For the given function Y= (A+ BC) (B+ C'A), design a circuit for SOP representation using gates to realize this function. Also implement the same using only NAND gates.
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- Simplify the following expressions, and implement them with two-level NAND gate circuits: (a) AB'+ABD + ABD’+A’C’D'+A’BC' (b) BD + BCD'+AB’C’D' Draw a logic diagram using only two-input NAND gates to implement the following expression: (AB + A’B') (CD'+C°D)Minimize the Boolean expression F=AB’C’+C’D+BD’+A’C using K -map and implement the logic circuit using NAND gates only.Draw a logic gate circuit for the following functions: F = AB’ + C’(A + B) F = (X’Y+Z) + (X +YZ’)
- T: Answer thne f. questions: 1) The hexadecimal number ´Al' has the decimal value equivalent to (A) 80 (B) 161 (C) 100 (D) 101 2) The output of a logic gate is 0 when all its inputs are logic 1. The logic is either (A) a NAND or an EX-OR (B) an OR or an EX-NOR (C) an AND or an EX-OR (D) an NOR or an EX-NOR 3) The Gray code of the Binary number 1100111 is (A) 1011011 (B) 1010100 (C) 1001001 (D) 101101 4) When simplified with Boollean Algebra (a+b)(a+c) simplifies to (A) a (B) a+a(b+c) (C) a(1+bc) (D) a+bc 5) -31 is represented as a sign Binary number ( using Sign-magnitude form ) equal to (A) 00011111 (B) 10101001 (C) 01110010 (D) 00101101 6) The Binary number 110111 is equivalent to decimal number (A) 25 (B) 55 (C) 26 (D) 34 7) With 4 bit, what the range of decimal values if the number is 2's complement signed number. (A) -32 to +31 (B) -2 to +1 (C) -8 to +7 (D) None of theseparity generator design, construct and test a circuit that generates an even parity bit ffrom four messages bits . use XOR gates. adding one more XOR gate, expand the circuit so that it generates an odd parity bit also.1) Use mixed logic to design an implementation for F = BC + AC + AB using only 2-input NOR and NOT gates. Draw your final design using only the NOR and NOT gate symbols. Give a truth table for this expression. 2) Use mixed logic to design an implementation for F = (AB). C using only 2-input NAND gates. Draw your final design using only the NAND gate symbols. Give the truth table for this expression.
- Using a MINIMUM number of Symbolic Logic gates and IC chips make the following set of circuits in this pattern: Gated SR Latch 3 inputs NAND Symbolic NAND IC Output Output S'R' Latch (BE CAREFUL OF INITIAL CONDITIONS -- SEE WHICH CAUSES RACE CONDITION!) 2 inputs NAND Symbolic NAND IC Output Output Gated D Latch 2 inputs Inverter, NAND Symbolic NAND Symbolic NAND IC Output Output Output The details... INTERACTIVE INPUT:Use only the number of Interactive Input buttons specified and put them at the far left. EVERY CIRCUIT to the right of the buttons will use these for input. NAND Symbolic Circuit:Using only the symbolic NAND gates…a) Create a 4 Variable Karnaugh Map in paper by mapping 1’s for given standard SOP Boolean expression. After mapping , make relevant groups within Karnaugh Map by considering rules for making groups for 4 variable Karnaugh Map. After making relevant grouping , extract the minimum SOP expression by considering rules for extracting minimum SOP using Karnaugh Map. * Standard SOP: *Create Circuit Diagram using logic gates and logic converter in Multisim for given standard SOP and minimum SOP which you have solved. Do make sure that truth table for both expressions should evaluate same result.Design a combinational circuit with 3 inputs and 1 output. The output must be logic 1 when the binary value of the inputs have more 1’s than 0’s and logic 0 otherwise. Use only NAND Gates. (show All the steps)