Genetic Analysis: An Integrated Approach (2nd Edition)
2nd Edition
ISBN: 9780321948908
Author: Mark F. Sanders, John L. Bowman
Publisher: PEARSON
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Chapter 19, Problem 23P
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Jonah and Jana are siblings. Jonah has the genetic disorder cystic fibrosis, caused by inheriting one copy from each parent of a mutation in the CF gene. Jana does not have cystic fibrosis. Which of the following statements is/are true? (Select all that are true)
a)Jana does not have the gene that when mutant causes cystic fibrosis.
b)Jana has the gene that when mutant causes cystic fibrosis.
c)Jana has two copies of the allele that causes cystic fibrosis.
d)Jana does not have two copies of the allele that causes cystic fibrosis.
Anyone know how to do this
A recently married couple are both heterozygous for cystic fibrosis, a recessive genetic disorder. They would like to start a family and would like to have two children.
a.) What is the probability that their second pregnancy would result in a child with cystic fibrosis?
b.) What is the probability that their second pregnancy would result in a child with cystic fibrosis?
Chapter 19 Solutions
Genetic Analysis: An Integrated Approach (2nd Edition)
Ch. 19 - 17.1 Reciprocal crosses of experimental animals or...Ch. 19 - 17.2 How are some of the characteristics of the...Ch. 19 - 17.3 The human mitochondrial genome encodes...Ch. 19 - What is the evidence that transfer of DNA from the...Ch. 19 - Draw a graph depicting the relative amounts of...Ch. 19 - Prob. 6PCh. 19 - 17.7 What is the evidence that the ancient...Ch. 19 - 17.8 Outline the steps required for a gene...Ch. 19 - 17.9 Consider the phylogenetic tree presented in...Ch. 19 - Most large protein complexes in mitochondria and...
Ch. 19 - What insights have analyses of human mitochondrial...Ch. 19 - You are a genetic counselor, and several members...Ch. 19 - A mutation in Arabidopsis immutans results in the...Ch. 19 - What type or types of inheritance are consistent...Ch. 19 - You have isolated (1) a streptomycin-resistant...Ch. 19 - You have isolated two petite mutants, pet1 and...Ch. 19 - 17.15 Consider this human pedigree for a vision...Ch. 19 - A 50- year - old man has been diagnosed with MELAS...Ch. 19 - 17.17 The first person in a family to exhibit...Ch. 19 - Prob. 20PCh. 19 - Prob. 21PCh. 19 - 17.19 What is the most likely mode of inheritance...Ch. 19 - 17.20 In , the Russian Tsar Nicholaswas deposed,...Ch. 19 - 17.21 The dodo bird (Raphus cucullatus) lived on...Ch. 19 - Cytoplasmic male sterility (CMS) in plants has...Ch. 19 - 17.23 Wolves and coyotes can interbreed in...Ch. 19 - Prob. 27PCh. 19 - Prob. 28P
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- If a Mother's genotype is IAi and her Daughter's genotype is ii and the mother claims a man who is type B as the father... a) Is that possible? Explain. b) The accused man can prove that both of his parents are type AB. Is it possible for him to be type B? If so, what is his genotype? Explain. d) Does the answer in part c change the answer in part b? Explain.arrow_forwardHow is it possible Jonathan has the dominant disorder, Huntington’s Disease, if none of his family had it? a) The mutant allele remained ‘hidden’ in previous generations. b) He is homozygous for mutant huntingtin alleles unlike his grandparents, who are clearly heterozygous for the condition. c) The appearance of Huntington Disease in him might be the result of a new mutation appearing during his lifetime. d) His parents and grandparents were ashamed to admit they had it.arrow_forwardIdentify the sex and any genetic conditions by analyzing the karyotype of this individual. 1.a) male b) female 2. a) normal b) triploid c) patau d) edwards syndrome e) down syndrome f) triplo-X g) turners syndrome h) klinefelter syndromearrow_forward
- In 1967, a couple accused a hospital of switching their baby with another. DNA interpretation did not exist at this time so the hospital traced the blood types of the family in order to determine if a mistake was made. The mother had Type A blood, the father had Type AB blood, and the baby had Type O blood. Use the Punnett square to defend your answer to the following question: Did the hospital make a mistake and switch the baby? ____________arrow_forwardDescendants of Queen Victoria (1819-1901) of England is believed to have suffered from hemophilia B, otherwise known as Christmas disease. Suppose that her affected son married her carrier daughter, what would be the chances of having a normal child? (A) 0% (B) 25% (C) 50% (D) 75%arrow_forwardA man and a woman have a child with cystic fibrosis. Neither parent has cystic fibrosis. How could this happen? a) Both parents carry the cystic fibrosis allele, and each passed that allele to their child. b) The child had a spontaneous mutation on both copies of their CFTR alleles, leading to cystic fibrosis. c) One parent gave the child two copies of the cystic fibrosis CFTR allele. c) One parent gave the child a wild type CFTR allele, and the other parent gave them a cystic fibrosis CFTR gene.arrow_forward
- 2) You're the director of Foothill Presbyterian Hospital's maternity ward, and you have four mixed-up babies, with blood types of O, A, B, and AB. The four sets of desperate parents are threatening to sue you if you don't get their babies back. You know the blood types (phenotypes) of the parents are: i) AB and O ii) A and O iii) A and AB iv) O and O You also know that each set of parents has only one child (no sets of twins, that is). Match each baby with its parents.arrow_forwardCystic Fibrosis (CF) is an autosomal recessive condition. Therefore, heterozygous (Cc) carriers do not display symptoms. Two parents who are carriers plan to start a family and you are a genetic counselor helping to advise them about their chances of having children affected by CF. a) Suppose the couple has 4 children, each one year apart. What is the probability that all 4 children will inherit CF? b) What is the probability that any 3 of their 4 children will not inherit CF, but 1 will be affected? c) What is the probability that their first child will not inherit CF, but the younger 3 children will inherit CF?arrow_forwardPKU is an inherited disease caused by a recessive allele. If a woman and her husband, who are both carriers (heterozygotes) for the disorder, have three children, what is the probability of each of the following? a) All three children are of normal phenotype. b) All three children have the disease. c) Any 2 of the three children have the normal phenotype.arrow_forward
- Shown below is a pedigree for Phenylketonuria (PKU), an autosomal recessive metabolic disorder. The characteristic feature of PKU is severe mental retardation A) What is the probability that individual II-1 is heterozygous for this gene? B) What is the probability that individual III-4 is heterozygous for this gene? C) If individuals III-3 and III-4 were to marry, what is the probability that their child would express PKU?arrow_forwardPart 1 The Symptoms Imagine that you work at the medical examiner's office for a major metropolitan city. As Chief Medical Officer, you investigate suspicious deaths and provide toxicology services for the county. Unfortunately, it's been a busy week. In the past five days, seven people have died, all with similar symptoms. It is your job to examine the data and determine the cause of death for these victims. The first was a 12-year-old girl. Her parents said that she was awake in the middle of the night complaining of a stuffy nose and sore throat. They gave her an extra strength Tylenol and sent her back to bed. At 7am the next morning, the parents discovered that the girl had collapsed on the bathroom floor. An ambulance rushed the girl to a nearby hospital, where she was pronounced dead. That same day, paramedics found the second victim unconscious on his kitchen floor after what they thought was an apparent heart attack. Sadly, the victim's brother and fiancée also collapsed later…arrow_forwardNumber 10arrow_forward
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Mitochondrial mutations; Author: Useful Genetics;https://www.youtube.com/watch?v=GvgXe-3RJeU;License: CC-BY