The reason as to why selective methylation occurs at only one OH in morphine to give codeine is to be stated. Concept introduction: Codeine is formed from morphine by selective methylation. In selective methylation reaction, the methyl group is attached at the specific position. A base aids in the abstraction of hydrogen ion from morphine, which results in the formation of phenoxide ion.

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Chapter 19, Problem 19.41P

Interpretation Introduction

Interpretation: The reason as to why selective methylation occurs at only one OH in morphine to give codeine is to be stated.

Concept introduction: Codeine is formed from morphine by selective methylation. In selective methylation reaction, the methyl group is attached at the specific position. A base aids in the abstraction of hydrogen ion from morphine, which results in the formation of phenoxide ion.

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Answer 2

Question

Chapter 19, Problem 19.41P

Interpretation Introduction

Interpretation: The reason as to why selective methylation occurs at only one OH in morphine to give codeine is to be stated.

Concept introduction: Codeine is formed from morphine by selective methylation. In selective methylation reaction, the methyl group is attached at the specific position. A base aids in the abstraction of hydrogen ion from morphine, which results in the formation of phenoxide ion.

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Answer 3

Question

Chapter 19, Problem 19.41P

Interpretation Introduction

Interpretation: The reason as to why selective methylation occurs at only one OH in morphine to give codeine is to be stated.

Concept introduction: Codeine is formed from morphine by selective methylation. In selective methylation reaction, the methyl group is attached at the specific position. A base aids in the abstraction of hydrogen ion from morphine, which results in the formation of phenoxide ion.

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Answer 4

Question

Chapter 19, Problem 19.41P

Interpretation Introduction

Interpretation: The reason as to why selective methylation occurs at only one OH in morphine to give codeine is to be stated.

Concept introduction: Codeine is formed from morphine by selective methylation. In selective methylation reaction, the methyl group is attached at the specific position. A base aids in the abstraction of hydrogen ion from morphine, which results in the formation of phenoxide ion.

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Answer 5

Chapter 19, Problem 19.41P

Interpretation Introduction

Interpretation: The reason as to why selective methylation occurs at only one OH in morphine to give codeine is to be stated.

Concept introduction: Codeine is formed from morphine by selective methylation. In selective methylation reaction, the methyl group is attached at the specific position. A base aids in the abstraction of hydrogen ion from morphine, which results in the formation of phenoxide ion.

Answer 6

Chapter 19, Problem 19.41P

Interpretation Introduction

Interpretation: The reason as to why selective methylation occurs at only one OH in morphine to give codeine is to be stated.

Concept introduction: Codeine is formed from morphine by selective methylation. In selective methylation reaction, the methyl group is attached at the specific position. A base aids in the abstraction of hydrogen ion from morphine, which results in the formation of phenoxide ion.

Answer 7

Chapter 19, Problem 19.41P

Interpretation Introduction

Interpretation: The reason as to why selective methylation occurs at only one OH in morphine to give codeine is to be stated.

Concept introduction: Codeine is formed from morphine by selective methylation. In selective methylation reaction, the methyl group is attached at the specific position. A base aids in the abstraction of hydrogen ion from morphine, which results in the formation of phenoxide ion.

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Ch. 19 - Give the IUPAC name for each compound.Ch. 19 - Problem 19.2 Give the structure corresponding to...Ch. 19 - Problem 19.3 Draw the structure corresponding to...Ch. 19 - Prob. 19.4P Ch. 19 - Prob. 19.5P Ch. 19 - Rank the following compounds in order of...Ch. 19 - Explain how you could use IR spectroscopy to...Ch. 19 - Identify the structure of a compound of molecular...Ch. 19 - Problem 19.9 How many tetrahedral stereogenic...Ch. 19 - What alcohol can be oxidized to each carboxylic...

Solution Summary: The author explains that selective methylation occurs at only one OH in morphine to give codeine.

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