Given that glucose when treated with NaBH 4 gets reduced to yield sorbitol. How this reduction process occurs is to be shown. Concept introduction: The cyclic pyranose ring in glucose, when cleaved, will yield the open chain compound with a free aldehyde group. The aldehyde group can be reduced by NaBH 4 to an alcohol group to get sorbitol. To show: How the reduction of glucose by NaBH 4 to yield sorbitol occurs.

Question

personality of each of them in terms of nucleophile vs. electrophile (some can be considered acids/bases but we are not looking at that here). Note you may have to use your growing intuition to figure out the personality of one of the molecules below but I believe in you! Rationalize it out based on what we have called strong versus weak electrophiles in past mechanisms. Consider using the memes below to help guide your understanding! A OH O B CH3 C Molecule A: [Select] Molecule B: [Select] Molecule C: [Select] Molecule D: [Select] > H D OH

Answer 1

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 19.SE, Problem 85AP

Interpretation Introduction

Interpretation:

Given that glucose when treated with NaBH₄ gets reduced to yield sorbitol. How this reduction process occurs is to be shown.

Concept introduction:

The cyclic pyranose ring in glucose, when cleaved, will yield the open chain compound with a free aldehyde group. The aldehyde group can be reduced by NaBH₄ to an alcohol group to get sorbitol.

To show:

How the reduction of glucose by NaBH₄ to yield sorbitol occurs.

Expert Solution & Answer

Trending nowThis is a popular solution!

Learn your wayIncludes step-by-step video

See solution

Check out sample textbook solution

05:53

Students have asked these similar questions

personality of each of them in terms of nucleophile vs. electrophile (some can be considered acids/bases but we are not looking at that here). Note you may have to use your growing intuition to figure out the personality of one of the molecules below but I believe in you! Rationalize it out based on what we have called strong versus weak electrophiles in past mechanisms. Consider using the memes below to help guide your understanding! A OH O B CH3 C Molecule A: [Select] Molecule B: [Select] Molecule C: [Select] Molecule D: [Select] > H D OH

4) Which oxygen atom in the structure below is most basic / nucleophilic? Please explain by discussing the electron density around each oxygen atom. Show at least three resonance structures for the compound. оого

Can you show me this problem. Turn them into lewis dot structures for me please and then answer the question because I cant seem to comprehend it/ The diagrams on the picture look too small I guess.

Answer 2

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 19.SE, Problem 85AP

Interpretation Introduction

Interpretation:

Given that glucose when treated with NaBH₄ gets reduced to yield sorbitol. How this reduction process occurs is to be shown.

Concept introduction:

The cyclic pyranose ring in glucose, when cleaved, will yield the open chain compound with a free aldehyde group. The aldehyde group can be reduced by NaBH₄ to an alcohol group to get sorbitol.

To show:

How the reduction of glucose by NaBH₄ to yield sorbitol occurs.

Expert Solution & Answer

Trending nowThis is a popular solution!

Learn your wayIncludes step-by-step video

See solution

Check out sample textbook solution

05:53

Answer 3

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 19.SE, Problem 85AP

Interpretation Introduction

Interpretation:

Given that glucose when treated with NaBH₄ gets reduced to yield sorbitol. How this reduction process occurs is to be shown.

Concept introduction:

The cyclic pyranose ring in glucose, when cleaved, will yield the open chain compound with a free aldehyde group. The aldehyde group can be reduced by NaBH₄ to an alcohol group to get sorbitol.

To show:

How the reduction of glucose by NaBH₄ to yield sorbitol occurs.

Expert Solution & Answer

Trending nowThis is a popular solution!

Learn your wayIncludes step-by-step video

See solution

Check out sample textbook solution

05:53

Answer 4

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 19.SE, Problem 85AP

Interpretation Introduction