Human Biology (MindTap Course List)
11th Edition
ISBN: 9781305112100
Author: Cecie Starr, Beverly McMillan
Publisher: Cengage Learning
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Textbook Question
Chapter 19, Problem 3CT
Go back to Problem 1, and assume you now study a third gene having alleles C and c. For each genotype listed, what type(s) of gametes can be produced?
- a. AABBCC
- b. AaBBcc
- c. AaBBCc
- d. AaBbCc
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What is/are the phenotypes of the recombinant offspring of the F2generation?a. red eyes, long wingsb. white eyes, miniature wingsc. red eyes, long wings and white eyes, miniature wingsd. red eyes, miniature wings and white eyes, long wings
[Answer the multiple-choice questions based on the following experiment:P generation: True-breeding flies with red eyes and long wings werecrossed to flies with white eyes and miniature wings. All F1 offspringhad red eyes and long wings.The F1 female flies were then crossed to males with white eyes and miniaturewings. The following results were obtained for the F2 generation:129 red eyes, long wings133 white eyes, miniature wings71 red eyes, miniature wings67 white eyes, long wings]
a. What is the type of inheritance?
b. What is known of the genotype of the male in the above cross?
c. What is known of the genotype of the female in the above cross?
d. Provide map distances if possible.
A,b and c please
Chapter 19 Solutions
Human Biology (MindTap Course List)
Ch. 19 - Define the difference between (a) gene and allele,...Ch. 19 - Prob. 2RQCh. 19 - What is probability, and how is it applied in...Ch. 19 - What is independent assortment? Does independent...Ch. 19 - Alleles are ___________. a. alternate forms of a...Ch. 19 - A heterozygote has _____. a. only one of the...Ch. 19 - Prob. 3SQCh. 19 - Offspring of a cross AA aa are ______. a. all AA...Ch. 19 - Prob. 5SQCh. 19 - Prob. 6SQ
Ch. 19 - Which statement best fits the principle of...Ch. 19 - Prob. 8SQCh. 19 - Prob. 9SQCh. 19 - Prob. 10SQCh. 19 - One gene has alleles A and a. Another has alleles...Ch. 19 - Still referring to Problem 1, what will be the...Ch. 19 - Go back to Problem 1, and assume you now study a...Ch. 19 - The young woman shown at right has albinismvery...Ch. 19 - When you decide to breed your Labrador retriever...Ch. 19 - The ABO blood system has been used to settle cases...Ch. 19 - Prob. 7CTCh. 19 - A man is homozygous dominant for ten different...Ch. 19 - Prob. 9CTCh. 19 - Bill and Marie each have flat feet, long...Ch. 19 - You decide to breed a pair of guinea pigs, one...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- The F1 flies described in question 1 were mated with brown-eyed flies from a true-breeding line. What phenotypes would you expect the offspring to have? (a) all with red eyes (b) all with brown eyes (c) half with red eyes and half with brown eyes (d) red-eyed females and brown-eyed males (e) brown-eyed females and red-eyed malesarrow_forwardFruit flies are very useful model organisms that have been used to study genetics. One mutant recessive trait in fruit flies is called "eyeless" because it causes flies to have no eyes. Cross an eyeless fly with a homozygous normal fly. a. Draw the Punnett square. b. What is the genotyoe ratio of the offspring? c. What is the phenotype ratio of the offspring? d. What genetic problem is this? (monohybrid, dihybrid or multiple allele)arrow_forwarda. aabbccDd b. AabbCcDd c. AAbbCCddarrow_forward
- For this problem, use the information given in problem 15. A young woman with blood type O gave birth to a baby with blood type O. In a court case, she claims that a certain young man is the father of her child. The man has type A blood. Could he be the father? Can it be proven on this evidence alone that he is the father? ^Need answers to that one, including genotype, phenotype gametes and punnett square. This is question 15 as a little background dont need this solved . In humans, there are three alleles for blood type: A, B, and O. The allele for blood type A and the allele for blood type B show incomplete dominance. A person with both alleles has blood type AB. Both A and B dominate type O. A person with alleles for blood types A and O marries someone with alleles for blood types B and O. List the types of blood their offspring could have and the probability for each blood type in the offspringarrow_forward. A sex-linked recessive allele c produces a red–green color blindness in humans. A normal woman whose father was color blind marries a color-blind mana. What genotypes are possible for the mother of the color-blind man? b. What are the chances that the first child from this marriage will be a color-blind boy? c. Of the girls produced by these parents, what proportion can be expected to be color blind? d. Of all the children (sex unspecified) of these parents, what proportion can be expected to have normal color vision?arrow_forwarda. Which progeny are the parental types? How can you tell?b. Which progeny are the recombinants? How can you tell?c. Do the results of this test cross support linkage of the traits? What is the % recombination?arrow_forward
- or each of the following genotypes how many gametes would be made? a. AaBb - b. AaBbCC - c. AABbCcdd - d. AabbCcDd -arrow_forwardDuchenne muscular dystrophy is sex linked and usually affects only males. Victims of the disease become progressively weaker, starting early in life.a. What is the probability that a woman whose brother has Duchenne’s disease will have an affected child?b. If your mother’s brother (your uncle) had Duchenne’s disease, what is the probability that you have received the allele?c. If your father’s brother had the disease, what is the probability that you have received the allele?arrow_forward3) A. How are the following proteins involved in cell division: condensing, cohesin, kinetochore complex, tubulin? B. Why does phenotype not always reveal genotype? C. How can Mendel's postulates of segregation and independent assortment be explained by meiosis? D. Explain the genotypic and phenotypic ratios predicted when performing a monohybrid and a dihybrid cross of heterozygotes? E. How can you use the product rule and sum rule to calculate the probability of a particular genotype resulting from crossing parents of specific genotypes?arrow_forward
- 3) How many possible gametes could a person with the following genotypes produce? a. AaBbCc b. AABbCc c. AabbCCarrow_forwardIn letter B: If the map distance equals the number of recombinant/total of offspring, wouldn't it be 24/806 x 100? Wouldn't we add both recombinants? Can you explain letter C? I don't grasp that concept well. And since I'm using my question already, would you be able to answer D. Thank you!arrow_forwardGenes G and H are located on chromosome 18. A woman with the genotype Gg Hh has a child with a man with the genotype GG HH. Unfortunately, the child has the genotype Ggg hhh and only survives for 6 months. When and in which parent did nondisjunction occur? Group of answer choices a. Meiosis II in the mother b. Meiosis I in the mother c. Meiosis I in the father d. Meiosis II in the fatherarrow_forward
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