For the given function Y= (A+ BC) (B+ C'A), design a circuit for SOP representation using gates to realize this function. Also implement the same using only NAND gates.
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representation using gates to realize this function. Also implement the same
using only NAND gates."
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- An equation in reduced SOP form, is F=AB+B'C+A'C'. I need to draw a logic circuit F using NOT/AND/OR and logoc circuit F using all NAND gates. Thank you for the help. I understood the previous types of gates but I am confused on how to draw these circuits.Using a K-Map, simplify the logic function F and construct the circuit using only NAND gates. F(x, y, z) = xz + xyz + yzlogic
- In this problem we'll explore the fact that all logical circuits can be implemented using just NAND gates. The figure below shows you the symbol for a NAND gate and its truth table. We then show you how NAND gates can be wired together to perform the equivalent of a NOT gate, an AND gate, and an OR gate. NAND gate AB Output 1 01 1 Inputa Inputg Output 10 1 11 NOT A- AND D B. A. OR B. 2 i. Let's denote p NAND q as pīq. Write a logical expression for the thrce circuits corresponding to AND, OR, and NOT. ii. Validate your three logical expressions with three truth tables. For clarity and full credit, show cach variable and distinct sub-clause in a separate column, culminating in your final formula. 3. 2.We can Design ripple counter that counts from 0 to 10 by inserting (A3,A1) to NAND gate and connect the output of the NAND gate to _____ input, where as the data input is 0000Simplify the following expressions, and implement them with two-level NAND gate circuits: (a) AB'+ABD + ABD’+A’C’D'+A’BC' (b) BD + BCD'+AB’C’D' Draw a logic diagram using only two-input NAND gates to implement the following expression: (AB + A’B') (CD'+C°D)
- Minimize the Boolean expression F=AB’C’+C’D+BD’+A’C using K -map and implement the logic circuit using NAND gates only.T: Answer thne f. questions: 1) The hexadecimal number ´Al' has the decimal value equivalent to (A) 80 (B) 161 (C) 100 (D) 101 2) The output of a logic gate is 0 when all its inputs are logic 1. The logic is either (A) a NAND or an EX-OR (B) an OR or an EX-NOR (C) an AND or an EX-OR (D) an NOR or an EX-NOR 3) The Gray code of the Binary number 1100111 is (A) 1011011 (B) 1010100 (C) 1001001 (D) 101101 4) When simplified with Boollean Algebra (a+b)(a+c) simplifies to (A) a (B) a+a(b+c) (C) a(1+bc) (D) a+bc 5) -31 is represented as a sign Binary number ( using Sign-magnitude form ) equal to (A) 00011111 (B) 10101001 (C) 01110010 (D) 00101101 6) The Binary number 110111 is equivalent to decimal number (A) 25 (B) 55 (C) 26 (D) 34 7) With 4 bit, what the range of decimal values if the number is 2's complement signed number. (A) -32 to +31 (B) -2 to +1 (C) -8 to +7 (D) None of theseDraw the logic circuit diagram using pure NAND gates and pure NOR gates: A B А ВCD X Note: convert first the logic gates with 3 inputs to its equivalent 2 inputs gate before converting to its equivalent purely NAND or NOR gates.
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