
Interpretation:
The percentage by mass of iron in the given iron ore is to be calculated.
Concept introduction:
The mass of an ion discharge during
Oxidation is the addition of the electronegative element and the removal of the electropositive element in a
Electrolysis is the process in which the reaction takes place at the electrodes. The electrode that is charged positively is called anode. The electrode that is charged negatively is called cathode. During electrolysis, the reduction takes place at the cathode and the oxidation takes place at the anode.

Answer to Problem 66AP
Solution:
Explanation of Solution
Given information: The mass of
is
Consider that the galvanic cell is made up of
The cell diagram is as follows:
The two half cell equations are as follow:
The number of electrons take part in the two half-cells reaction should be the same.
Adding the two half reactions gives the overall cell reaction, which is as follows:
The overall balanced equation is as follows:
The number of moles of
is calculated as follows:
Substitute the value of the concentration and the volume in the above expression as follows:
The overall balanced equation is as follows:
From the balance equation, 1 mole of
The number of moles of
The mass
Substitute the value of moles and the molecular mass in the above expression as:
The mass percentage of iron ore is calculated by using the expression, which is as follows:
Substitute the mass of iron and the mass of sample in the above expression,
The percentage by mass of iron in the ore is
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Chapter 19 Solutions
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