is five, and “hexa-” is six, “hepta-” is seven, “octo-” is eight, “nona-” is nine, and “deca” is ten.
Don't used hand raiting and don't used Ai solution
H2(g) + I2(g) ⇔ 2HI(g)
Using the above equilibrium, find the equilibrium concentration of H2 if the intial concentration of both H2 and I2 are 2.0. K at this temperature is 55.64.
find K, the equilibrium constant, if the inital concentration of SO3 is 0.166 M, and the equilibrium concentration of O2 is 0.075 M.
2SO3 (g) ⇌ 2SO2 (g) + O2 (g)