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- Calculate K for the reaction SnO2(s) + 2 CO(g) Sn(s) + 2 CO2(g) given the following information: SnO2(s)+2H2(g)Sn(s)+2H2O(g)K=8.12H2(g)+CO2(g)H2O(g)+CO(g)K=0.771arrow_forwardCalculate K at 25°C for each of the reactions referred to in Question 32. Assume smallest whole-number coefficients.arrow_forwardEstimate ΔrG° at 2000. K for each reaction in Question 60.arrow_forward
- Calculate G and K at 25C for the reactions in Exercises 38 and 42.arrow_forwardUsing the following data, calculate the value of Ksp for Ba(NO3)2, one of the least soluble of the common nitrate salts. Species Gfo Ba2+(aq) 561 KJ/mol NO3(aq) 109 KJ/mol Ba(NO3)2(s) 797KJ/molarrow_forwardCalculate the equilibrium constant at 25 C for each of the following reactions from the value G given. (a) I2(s)+Cl2(l)2ICl(g)G=10.88kJ (b) H2(g)+I2(s)2HI(g)G=3.4kJ (c) CS2(g)+3Cl2(g)CCl4(g)+S2Cl2(g)G=39kJ (d) 2SO2(g)+O2(g)2SO3(g)G=141.82kJ (e) CS2(g)CS2(l)G=1.88kJarrow_forward
- The thermite reaction is 2Al(s) + Fe2O3(s) Al2O3(s) + 2Fe(s) (a) Calculate G for this reaction. (b) Calculate Keq for this reaction. Assume T = 298 K. You may have to do some mathematical manipulations to get your final numerical answer.arrow_forwardGiven the following data: PtCl42(aq)+2ePt(s)+4Cl(aq)Ered=0.73VPt2+(aq)+2ePt(s)Ered=1.20V Find Kffor PtCl42- at 25°C.arrow_forwardCalculate equilibrium constants for the following reactions at 208 K. Indicate whether the equilibrium as written is reactant- or product-favored at equilibrium. (a) Co(s) + Ni2+(aq) Co2+(aq) + Ni(s) (b) Fe3+(aq) + Cr2+(aq) Cr3+(aq) + Fe2+(aq)arrow_forward
- a Calculate K1, at 25C for phosphoric acid: H3PO4(aq)H+(aq)+H2PO4(aq) b Which thermodynamic factor is the most significant in accounting for the fact that phosphoric acid is a weak acid? Why ?arrow_forwardThe equilibrium constant for a reaction decreases as temperature increases. Explain how this observation is used to determine the sign of either H or S.arrow_forwardUse the values for G f in Appendix 1 to calculate Ksp for barium sulfate at 25C. Compare with the value given in Chapter 15.arrow_forward
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