Organic Chemistry
7th Edition
ISBN: 9780321803221
Author: Paula Y. Bruice
Publisher: Prentice Hall
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Question
Chapter 19, Problem 91P
a)
Interpretation Introduction
Interpretation:
More stable intermediate from the given pair has to be determined.
Concept Introduction:
A strong electron releasing group stabilizes the carbocation intermediate by releasing more electron density towards benzene nucleus.
b)
Interpretation Introduction
Interpretation:
More stable intermediate from the given pair has to be determined.
Concept Introduction:
A strong electron releasing group stabilizes the carbocation intermediate by releasing more electron density towards benzene nucleus.
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Rank each of the following substituted benzene molecules in order of which will react fastest (1) to slowest (4) by electrophilic
aromatic substitution.
Explanation
Check
CF3
(Choose one)
OH
(Choose one)
H
(Choose one)
(Choose one)
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Identifying electron-donating and electron-withdrawing effects
For each of the substituted benzene molecules below, determine the inductive and resonance effects the substituent will have on the
benzene ring, as well as the overall electron-density of the ring compared to unsubstituted benzene.
Molecule
Inductive Effects
Resonance Effects
Overall Electron-Density
CF3
O donating
O donating
O electron-rich
O withdrawing
withdrawing
O no inductive effects
O no resonance effects
O electron-deficient
O similar to benzene
OCH3
Explanation
Check
O donating
O donating
○ withdrawing
withdrawing
O no inductive effects
no resonance effects
electron-rich
electron-deficient
O similar to benzene
Х
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The acid-base chemistry of both EDTA and EBT are important to ensuring that the reactions proceed as desired, thus the pH is controlled using a buffer. What percent of the EBT indicator will be in the desired HIn2- state at pH = 10.5. pKa1 = 6.2 and pKa2 = 11.6 of EBT
Chapter 19 Solutions
Organic Chemistry
Ch. 19.1 - Draw the structure for each of the following: a....Ch. 19.2 - PROBLEM 2
If electrophilic addition to benzene is...Ch. 19.4 - Why does hydration inactivate FeBr3?Ch. 19.6 - Prob. 5PCh. 19.7 - Prob. 6PCh. 19.8 - What is the major product of a Friedel-Crafts...Ch. 19.10 - Describe two ways to prepare each of the following...Ch. 19.12 - Prob. 9PCh. 19.13 - Name the following:Ch. 19.13 - Prob. 12P
Ch. 19.13 - Prob. 13PCh. 19.13 - Prob. 14PCh. 19.14 - Prob. 15PCh. 19.14 - List the compounds in each set from most reactive...Ch. 19.15 - Prob. 18PCh. 19.15 - What product(s) result from nitration of each of...Ch. 19.15 - Prob. 20PCh. 19.16 - Which acid in each of the following pairs is...Ch. 19.16 - Prob. 23PCh. 19.16 - Prob. 24PCh. 19.18 - Show how the following compounds can be...Ch. 19.18 - Give the products, if any, of each of the...Ch. 19.19 - a. Does a coupling reaction have to be used to...Ch. 19.19 - PROBLEM 28
Show how each of the following...Ch. 19.20 - What is the major product(s) of each of the...Ch. 19.20 - Prob. 30PCh. 19.21 - Why isn't FeBr3 used as a catalyst in the first...Ch. 19.21 - Prob. 33PCh. 19.21 - Write the sequence of steps required for the...Ch. 19.21 - Prob. 35PCh. 19.22 - What product is formed from reaction of...Ch. 19.22 - Prob. 37PCh. 19.22 - Draw the structure of the activated ring and the...Ch. 19.23 - Prob. 39PCh. 19.23 - Prob. 40PCh. 19.23 - Diazomethane can be used to convert a carboxylic...Ch. 19.24 - Prob. 42PCh. 19.24 - Prob. 43PCh. 19.24 - Prob. 44PCh. 19.25 - Prob. 45PCh. 19 - Draw the structure for each of the following: a....Ch. 19 - Prob. 47PCh. 19 - Prob. 48PCh. 19 - Prob. 49PCh. 19 - For each of the statements in Column I, choose a...Ch. 19 - What product is obtained from the reaction of...Ch. 19 - Draw the product(s) of each of the following...Ch. 19 - Rank the following substituted anilines from most...Ch. 19 - Prob. 54PCh. 19 - The compound with the 1H NMR spectrum shown below...Ch. 19 - Prob. 56PCh. 19 - Show how the following compounds can be...Ch. 19 - Prob. 58PCh. 19 - Rank each group of compounds from most reactive to...Ch. 19 - Prob. 60PCh. 19 - Describe two ways to prepare anisole from benzene.Ch. 19 - For each of the following components, indicate the...Ch. 19 - Prob. 63PCh. 19 - Prob. 64PCh. 19 - Prob. 65PCh. 19 - Prob. 66PCh. 19 - An aromatic hydrocarbon with a molecular formula...Ch. 19 - The following tertiary alkyl bromides undergo an...Ch. 19 - Show how the following compounds can be...Ch. 19 - Use the four compounds shown below to answer the...Ch. 19 - a. Rank the following esters from most reactive to...Ch. 19 - A mixture of 0.10 mol benzene and 0.10 mol...Ch. 19 - Prob. 73PCh. 19 - Benzene underwent a Friedel-Crafts acylation...Ch. 19 - Prob. 75PCh. 19 - Prob. 76PCh. 19 - Prob. 77PCh. 19 - Friedel-Crafts alkylations can be carried out with...Ch. 19 - Show how the following compounds can be prepared...Ch. 19 - Prob. 80PCh. 19 - Prob. 81PCh. 19 - a. Describe four ways the following reaction can...Ch. 19 - Propose a mechanism for each of the following...Ch. 19 - Prob. 84PCh. 19 - Describe how naphthalene can he prepared from the...Ch. 19 - Prob. 86PCh. 19 - Using resonance contributors for the carbocation...Ch. 19 - Prob. 88PCh. 19 - When heated with chromic acid, compound A forms...Ch. 19 - Prob. 90PCh. 19 - Prob. 91PCh. 19 - What reagents are required to carry out the...Ch. 19 - Show how the following compounds can be prepared...Ch. 19 - An unknown compound reacts with ethyl chloride and...Ch. 19 - How can you distinguish the following compounds...Ch. 19 - P-Fluoronitrobenzene is more reactive toward...Ch. 19 - a. Explain why the following reaction leads to the...Ch. 19 - Describe how mescaline can be synthesized from...Ch. 19 - Propose a mechanism for the following reaction...Ch. 19 - Explain why hydroxide ion catalyzes the reaction...Ch. 19 - Propose a mechanism for each of the following...Ch. 19 - Prob. 102PCh. 19 - Prob. 103PCh. 19 - Describe how 3-methyl-1-phenyl-3-pentanol can he...Ch. 19 - a. How can aspirin be synthesized from benzene? b....Ch. 19 - Prob. 106PCh. 19 - Show how Novocain, a painkiller used frequently by...Ch. 19 - Prob. 108PCh. 19 - Saccharin, an artificial sweetener, is about 300...
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