![Fundamentals of Electric Circuits](https://www.bartleby.com/isbn_cover_images/9780078028229/9780078028229_largeCoverImage.gif)
Assume that the two circuits in Fig. 19.135 are equivalent. The parameters of the two circuits must be equal. Using this factor and the z parameters, derive Eqs. (9.67) and (9.68).
Figure 19.135
![Check Mark](/static/check-mark.png)
Derive the expressions in Equations (9.67) and (9.68) in the textbook.
Explanation of Solution
Given Data:
Refer to Figure 19.135 in the textbook given circuits.
Consider the parameters of two circuits are equal.
Calculation:
Refer to Figure 19.135 (a) in the textbook and write the expression for
Refer to Figure 19.135 (b) in the textbook and write the expression for
From Equation (1), substitute
Refer to Figure 19.135 (a) in the textbook and write the expression for
Refer to Figure 19.135 (b) in the textbook and write the expression for
From Equation (3), substitute
Refer to Figure 19.135 (a) in the textbook and write the expression for
Refer to Figure 19.135 (b) in the textbook and write the expression for
From Equation (5), substitute
Subtract Equation (4) from Equation (2) and obtain the expression as follows:
Add Equations (6) and (7) and obtain the expression as follows:
Simplify the expression as follows:
Subtract Equation (8) from Equation (6) and obtain the expression as follows:
Subtract Equation (8) from Equation (2) and obtain the expression as follows:
From Equations (8), (9), and (10), the expressions in Equation (9.68) are derived.
Note that, the obtained expressions are not same as the expressions in the textbook, since the position of the impedances are changed in the given circuits.
Use expressions in Equations (8), (9), and (10) and obtain the expression as follows:
Divide Equation (11) by Equation (8) and obtain the expression as follows:
Divide Equation (11) by Equation (9) and obtain the expression as follows:
Divide Equation (11) by Equation (10) and obtain the expression as follows:
From Equations (12), (13), and (14), the expressions in Equation (9.67) are derived.
Note that, the obtained expressions are not same as the expressions in the textbook, since the position of the impedances are changed in the given circuits.
Conclusion:
Thus, the expressions in Equations (9.67) and (9.68) in the textbook are derived.
Want to see more full solutions like this?
Chapter 19 Solutions
Fundamentals of Electric Circuits
- use this code on the bottom to answer the question in the photo clc; clearvars; % Read the file [y, Fs] = audioread('106miles.wav'); N = length(y); Nfft = 2^nextpow2(N); dt = 1/Fs; t = (0:dt:(N-1)*dt)'; % Ensure t is a column vector y = y - mean(y); % Remove DC component (if not already zero-mean) % Carrier signal (25 kHz) fc = 25000; % Carrier frequency in Hz carrier = cos(2 * pi * fc * t); % DSB-SC Modulation modulated_signal = y .* carrier; % Plot Time Domain Signal figure; subplot(2,1,1); plot(t, y); title('Original Signal (Time Domain)'); xlabel('Time (s)'); ylabel('Amplitude'); subplot(2,1,2); plot(t, modulated_signal); title('DSB-SC Modulated Signal (Time Domain)'); xlabel('Time (s)'); ylabel('Amplitude'); % Frequency Domain (FFT) Y = fft(y, Nfft) / Nfft; Modulated_Y = fft(modulated_signal, Nfft) / Nfft; f = Fs * (0:(Nfft/2)) / Nfft; % Frequency vector % Plot Frequency Domain Signal figure; subplot(2,1,1); plot(f, abs(Y(1:Nfft/2+1))); title('Original Signal…arrow_forward5-9 A 230 V shunt motor has a nominal arma- ture current of 60 A. If the armature resist- ance is 0.152, calculate the following: a. The counter-emf [V] b. The power supplied to the armature [W] c. The mechanical power developed by the motor, [kW] and [hp] 5-10 a. In Problem 5-9 calculate the initial start- ing current if the motor is directly con- nected across the 230 V line. b. Calculate the value of the starting resistor needed to limit the initial current to 115 A.arrow_forwardhow to solve this?arrow_forward
- For the circuit in Fig. P8.52, choose the load impedance ZLso that the power dissipated in it is a maximum. How much powerwill that be?arrow_forwardhow to solve the attached question? please explain or give reference where required in the solution.arrow_forwardHANDWRITTEN SOLUTION REQUIRED NOT USING CHATGPTarrow_forward
- Please only do part E and F. Please show your work and be as detailed as possible. Please explain the relationship between K the gain and stability of the system. Also, show how to plot the poles and why they are on either the real or imaginary axis. What is it about the example that indicated that? thank youarrow_forwardPlease draw the block diagram for this problem and explain how. thank youarrow_forwardPlease show your work and be as detailed as possible. I would like to really understand the connection between the type of loop, the dampness, and the gain, K. Thank youarrow_forward
- In the zone refining of silicon, an RF-heater is used to remove trace amounts of impuritiesfrom the silicon. If the silicon has the impurity of 10^14 Co (k = 8*10^-6) what is the purityof the crystal after one pass of the zone refiner? After two passes? Plot concentration as afunction of crystal length from 0 to 8ft (total length of the crystal). The width of the moltenzone is 5”.arrow_forwardNot use ai pleasearrow_forwardSolve on paper not using AI or chatgptarrow_forward
- Introductory Circuit Analysis (13th Edition)Electrical EngineeringISBN:9780133923605Author:Robert L. BoylestadPublisher:PEARSONDelmar's Standard Textbook Of ElectricityElectrical EngineeringISBN:9781337900348Author:Stephen L. HermanPublisher:Cengage LearningProgrammable Logic ControllersElectrical EngineeringISBN:9780073373843Author:Frank D. PetruzellaPublisher:McGraw-Hill Education
- Fundamentals of Electric CircuitsElectrical EngineeringISBN:9780078028229Author:Charles K Alexander, Matthew SadikuPublisher:McGraw-Hill EducationElectric Circuits. (11th Edition)Electrical EngineeringISBN:9780134746968Author:James W. Nilsson, Susan RiedelPublisher:PEARSONEngineering ElectromagneticsElectrical EngineeringISBN:9780078028151Author:Hayt, William H. (william Hart), Jr, BUCK, John A.Publisher:Mcgraw-hill Education,
![Text book image](https://www.bartleby.com/isbn_cover_images/9780133923605/9780133923605_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781337900348/9781337900348_smallCoverImage.jpg)
![Text book image](https://www.bartleby.com/isbn_cover_images/9780073373843/9780073373843_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9780078028229/9780078028229_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9780134746968/9780134746968_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9780078028151/9780078028151_smallCoverImage.gif)