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Concept explainers
(a)
The position of the image from the lens.
To identify: Whether the image is real or virtual.
(a)
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Answer to Problem 30SSC
The position of the image from the lens is
The image is a real image.
Explanation of Solution
Given:
The height of the salt shaker is
The position of the salt shaker is
The focal length is
Formula used:
The expression for the mirror equation is,
Here,
Calculation:
The position of the image is,
Hence, the image is a real image.
Conclusion:
Thus, the position of the image from the lens is
Thus, the image is a real image.
(b)
The magnification.
To identify: Whether the image is smaller or larger than the object.
(b)
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Answer to Problem 30SSC
The magnification is
The image is an enlarged image.
Explanation of Solution
Given:
The height of the salt shaker is
The position of the salt shaker is
The focal length is
Formula used:
The expression for the magnification equation is,
Here,
Calculation:
From part (a), the position of the image from the lens is
The magnification is,
Hence, the image is an enlarged image.
Conclusion:
Thus, the magnification is
Thus, the image is an enlarged image.
(c)
The distance of the image from the lens and the magnification.
To identify: Whether the image is smaller or larger than the object.
(c)
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Answer to Problem 30SSC
The distance of the image from the lens is
The magnification is
Explanation of Solution
Given:
The height of the salt shaker is
The position of the salt shaker is
The focal length is
Formula used:
Show the expression for the mirror equation as follows:
Here,
Show the expression for the magnification equation as follows:
Here,
Calculation:
The position of the image is,
Hence, the image is the virtual image.
The magnification is,
Thus, the image is an enlarged image.
Conclusion:
Thus, the position of the image from the lens is
Thus, the magnification is
Thus, the image is an enlarged image.
Chapter 18 Solutions
Glencoe Physics: Principles and Problems, Student Edition
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