Organic Chemistry, Ebook And Single-course Homework Access
Organic Chemistry, Ebook And Single-course Homework Access
6th Edition
ISBN: 9781319085841
Author: LOUDON
Publisher: MAC HIGHER
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Chapter 19, Problem 19.34P
Interpretation Introduction

Interpretation:

The structures of all aldehydes or ketones that result in the formation of 1-isobutyl-4-methylbenzene after application of either the Wolff-Kishner or Clemmensen reduction are to be stated.

Concept introduction:

The organic reaction which is used for the preparation of an alkane from an aldehyde or ketone using reagent H2NNH2 in the presence of base (OH) is called Wolff-Kishner reduction reaction. The major product of the reaction is present in maximum yield as compared to the other.

The organic reaction used for the conversion of an aldehyde or ketone to an alkane using reagent Zn(Hg) in the presence of HCl in concentrated form is called Clemmensen reduction reaction.

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Using the general properties of equilibrium constants At a certain temperature, the equilibrium constant K for the following reaction is 0.84: H2(g) + 2(g) 2 HI(g) = Use this information to complete the following table. Suppose a 34. L reaction vessel is filled with 0.79 mol of HI. What can you say about the composition of the mixture in the vessel at equilibrium? There will be very little H2 and 12. ☐ x10 There will be very little HI. Neither of the above is true. What is the equilibrium constant for the following reaction? Be sure your answer has the correct number of significant digits. 2 HI(g) H₂(9)+12(9) K = What is the equilibrium constant for the following reaction? Be sure your answer has the correct number of significant digits. 2 H2(g)+212(9) 4 HI(g) K = ☐ ☑
Predicting the qualitative acid-base properties of salts Consider the following data on some weak acids and weak bases: base acid Κα Kb name formula name formula hydrocyanic acid - 10 HCN 4.9 × 10 pyridine C₂H₂N 1.7 × 10 9 acetic acid HCH3CO2 1.8 × 10 5 hydroxylamine HONH2 1.1 × 10¯ 8 Use this data to rank the following solutions in order of increasing pH. In other words, select a '1' next to the solution that will have the lowest pH, a '2' next to the solution that will have the next lowest pH, and so on. 0.1 M KCN solution pH choose one ✓ 0.1 M C5H5NHCI choose one ✓ 0.1 M NaCH3CO2 choose one ✓ 0.1 M HONH3Br ✓ choose one 1 (lowest) 2 3 4 (highest)
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Chapter 19 Solutions

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