(a) Interpretation: The explanation for the fact that the m / z = 57 fragment peak is much more intense in the spectrum of 3, 3-dimethyl-2-butanone than it is in the spectrum of 2-hexanone is to be stated. Concept introduction: Spectroscopy method is used to identify the structure of the substance. The mass spectroscopy is used to determine the molecular mass of a compound. In the mass spectrum, the molecular ion peak is the most important peak. The ratio m / z of the molecular ion occurs at the molecular mass.

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Answer 1

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Chapter 19, Problem 19.10P

Interpretation Introduction

(a)

Interpretation:

The explanation for the fact that the m/z=57 fragment peak is much more intense in the spectrum of 3, 3-dimethyl-2-butanone than it is in the spectrum of 2-hexanone is to be stated.

Concept introduction:

Spectroscopy method is used to identify the structure of the substance. The mass spectroscopy is used to determine the molecular mass of a compound. In the mass spectrum, the molecular ion peak is the most important peak. The ratio m/z of the molecular ion occurs at the molecular mass.

Interpretation Introduction

(b)

Interpretation:

The explanation for the fact that the spectrum of 3, 3-dimethyl-2-butanone (B) does not shows a fragment at m/z=58, but that of 2-hexanone shows is to be stated.

Concept introduction:

Spectroscopy method is used to identify the structure of the substance. The mass spectroscopy is used to determine the molecular mass of a compound. In the mass spectrum, the molecular ion peak is the most important peak. The ratio m/z of the molecular ion occurs at the molecular mass.

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Question 19 0/2 pts 3 Details You have a mixture of sodium chloride (NaCl) and potassium chloride (KCl) dissolved in water and want to separate out the Cl- ions by precipitating them out using silver ions (Ag+). The chemical equation for the net ionic reaction of NaCl and KCl with silver nitrate, AgNO3, is shown below. Ag+(aq) + Cl(aq) → AgCl(s) The total mass of the NaCl/KCl mixture is 1.299 g. Adding 50.42 mL of 0.381 M solution precipitates out all of the Cl-. What are the masses of NaCl and KCl in the mixture? Atomic masses: g: Mass of NaCl g: Mass of KCL Ag = 107.868 g mol- 1 Cl = 35.453 g mol- 1 K = 39.098 g mol- N = 14.007 g mol−1 Na = 22.99 g mol−1 0 = 15.999 g mol 1 Question Help: ✓ Message instructor Submit Question

Part 1. Draw monomer units of the following products and draw their reaction mechanism (with arrow pushing) Polyester fiber Using a) pthalic anhydride + anhydrous sodium acetate + ethylene glycol B)pthalic anhydride + anhydrous sodium acetate + glycerol

Identify the missing starting materials/ reagents/ products in the following reactions. Show the stereochemistry clearly in the structures, if any. If there is a major product, draw the structures of the major product with stereochemistry clearly indicated where applicable. Show only the diastereomers (you do not have to draw the pairs of enantiomers). If you believe that multiple products are formed in approximately equal amounts (hence neither is the major product), draw the structures of the products, and show the detailed mechanism of these reactions to justify the formation of the multiple products. If you believe no product is formed, explain why briefly. (6 mark for each, except f and g, which are 10 mark each)

Answer 2

Question

Chapter 19, Problem 19.10P

Interpretation Introduction

(a)

Interpretation:

The explanation for the fact that the m/z=57 fragment peak is much more intense in the spectrum of 3, 3-dimethyl-2-butanone than it is in the spectrum of 2-hexanone is to be stated.

Concept introduction:

Spectroscopy method is used to identify the structure of the substance. The mass spectroscopy is used to determine the molecular mass of a compound. In the mass spectrum, the molecular ion peak is the most important peak. The ratio m/z of the molecular ion occurs at the molecular mass.

Interpretation Introduction

(b)

Interpretation:

The explanation for the fact that the spectrum of 3, 3-dimethyl-2-butanone (B) does not shows a fragment at m/z=58, but that of 2-hexanone shows is to be stated.

Concept introduction:

Spectroscopy method is used to identify the structure of the substance. The mass spectroscopy is used to determine the molecular mass of a compound. In the mass spectrum, the molecular ion peak is the most important peak. The ratio m/z of the molecular ion occurs at the molecular mass.

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Answer 3

Question

Chapter 19, Problem 19.10P

Interpretation Introduction

(a)

Interpretation:

The explanation for the fact that the m/z=57 fragment peak is much more intense in the spectrum of 3, 3-dimethyl-2-butanone than it is in the spectrum of 2-hexanone is to be stated.

Concept introduction:

Spectroscopy method is used to identify the structure of the substance. The mass spectroscopy is used to determine the molecular mass of a compound. In the mass spectrum, the molecular ion peak is the most important peak. The ratio m/z of the molecular ion occurs at the molecular mass.

Interpretation Introduction

(b)

Interpretation:

The explanation for the fact that the spectrum of 3, 3-dimethyl-2-butanone (B) does not shows a fragment at m/z=58, but that of 2-hexanone shows is to be stated.

