Human Biology (MindTap Course List)
11th Edition
ISBN: 9781305112100
Author: Cecie Starr, Beverly McMillan
Publisher: Cengage Learning
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Chapter 19, Problem 4SQ
Offspring of a cross AA × aa are ______.
- a. all AA
- b. all aa
- c. all Aa
- d. 1/2 AA and 1/2 aa
- e. none of the above
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Match the terms with the best description.___ dihybrid cross a. bb___ monohybrid cross b. AaBb × AaBb___ homozygous condition c. Aa___ heterozygous condition d. Aa × Aa
Assuming complete dominance, a cross between dihybrid F1 pea plants produces F2 phenotype ratios of____ . a. 1:2:1 b. 3:1 c. 1:1:1:1 d. 9:3:3:1
A test cross is performed to determine if a specific individual is a carrier. The results generate a 50/50 ratio of phenotypes. The test subject is therefore ________.
A. Unable to reproduce
B. Homozygous recessive
C. Not following the rules of Mendelian genetics
D. Homozygous dominant
E. Heterozygous
Chapter 19 Solutions
Human Biology (MindTap Course List)
Ch. 19 - Define the difference between (a) gene and allele,...Ch. 19 - Prob. 2RQCh. 19 - What is probability, and how is it applied in...Ch. 19 - What is independent assortment? Does independent...Ch. 19 - Alleles are ___________. a. alternate forms of a...Ch. 19 - A heterozygote has _____. a. only one of the...Ch. 19 - Prob. 3SQCh. 19 - Offspring of a cross AA aa are ______. a. all AA...Ch. 19 - Prob. 5SQCh. 19 - Prob. 6SQ
Ch. 19 - Which statement best fits the principle of...Ch. 19 - Prob. 8SQCh. 19 - Prob. 9SQCh. 19 - Prob. 10SQCh. 19 - One gene has alleles A and a. Another has alleles...Ch. 19 - Still referring to Problem 1, what will be the...Ch. 19 - Go back to Problem 1, and assume you now study a...Ch. 19 - The young woman shown at right has albinismvery...Ch. 19 - When you decide to breed your Labrador retriever...Ch. 19 - The ABO blood system has been used to settle cases...Ch. 19 - Prob. 7CTCh. 19 - A man is homozygous dominant for ten different...Ch. 19 - Prob. 9CTCh. 19 - Bill and Marie each have flat feet, long...Ch. 19 - You decide to breed a pair of guinea pigs, one...
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- Please Aspaarrow_forwardA testcross is a way to determine_______ . a. phenotype b. genotype c. dominancearrow_forwardThe probability of a crossover occurring between two genes on the same chromosome_____ . a. is unrelated to the distance between them b. decreases with increasing distance between them c. increases with the distance between themarrow_forward
- A mother who is blood type a B has a child who is a B also. A potential father‘s blood type O. A geneticist concludes that. A. He cannot be the father B. He is very likely to be the father C. No conclusion can be drawnarrow_forwardChromosomes undergo division during meiosis. Such chromosomal behaviors are consistent with Mendel's laws of a. Unit Characters b. None of these c. Dominance and Recessiveness d. Independent Assortment e. Secondary Nondisjunction Chromosomes undergo division during meiosis. Such chromosomal behaviors are consistent with Mendel's laws of a. Unit Characters b. None of these c. Dominance and Recessiveness d. Independent Assortment e. Secondary Nondisjunctionarrow_forwardDuring a ____ cross, an individual with the dominant phenotype andunknown genotype is crossed with a ___ individual to determine theunknown genotype.a. single-factor, homozygous recessiveb. two-factor, heterozygousc. test, homozygous dominantd. single-factor, homozygous dominante. test, homozygous recessivearrow_forward
- A BOOKMARK E- Question 4/28 NEXT Which Punnett square shows a cross between a heterozygous tall (Tt) plant and a homozygous short (tt) pea plant? C. A. Tt tt TT TT Tt tt TT TT D. В. Tt Tt tt tt Tt Tt tt tt C DDarrow_forwardthis is all i have for infoarrow_forwardIn this case a family history revealed a genetic basis for the disorder. The pedigree is shown in Fig. 1 Below. Key Ø Female: affected Female: unaffected I || IV V TOLO 5 DO 머 9 10 a. Any of these options is possible b. III.5 but not V.3 would display the disease O c. V.3 but not III.5 would display the disease O d. Neither III.5 nor V.3 would display the disease Oe. Both III.3 and V.3 would display the disease 10 ન Male: affected Male: unaffected Deceased Disease status not given Dizygotic twins Monozygotic twins Fig. 1 Disease pedigree. Five generations I, II, III, IV, V are shown. Females are represented by circles, males by squares, dizygotic (non-identical) twins by diagonal lines originating from the same point, Monozygotic (identical) twins by diagonal lines originating from the same point and joined symbols and deceased by a diagonal line through the symbol. Filled symbols indicate that the individual displays the disease phenotype. Unfilled symbols indicate that the individual…arrow_forward
- A single syndrome that has more than one genetic causeexhibits ________.a. pleiotropyb. incomplete penetrancec. genetic heterogeneityd. variable expressivityarrow_forwardT = Tall t = short pollen from a tall pea plant T T eggs from a tall pea plant T TT TT t Tt Tt In the square shown, which of the following is true about the offspring resulting from the cross? Multiple Choice a. Half are expected to be short. b. All are expected to be tall. c. All are expected to be short. d. All are expected to be of medium height.arrow_forwardThe offspring of the cross AA aa are ________. a. all AA b. all aa c. all Aa d. half are AA and half are aaarrow_forward
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