Concept introduction:

Spectroscopy method is used to identify the structure of the substance. The mass spectroscopy is used to determine the molecular mass of a compound. In the mass spectrum, the molecular ion peak is the most important peak. The ratio m/z of the molecular ion occurs at the molecular mass.

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Answer 4

Question

Chapter 19, Problem 19.10P

Interpretation Introduction

(a)

Interpretation:

The explanation for the fact that the m/z=57 fragment peak is much more intense in the spectrum of 3, 3-dimethyl-2-butanone than it is in the spectrum of 2-hexanone is to be stated.

Concept introduction:

Spectroscopy method is used to identify the structure of the substance. The mass spectroscopy is used to determine the molecular mass of a compound. In the mass spectrum, the molecular ion peak is the most important peak. The ratio m/z of the molecular ion occurs at the molecular mass.

Interpretation Introduction

(b)

Interpretation:

The explanation for the fact that the spectrum of 3, 3-dimethyl-2-butanone (B) does not shows a fragment at m/z=58, but that of 2-hexanone shows is to be stated.

Concept introduction:

Spectroscopy method is used to identify the structure of the substance. The mass spectroscopy is used to determine the molecular mass of a compound. In the mass spectrum, the molecular ion peak is the most important peak. The ratio m/z of the molecular ion occurs at the molecular mass.

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Answer 5

Chapter 19, Problem 19.10P

Interpretation Introduction

(a)

Interpretation:

The explanation for the fact that the m/z=57 fragment peak is much more intense in the spectrum of 3, 3-dimethyl-2-butanone than it is in the spectrum of 2-hexanone is to be stated.

Concept introduction:

Spectroscopy method is used to identify the structure of the substance. The mass spectroscopy is used to determine the molecular mass of a compound. In the mass spectrum, the molecular ion peak is the most important peak. The ratio m/z of the molecular ion occurs at the molecular mass.

Interpretation Introduction

(b)

Interpretation:

The explanation for the fact that the spectrum of 3, 3-dimethyl-2-butanone (B) does not shows a fragment at m/z=58, but that of 2-hexanone shows is to be stated.

Concept introduction:

Spectroscopy method is used to identify the structure of the substance. The mass spectroscopy is used to determine the molecular mass of a compound. In the mass spectrum, the molecular ion peak is the most important peak. The ratio m/z of the molecular ion occurs at the molecular mass.

Answer 6

Chapter 19, Problem 19.10P

Interpretation Introduction

(a)

Interpretation:

The explanation for the fact that the m/z=57 fragment peak is much more intense in the spectrum of 3, 3-dimethyl-2-butanone than it is in the spectrum of 2-hexanone is to be stated.

Concept introduction:

Spectroscopy method is used to identify the structure of the substance. The mass spectroscopy is used to determine the molecular mass of a compound. In the mass spectrum, the molecular ion peak is the most important peak. The ratio m/z of the molecular ion occurs at the molecular mass.

Answer 7

Chapter 19, Problem 19.10P

Interpretation Introduction

(a)

Interpretation:

The explanation for the fact that the m/z=57 fragment peak is much more intense in the spectrum of 3, 3-dimethyl-2-butanone than it is in the spectrum of 2-hexanone is to be stated.

Concept introduction:

Spectroscopy method is used to identify the structure of the substance. The mass spectroscopy is used to determine the molecular mass of a compound. In the mass spectrum, the molecular ion peak is the most important peak. The ratio m/z of the molecular ion occurs at the molecular mass.

Answer 8

Interpretation Introduction

(b)

Interpretation:

The explanation for the fact that the spectrum of 3, 3-dimethyl-2-butanone (B) does not shows a fragment at m/z=58, but that of 2-hexanone shows is to be stated.

Concept introduction:

Spectroscopy method is used to identify the structure of the substance. The mass spectroscopy is used to determine the molecular mass of a compound. In the mass spectrum, the molecular ion peak is the most important peak. The ratio m/z of the molecular ion occurs at the molecular mass.

Answer 9

Interpretation Introduction

(b)

Interpretation:

The explanation for the fact that the spectrum of 3, 3-dimethyl-2-butanone (B) does not shows a fragment at m/z=58, but that of 2-hexanone shows is to be stated.

Concept introduction:

Spectroscopy method is used to identify the structure of the substance. The mass spectroscopy is used to determine the molecular mass of a compound. In the mass spectrum, the molecular ion peak is the most important peak. The ratio m/z of the molecular ion occurs at the molecular mass.

Answer 10

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Answer 11

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Answer 12

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Answer 13

Ch. 19 - Prob. 19.1P Ch. 19 - Prob. 19.2P Ch. 19 - Prob. 19.3P Ch. 19 - Prob. 19.4P Ch. 19 - Prob. 19.5P Ch. 19 - Prob. 19.6P Ch. 19 - Prob. 19.7P Ch. 19 - Prob. 19.8P Ch. 19 - Prob. 19.9P Ch. 19 - Prob. 19.10P

Solution Summary: The author explains that the m/z=57 fragment peak is much more intense in the spectrum of 3, 3-dimethyl-2-butanone than it is in

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